LeeCode-Rotate Array

Rotate an array of n elements to the right by k steps.

For example, with n = 7 and k = 3, the array [1,2,3,4,5,6,7] is rotated to [5,6,7,1,2,3,4].

Note:
Try to come up as many solutions as you can, there are at least 3 different ways to solve this problem.

 void rotate(int* nums, int numsSize, int k)
 {
         int *TempArray;
     TempArray=(int *)malloc(numsSize*sizeof(int));
 
     for(int i=;i<numsSize;i++)
     {
         if((i+k+)<=numsSize)
         {
             TempArray[i+k]=nums[i];
         }
         else
         {
             TempArray[(i+k)%numsSize]=nums[i];
         }
     }
 
     for(int i=;i<numsSize;i++)
     {
         nums[i]=TempArray[i];
     }
 }