Given an unsorted array, find the maximum difference between the successive elements in its sorted form.

Return 0 if the array contains less than 2 elements.

Example 1:

Input: [3,6,9,1]
Output: 3
Explanation: The sorted form of the array is [1,3,6,9], either
  (3,6) or (6,9) has the maximum difference 3.

Example 2:

Input: [10]
Output: 0
Explanation: The array contains less than 2 elements, therefore return 0.

Note:

  • You may assume all elements in the array are non-negative integers and fit in the 32-bit signed integer range.
  • Try to solve it in linear time/space.

遇到这类问题肯定先想到的是要给数组排序,但是题目要求是要线性的时间和空间,那么只能用桶排序或者基排序。这里用桶排序 Bucket Sort 来做,首先找出数组的最大值和最小值,然后要确定每个桶的容量,即为 (最大值 - 最小值) / 个数 + 1,在确定桶的个数,即为 (最大值 - 最小值) / 桶的容量 + 1,然后需要在每个桶中找出局部最大值和最小值,而最大间距的两个数不会在同一个桶中,而是一个桶的最小值和另一个桶的最大值之间的间距,这是因为所有的数字要尽量平均分配到每个桶中,而不是都拥挤在一个桶中,这样保证了最大值和最小值一定不会在同一个桶中,具体的证明博主也不会,只是觉得这样想挺有道理的,各位看官大神们若知道如何证明请务必留言告诉博主啊,参见代码如下:

class Solution {
public:
int maximumGap(vector<int>& nums) {
if (nums.size() <= ) return ;
int mx = INT_MIN, mn = INT_MAX, n = nums.size(), pre = , res = ;
for (int num : nums) {
mx = max(mx, num);
mn = min(mn, num);
}
int size = (mx - mn) / n + , cnt = (mx - mn) / size + ;
vector<int> bucket_min(cnt, INT_MAX), bucket_max(cnt, INT_MIN);
for (int num : nums) {
int idx = (num - mn) / size;
bucket_min[idx] = min(bucket_min[idx], num);
bucket_max[idx] = max(bucket_max[idx], num);
}
for (int i = ; i < cnt; ++i) {
if (bucket_min[i] == INT_MAX || bucket_max[i] == INT_MIN) continue;
res = max(res, bucket_min[i] - bucket_max[pre]);
pre = i;
}
return res;
}
};

Github 同步地址:

https://github.com/grandyang/leetcode/issues/164

参考资料:

https://leetcode.com/problems/maximum-gap

http://blog.csdn.net/u011345136/article/details/41963051

https://leetcode.com/problems/maximum-gap/discuss/50642/radix-sort-solution-in-java-with-explanation

https://leetcode.com/problems/maximum-gap/discuss/50643/bucket-sort-java-solution-with-explanation-on-time-and-space

LeetCode All in One 题目讲解汇总(持续更新中...)

[LeetCode] 164. Maximum Gap 求最大间距的更多相关文章

  1. LeetCode 164. Maximum Gap[翻译]

    164. Maximum Gap 164. 最大间隔 Given an unsorted array, find the maximum difference between the successi ...

  2. [LintCode] Maximum Gap 求最大间距

    Given an unsorted array, find the maximum difference between the successive elements in its sorted f ...

  3. leetcode[164] Maximum Gap

    梅西刚梅开二度,我也记一题. 在一个没排序的数组里,找出排序后的相邻数字的最大差值. 要求用线性时间和空间. 如果用nlgn的话,直接排序然后判断就可以了.so easy class Solution ...

  4. [LeetCode] Maximum Gap 求最大间距

    Given an unsorted array, find the maximum difference between the successive elements in its sorted f ...

  5. ✡ leetcode 164. Maximum Gap 寻找最大相邻数字差 --------- java

    Given an unsorted array, find the maximum difference between the successive elements in its sorted f ...

  6. Java for LeetCode 164 Maximum Gap

    Given an unsorted array, find the maximum difference between the successive elements in its sorted f ...

  7. 【LeetCode】164. Maximum Gap (2 solutions)

    Maximum Gap Given an unsorted array, find the maximum difference between the successive elements in ...

  8. 【刷题-LeetCode】164 Maximum Gap

    Maximum Gap Given an unsorted array, find the maximum difference between the successive elements in ...

  9. 【leetcode】Maximum Gap

    Maximum Gap Given an unsorted array, find the maximum difference between the successive elements in ...

随机推荐

  1. H3C S12508单板卡 通过bootware升级software版本

    H3C S12508单板卡 通过bootware升级software版本 案例:S12508更换主控板LST1MRPNC1 ,该板卡状态为Slave状态: 设备状态:S12508共2台做了堆叠,共含4 ...

  2. KVM学习笔记--静态迁移

    .静态迁移过程如下 (1)确定虚拟机关闭状态 (2)准备迁移oeltest02虚拟机,查看该虚拟机配置的磁盘文件 (3)导入虚拟机配置文件 [root@node1~]# virsh dumpxml o ...

  3. 禁止直接通过IP访问--->nginx

    在nginx.conf 中添加 server{ listen 80 default_server; return 501; } 注: nginx加载include是按顺序,如果是文件夹,就是文件顺序, ...

  4. 1、Ext.NET 1.7官方示例笔记-事件

    官网参考地址:https://examples1.ext.net/#/Events/DirectEvents/Overview/ 先了解一下“事件” Ext.NET包括3种事件机制 DirectEve ...

  5. Java并发包——线程安全的Map相关类

    Java并发包——线程安全的Map相关类 摘要:本文主要学习了Java并发包下线程安全的Map相关的类. 部分内容来自以下博客: https://blog.csdn.net/bill_xiang_/a ...

  6. DevExpress的TreeList的常用属性设置以及常用事件

    场景 Winform控件-DevExpress18下载安装注册以及在VS中使用: https://blog.csdn.net/BADAO_LIUMANG_QIZHI/article/details/1 ...

  7. JS-21点游戏

    //21点游戏 let readline=require("readline-sync"); //清屏函数 let clear=()=>process.stdout.writ ...

  8. 3 测试使用和LogCat日志

    测试概念: 1.根据是否知道源代码分: 黑盒测试:功能测试 白盒测试:编写代码进行测试 2.测试力度划分: 方法测试: 单元测试: 集成测试: 系统测试: 3.暴力程度划分: 压力测试: 冒烟测试:压 ...

  9. RDD算子的使用

    TransformationDemo.scala import org.apache.spark.{HashPartitioner, SparkConf, SparkContext} import s ...

  10. Odoo 启动选项总结

    转载请注明原文地址:https://www.cnblogs.com/ygj0930/p/11189209.html 一:启动选项用在哪里 如果你是用Pycharm进行odoo二次开发的话,可以通过 R ...