hdu 5146 Sequence
题目连接
http://acm.hdu.edu.cn/showproblem.php?pid=5146
Sequence
Description
Today we have a number sequence A includes n elements.
Nero thinks a number sequence A is good only if the sum of its elements with odd index equals to the sum of its elements with even index and this sequence is not a palindrome.
Palindrome means no matter we read the sequence from head to tail or from tail to head,we get the same sequence.
Two sequence A and B are consider different if the length of A is different from the length of B or there exists an index i that $A_{i}\neq B_{i}.$
Now,give you the sequence A,check out it’s good or not.
Input
The first line contains a single integer T,indicating the number of test cases.
Each test case begins with a line contains an integer n,the length of sequence A.
The next line follows n integers $A_{1},A_{2}, \ldots, A_{n}$
[Technical Specification]
1 <= T <= 100
1 <= n <= 1000
0 <= $A_{i}$ <= 1000000
Output
For each case output one line,if the sequence is good ,output "Yes",otherwise output "No".
Sample Input
3
7
1 2 3 4 5 6 7
7
1 2 3 5 4 7 6
6
1 2 3 3 2 1
Sample Output
No
Yes
No
手速题。。。
- #include<algorithm>
- #include<iostream>
- #include<cstdlib>
- #include<cstring>
- #include<cstdio>
- #include<vector>
- #include<map>
- #include<set>
- using std::cin;
- using std::cout;
- using std::endl;
- using std::find;
- using std::sort;
- using std::set;
- using std::map;
- using std::pair;
- using std::vector;
- using std::multiset;
- using std::multimap;
- #define pb(e) push_back(e)
- #define sz(c) (int)(c).size()
- #define mp(a, b) make_pair(a, b)
- #define all(c) (c).begin(), (c).end()
- #define iter(c) decltype((c).begin())
- #define cls(arr,val) memset(arr,val,sizeof(arr))
- #define cpresent(c, e) (find(all(c), (e)) != (c).end())
- #define rep(i, n) for (int i = 1; i <= (int)(n); i++)
- #define tr(c, i) for (iter(c) i = (c).begin(); i != (c).end(); ++i)
- const int Max_N = ;
- typedef unsigned long long ull;
- int arr[Max_N];
- int main() {
- #ifdef LOCAL
- freopen("in.txt", "r", stdin);
- freopen("out.txt", "w+", stdout);
- #endif
- int t, n;
- ull sum1, sum2;
- scanf("%d", &t);
- while (t--) {
- bool f = false;
- sum1 = sum2 = ;
- scanf("%d", &n);
- rep(i, n) {
- scanf("%d", &arr[i]);
- if (i & ) sum1 += arr[i];
- else sum2 += arr[i];
- }
- if (sum1 != sum2) { puts("No"); continue; }
- for (int i = , j = n; i < j; i++, j--) {
- if (arr[i] != arr[j]) { f = true; break; }
- }
- puts(f ? "Yes" : "No");
- }
- return ;
- }
hdu 5146 Sequence的更多相关文章
- HDU 3397 Sequence operation(线段树)
HDU 3397 Sequence operation 题目链接 题意:给定一个01序列,有5种操作 0 a b [a.b]区间置为0 1 a b [a,b]区间置为1 2 a b [a,b]区间0变 ...
- HDU 5919 Sequence II(主席树+逆序思想)
Sequence II Time Limit: 9000/4500 MS (Java/Others) Memory Limit: 131072/131072 K (Java/Others) To ...
- HDU 6395 Sequence 【矩阵快速幂 && 暴力】
任意门:http://acm.hdu.edu.cn/showproblem.php?pid=6395 Sequence Time Limit: 4000/2000 MS (Java/Others) ...
- hdu 5312 Sequence(数学推导——三角形数)
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=5312 Sequence Time Limit: 2000/2000 MS (Java/Others) ...
- hdu 1711Number Sequence (KMP入门,子串第一次出现的位置)
Number Sequence Time Limit: 10000/5000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) ...
- hdu 3397 Sequence operation(线段树:区间更新)
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=3397 题意:给你一个长度为n的0,1序列,支持下列五种操作, 操作0(0 a b):将a到b这个区间的 ...
- HDU 1141---Brackets Sequence(区间DP)
题目链接 http://poj.org/problem?id=1141 Description Let us define a regular brackets sequence in the fol ...
- hdu 1711Number Sequence
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1711 数字KMP,原来还能这么用 #include<stdio.h> ],b[]; ]; ...
- HDU 5918 Sequence I KMP
Sequence I Problem Description Mr. Frog has two sequences a1,a2,⋯,an and b1,b2,⋯,bm and a number p ...
随机推荐
- 怎样去掉FireFox的导入向导
用robotframework的时候,用ride去打开firefox,但是每次都会出现导入向导,影响了后续的操作,怎样才能去掉呢? 网上查到的解决方案是:到firefox的profiles.ini所在 ...
- WebView 获取网页点击事件
网页上的点击按钮 本身绑定了URL,点击的时候webview 会在下面的这个方法中加载URL - (BOOL)webView:(UIWebView*)webView shouldStartLoadWi ...
- mybatis-generator 代码自动生成工具
今天来介绍下怎么用mybatis-gennerator插件自动生成mybatis所需要的dao.bean.mapper xml文件,这样我们可以节省一部分精力,把精力放在业务逻辑上. 之前看过很多文章 ...
- TCP/IP详解学习笔记(10)-- DNS:域名系统
1.DNS DNS 是计算机域名系统(Domain Name System 或Domain Name Service) 的缩写,它是由解析器以及域名服务器组成的.域名服务器是指保存有该网络中 ...
- java基础回顾(五)——Stack、Heap
栈(stack):是简单的数据结构,但在计算机中使用广泛.栈最显著的特征是:LIFO(Last In, First Out,后进先出).比如我们往箱子里面放衣服,先放入的在最下方,只有拿出后来放入的才 ...
- ASP.NET的SEO:使用.ashx文件——排除重复内容
本系列目录 不同的链接指向的页面如果具有大量相同的内容,这种现象就会被称为"重复内容",如果一个网站的重复内容很多,搜索引擎就会认为这个网站的价值不高.所以我们应尽量避免各种重复内 ...
- SID与GUID的区别
1.在AD里面创建一个用户或者组都会为其分配一个SID,同时也会为这些对象分配一个GUID,GUID是一个128位的字符串,一个标识符,GUID不仅在整个域里面是唯一的,并且在全世界的范围内都是唯一的 ...
- 【好文要转】Python:模拟登录以获取新浪微博OAuth的code参数值
[转自]http://www.tuicool.com/articles/zAz6zi [原文]http://blog.segmentfault.com/hongfei/1190000000343851 ...
- JavaScript编程规范
最近看NodeJS中,有一部分写JS约定俗成的编程规范(附录B,详情参考附件),感觉在实际工作中能用到, 大致意思分享给大家,详情参考附件: 1.缩进:建议两空格 作为Node.js代码的缩进标记: ...
- c++ 创建 socket server
下面一段代码是创建socket server的代码片段: 需要引用的库包括: #include <sys/types.h> #include <sys/socket.h> #i ...