Spring源码 19 IOC getBean
参考源
https://www.bilibili.com/video/BV1tR4y1F75R?spm_id_from=333.337.search-card.all.click
https://www.bilibili.com/video/BV12Z4y197MU?spm_id_from=333.999.0.0
《Spring源码深度解析(第2版)》
版本
本文章基于 Spring 5.3.15
前面实现了
ClassPathXmlApplicationContext
的构造,接下来分析其调用的getBean
方法。
以getBean(UserDao.class)
为例。
1 AbstractApplicationContext
public <T> T getBean(Class<T> requiredType) throws BeansException {
// 断言 Bean 工厂活动
assertBeanFactoryActive();
// 获取 Bean 工厂
// 获取 Bean
return getBeanFactory().getBean(requiredType);
}
1-1 断言 Bean 工厂活动
assertBeanFactoryActive()
protected void assertBeanFactoryActive() {
if (!this.active.get()) {
if (this.closed.get()) {
// 获取显示名称
throw new IllegalStateException(getDisplayName() + " has been closed already");
}
else {
// 获取显示名称
throw new IllegalStateException(getDisplayName() + " has not been refreshed yet");
}
}
}
获取显示名称前面已经分析过了,这里不再分析。
1-1 获取 Bean 工厂
getBeanFactory()
2 AbstractRefreshableApplicationContext
public final ConfigurableListableBeanFactory getBeanFactory() {
DefaultListableBeanFactory beanFactory = this.beanFactory;
if (beanFactory == null) {
throw new IllegalStateException("BeanFactory not initialized or already closed - " + "call 'refresh' before accessing beans via the ApplicationContext");
}
return beanFactory;
}
if (beanFactory == null)
由于前面定义了beanFactory
,这里直接返回。
1 AbstractApplicationContext
1-1 获取 Bean
getBean(requiredType)
3 DefaultListableBeanFactory
public <T> T getBean(Class<T> requiredType) throws BeansException {
// 获取 Bean
return getBean(requiredType, (Object[]) null);
}
public <T> T getBean(Class<T> requiredType, @Nullable Object... args) throws BeansException {
Assert.notNull(requiredType, "Required type must not be null");
// 解析 Bean
Object resolved = resolveBean(ResolvableType.forRawClass(requiredType), args, false);
if (resolved == null) {
throw new NoSuchBeanDefinitionException(requiredType);
}
return (T) resolved;
}
3-1 解析 Bean
resolveBean(ResolvableType.forRawClass(requiredType), args, false)
private <T> T resolveBean(ResolvableType requiredType, @Nullable Object[] args, boolean nonUniqueAsNull) {
// 解析 Bean 命名
NamedBeanHolder<T> namedBean = resolveNamedBean(requiredType, args, nonUniqueAsNull);
if (namedBean != null) {
return namedBean.getBeanInstance();
}
// 获取父级 Bean 工厂
BeanFactory parent = getParentBeanFactory();
if (parent instanceof DefaultListableBeanFactory) {
// 解析 Bean,递归调用
return ((DefaultListableBeanFactory) parent).resolveBean(requiredType, args, nonUniqueAsNull);
}
else if (parent != null) {
ObjectProvider<T> parentProvider = parent.getBeanProvider(requiredType);
if (args != null) {
return parentProvider.getObject(args);
}
else {
return (nonUniqueAsNull ? parentProvider.getIfUnique() : parentProvider.getIfAvailable());
}
}
return null;
}
3-2 解析 Bean 命名
resolveNamedBean(requiredType, args, nonUniqueAsNull)
private <T> NamedBeanHolder<T> resolveNamedBean(ResolvableType requiredType, @Nullable Object[] args, boolean nonUniqueAsNull) throws BeansException {
Assert.notNull(requiredType, "Required type must not be null");
// 获取类型的 Bean 名称
String[] candidateNames = getBeanNamesForType(requiredType);
if (candidateNames.length > 1) {
List<String> autowireCandidates = new ArrayList<>(candidateNames.length);
for (String beanName : candidateNames) {
if (!containsBeanDefinition(beanName) || getBeanDefinition(beanName).isAutowireCandidate()) {
autowireCandidates.add(beanName);
}
}
if (!autowireCandidates.isEmpty()) {
