HDU6308-2018ACM暑假多校联合训练1011-Time Zone

题目大意就是给你UTC-8时区的时间 让你求对应时区的时间

哇 这个题 看似简单，但是一开始怎么都过不了啊

同学用自己写的read过了，后来看了一下各位大佬说改成分钟随便过，就随便过了

Problem Description

Chiaki often participates in international competitive programming contests. The time zone becomes a big problem.
Given a time in Beijing time (UTC +8), Chiaki would like to know the time in another time zone s.

 

Input

There are multiple test cases. The first line of input contains an integer T (1≤T≤106), indicating the number of test cases. For each test case:
The first line contains two integers a, b (0≤a≤23,0≤b≤59) and a string s in the format of "UTC+X'', "UTC-X'', "UTC+X.Y'', or "UTC-X.Y'' (0≤X,X.Y≤14,0≤Y≤9).

 

Output

For each test, output the time in the format of hh:mm (24-hour clock).

 

Sample Input

3
11 11 UTC+8
11 12 UTC+9
11 23 UTC+0

 

Sample Output

11:11 12:12 03:23

#include <cstdio>
#include <iostream>
 
using namespace std;
 
int main()
{
    int t;
    scanf("%d", &t);
 
    while (t--)
    {
        int p, q;
        float f=0.0;
        char s[];
        char s1[];
        scanf("%d %d %s", &p, &q, s);
        sscanf(s + ,"%f",&f);
        f += 0.01;
        if (s[] == '-')
            f = -f;
        int num = p *  + q -  * ;
        p = f * 60.0;
        num += p;
        if (num < )
            num += ;
        else if (num >= )
            num -= ;
 
        p = num / ;
        q = num - p * ;
        printf("%02d:%02d\n", p, q);
    }
 
    return ;
}