LeetCode-Combination Sum IV
Given an integer array with all positive numbers and no duplicates, find the number of possible combinations that add up to a positive integer target.
Example:
nums = [1, 2, 3]
target = 4 The possible combination ways are:
(1, 1, 1, 1)
(1, 1, 2)
(1, 2, 1)
(1, 3)
(2, 1, 1)
(2, 2)
(3, 1) Note that different sequences are counted as different combinations. Therefore the output is 7.
Follow up:
What if negative numbers are allowed in the given array?
How does it change the problem?
What limitation we need to add to the question to allow negative numbers?
Credits:
Special thanks to @pbrother for adding this problem and creating all test cases.
public class Solution {
public int combinationSum4(int[] nums, int target) {
if (nums.length==0) return 0;
Arrays.sort(nums); int[] combines = new int[target+1];
combines[0] = 1; for (int val=1;val<=target;val++)
for (int i=0;i<nums.length;i++)
if (val >= nums[i]){
combines[val] += combines[val-nums[i]];
} else break; return combines[target];
}
}
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