candidateNames = StringUtils.toStringArray(autowireCandidates);
}
}
if (candidateNames.length == 1) {
// 解析 Bean 命名
return resolveNamedBean(candidateNames[0], requiredType, args);
} else if (candidateNames.length > 1) {
Map<String, Object> candidates = CollectionUtils.newLinkedHashMap(candidateNames.length);
for (String beanName : candidateNames) {
if (containsSingleton(beanName) && args == null) {
Object beanInstance = getBean(beanName);
candidates.put(beanName, (beanInstance instanceof NullBean ? null : beanInstance));
} else {
candidates.put(beanName, getType(beanName));
}
}
// 确定主要候选
String candidateName = determinePrimaryCandidate(candidates, requiredType.toClass());
if (candidateName == null) {
// 确定最高优先级候选
candidateName = determineHighestPriorityCandidate(candidates, requiredType.toClass());
}
if (candidateName != null) {
Object beanInstance = candidates.get(candidateName);
if (beanInstance == null) {
return null;
}
if (beanInstance instanceof Class) {
// 解析 Bean 命名
return resolveNamedBean(candidateName, requiredType, args);
}
return new NamedBeanHolder<>(candidateName, (T) beanInstance);
}
if (!nonUniqueAsNull) {
throw new NoUniqueBeanDefinitionException(requiredType, candidates.keySet());
}
}
return null;
}
3-3 确定主要候选
determinePrimaryCandidate(candidates, requiredType.toClass())
protected String determinePrimaryCandidate(Map<String, Object> candidates, Class<?> requiredType) {
String primaryBeanName = null;
for (Map.Entry<String, Object> entry : candidates.entrySet()) {
String candidateBeanName = entry.getKey();
Object beanInstance = entry.getValue();
if (isPrimary(candidateBeanName, beanInstance)) {
if (primaryBeanName != null) {
boolean candidateLocal = containsBeanDefinition(candidateBeanName);
boolean primaryLocal = containsBeanDefinition(primaryBeanName);
if (candidateLocal && primaryLocal) {
throw new NoUniqueBeanDefinitionException(requiredType, candidates.size(), "more than one 'primary' bean found among candidates: " + candidates.keySet());
} else if (candidateLocal) {
primaryBeanName = candidateBeanName;
}
} else {
primaryBeanName = candidateBeanName;
}
}
}
return primaryBeanName;
}
3-3 确定最高优先级候选
determineHighestPriorityCandidate(candidates, requiredType.toClass())
protected String determineHighestPriorityCandidate(Map<String, Object> candidates, Class<?> requiredType) {
String highestPriorityBeanName = null;
Integer highestPriority = null;
for (Map.Entry<String, Object> entry : candidates.entrySet()) {
String candidateBeanName = entry.getKey();
Object beanInstance = entry.getValue();
if (beanInstance != null) {
Integer candidatePriority = getPriority(beanInstance);
if (candidatePriority != null) {
if (highestPriorityBeanName != null) {
if (candidatePriority.equals(highestPriority)) {
throw new NoUniqueBeanDefinitionException(requiredType, candidates.size(), "Multiple beans found with the same priority ('" + highestPriority + "') among candidates: " + candidates.keySet());
} else if (candidatePriority < highestPriority) {
highestPriorityBeanName = candidateBeanName;
highestPriority = candidatePriority;
}
} else {
highestPriorityBeanName = candidateBeanName;
highestPriority = candidatePriority;
}
}
}
}
return highestPriorityBeanName;
}
Spring源码 19 IOC getBean的更多相关文章
- spring源码浅析——IOC
=========================================== 原文链接: spring源码浅析--IOC 转载请注明出处! ======================= ...
- spring源码分析---IOC(1)
我们都知道spring有2个最重要的概念,IOC(控制反转)和AOP(依赖注入).今天我就分享一下spring源码的IOC. IOC的定义:直观的来说,就是由spring来负责控制对象的生命周期和对象 ...
