判断当前用户有无Administrator的权限

很方便的一个函数，有兴趣的看看！

1. /************************************************************************/
2. /* 函数说明：判断有无Administrator的权限
3. /* 参    数：无
4. /* 返 回 值：成功返回TRUE，否则返回FALSE
5. /* By:Koma   2009.07.28 23:30
6. /************************************************************************/
7. BOOL IsAdmin()
8. {
9. HANDLE hAccessToken;
10. BYTE * InfoBuffer = new BYTE[1024];
11. PTOKEN_GROUPS ptgGroups;
12. DWORD dwInfoBufferSize;
13. PSID psidAdministrators;
14. SID_IDENTIFIER_AUTHORITY siaNtAuthority = SECURITY_NT_AUTHORITY;
15. if(!OpenProcessToken(GetCurrentProcess(),TOKEN_QUERY,&hAccessToken))
16. {
17. delete InfoBuffer;
18. return FALSE;
19. }
20. if(!GetTokenInformation(hAccessToken,TokenGroups,InfoBuffer,1024,&dwInfoBufferSize))
21. {
22. delete InfoBuffer;
23. CloseHandle(hAccessToken);
24. return FALSE;
25. }
26. CloseHandle(hAccessToken);
27. if(!AllocateAndInitializeSid(&siaNtAuthority,
28. 2,
29. SECURITY_BUILTIN_DOMAIN_RID,
30. DOMAIN_ALIAS_RID_ADMINS,
31. 0,0,0,0,0,0,
32. &psidAdministrators))
33. {
34. delete InfoBuffer;
35. return FALSE;
36. }
37. ptgGroups = (PTOKEN_GROUPS)InfoBuffer;
38. for(UINT i = 0; i < ptgGroups->GroupCount; i++)
39. {
40. if(EqualSid(psidAdministrators,ptgGroups->Groups[i].Sid))
41. {
42. FreeSid(psidAdministrators);
43. delete InfoBuffer;
44. return TRUE;
45. }
46. }
47. return FALSE;
48. }