LOJ#6280. 数列分块入门 4

另外开一个数组维护每一个块内的总和。

给区间加值是，残余的块一个一个点更新，整个的块一次性更新

查询的时候也是，残余的块一个一个点加，整个的块一次性加

#include<map>
#include<set>
#include<ctime>
#include<cmath>
#include<stack>
#include<queue>
#include<string>
#include<vector>
#include<cstdio>
#include<cstdlib>
#include<cstring>
#include<iostream>
#include<algorithm>
#define first fi
#define second se
#define lowbit(x) (x & (-x))

typedef unsigned long long int ull;
typedef long long int ll;
const double pi = 4.0*atan(1.0);
const int inf = 0x3f3f3f3f;
const int maxn = ;
const int maxm = ;
const int mod = ;
using namespace std;

int n, m, tol, T;
int block;
ll a[maxn];
ll b[maxn];
ll add[maxn];
int belong[maxn];

void init() {
    memset(a, , sizeof a);
    memset(b, , sizeof b);
    memset(add, , sizeof add);
    memset(belong, , sizeof belong);
}

int L(int x) {
    return (x-)*block+;
}

int R(int x) {
    return min(n, x*block);
}

void update(int l, int r, int c) {
    for(int i=l; i<=min(r, R(belong[l])); i++) {
        a[i] += c;
        b[belong[i]] += c;
    }
    if(belong[l] == belong[r])    return ;
    if(belong[l] != belong[r]) {
        for(int i=L(belong[r]); i<=r; i++) {
            a[i] += c;
            b[belong[i]] += c;
        }
    }
    for(int i=belong[l]+; i<belong[r]; i++) {
        add[i] += c;
        b[i] += c * (R(i) - L(i) + );
    }
}

ll query(int l, int r, int c) {
    ll ans = ;
    for(int i=l; i<=min(r, R(belong[l])); i++) {
        ans += a[i] + add[belong[i]];
        ans %= c;
    }
    if(belong[l] == belong[r])    return ans;
    if(belong[l] != belong[r]) {
        for(int i=L(belong[r]); i<=r; i++) {
            ans += a[i] + add[belong[i]];
            ans %= c;
        }
    }
    for(int i=belong[l]+; i<belong[r]; i++) {
        ans += b[i];
        ans %= c;
    }
    return ans % c;
}

int main() {
    while(~scanf("%d", &n)) {
        init();
        block = sqrt(n);
        for(int i=; i<=n; i++) {
            scanf("%lld", &a[i]);
            belong[i] = (i-) / block + ;
            b[belong[i]] += a[i];
        }
        m = n;
        while(m--) {
            int op, l, r, c;
            scanf("%d%d%d%d", &op, &l, &r, &c);
            if(op == ) {
                update(l, r, c);
            } else {
                ll ans = query(l, r, c+);
                printf("%lld\n", ans);
            }
        }
    }
    return ;
}