- Spring源码解析-ioc容器的设计
Spring源码解析-ioc容器的设计 1 IoC容器系列的设计:BeanFactory和ApplicatioContext 在Spring容器中,主要分为两个主要的容器系列,一个是实现BeanFac ...
- Spring源码 05 IOC 注解方式
参考源 https://www.bilibili.com/video/BV1tR4y1F75R?spm_id_from=333.337.search-card.all.click https://ww ...
- Spring源码 16 IOC refresh方法11
参考源 https://www.bilibili.com/video/BV1tR4y1F75R?spm_id_from=333.337.search-card.all.click https://ww ...
- Spring源码 17 IOC refresh方法12
参考源 https://www.bilibili.com/video/BV1tR4y1F75R?spm_id_from=333.337.search-card.all.click https://ww ...
- Spring源码 11 IOC refresh方法6
参考源 https://www.bilibili.com/video/BV1tR4y1F75R?spm_id_from=333.337.search-card.all.click https://ww ...
- Spring源码 07 IOC refresh方法2
参考源 https://www.bilibili.com/video/BV1tR4y1F75R?spm_id_from=333.337.search-card.all.click https://ww ...
- Spring源码 06 IOC refresh方法1
参考源 https://www.bilibili.com/video/BV1tR4y1F75R?spm_id_from=333.337.search-card.all.click https://ww ...
随机推荐
- Python数据分析--Numpy常用函数介绍(4)--Numpy中的线性关系和数据修剪压缩
摘要:总结股票均线计算原理--线性关系,也是以后大数据处理的基础之一,NumPy的 linalg 包是专门用于线性代数计算的.作一个假设,就是一个价格可以根据N个之前的价格利用线性模型计算得出. 前一 ...
- 关于我学git这档子事(5)
对于错误: fatal: refusing to merge unrelated histories 解决之道: git pull origin main --allow-unrelated-hist ...
- Tomcat启动失败:java.lang.NoSuchMethodError: org.apache.tomcat.util.res.StringManager.getManager(Ljava/lang/Class;)Lorg/apache/tomcat/util/res/StringManager
项目开发中发现服务器上Tomcat启动失败 开始定位 第一步:打开tomcat日志catalina.log: 2017-07-25 17:02:43,799 [Catalina-startStop-1 ...
- 计算机网络 - HTTP和HTTPS的区别
计算机网络 - HTTP和HTTPS的区别 http所有传输的内容都是明文,并且客户端和服务器端都无法验证对方的身份. https具有安全性的ssl加密传输协议,加密采用对称加密. https协议需要 ...
- midway的使用教程
一.写在前面 先说下本文的背景,这是一道笔者遇到的Node后端面试题,遂记录下,通过本文的阅读,你将对楼下知识点有所了解: midway项目的创建与使用 typescript在Node项目中的应用 如 ...
- 给王心凌打Call的,原来是神奇的智能湖仓
图文原创:谭婧(王凌老粉) "爷青回" "我们只是老了,并没有死." 谭老师作为老粉,热烈庆祝"甜心教主"王凌成为现象级翻红顶流. 只要地球 ...
- BetterScroll源码阅读顺便学习TypeScript
开头 TypeScript已经出来很多年了,现在用的人也越来越多,毋庸置疑,它会越来越流行,但是我还没有用过,因为首先是项目上不用,其次是我对强类型并不敏感,所以纯粹的光看文档看不了几分钟就心不在焉, ...
- 常用Linux命令整理
常见系统命令 export 查看或修改环境变量 # 例:临时修改命令提示符为字符串$ export PS1=$ # 例:临时修改命令提示符显示系统时间 时间使用\t 表示 export PS1=&qu ...
- elastic-job和spring cloud版本冲突2
***************************APPLICATION FAILED TO START*************************** Description: An at ...
- Solution -「SDOI2011」拦截导弹
Sol. 题目要求一个数对序列的二维最长下降子序列,我们称其为 Q.并求出每一个元素分别在可能的 Q 中出现了多少次. 直接 Dp,时间复杂度 \(O(n^2)\) 不行.考虑 CDQ 分治 ...