B - Bit++
Problem description
The classic programming language of Bitland is Bit++. This language is so peculiar and complicated.
The language is that peculiar as it has exactly one variable, called x. Also, there are two operations:
- Operation ++ increases the value of variable x by 1.
- Operation -- decreases the value of variable x by 1.
A statement in language Bit++ is a sequence, consisting of exactly one operation and one variable x. The statement is written without spaces, that is, it can only contain characters "+", "-", "X". Executing a statement means applying the operation it contains.
A programme in Bit++ is a sequence of statements, each of them needs to be executed. Executing a programme means executing all the statements it contains.
You're given a programme in language Bit++. The initial value of x is 0. Execute the programme and find its final value (the value of the variable when this programme is executed).
Input
The first line contains a single integer n (1 ≤ n ≤ 150) — the number of statements in the programme.
Next n lines contain a statement each. Each statement contains exactly one operation (++ or --) and exactly one variable x (denoted as letter «X»). Thus, there are no empty statements. The operation and the variable can be written in any order.
Output
Print a single integer — the final value of x.
Examples
Input
1
++X
Output
1
Input
2
X++
--X
Output
0
解题思路:给X初始值为0,通过n个操作,实现加1减1运算,水过!
AC代码:
#include <bits/stdc++.h>
using namespace std;
int main()
{
int n,x=;char q[];
cin>>n;
while(n--){
cin>>q;
if(q[]=='+'||q[]=='+')x++;
else x--;
}
cout<<x<<endl;
return ;
}
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