[HIHO1184]连通性二·边的双连通分量（双连通分量）

题目链接：http://hihocoder.com/problemset/problem/1184

题意裸，写个博客记下输出姿势。

 /*
 ━━━━━┒ギリギリ♂ eye！
 ┓┏┓┏┓┃キリキリ♂ mind！
 ┛┗┛┗┛┃＼○／
 ┓┏┓┏┓┃ /
 ┛┗┛┗┛┃ノ)
 ┓┏┓┏┓┃
 ┛┗┛┗┛┃
 ┓┏┓┏┓┃
 ┛┗┛┗┛┃
 ┓┏┓┏┓┃
 ┛┗┛┗┛┃
 ┓┏┓┏┓┃
 ┃┃┃┃┃┃
 ┻┻┻┻┻┻
 */
 #include <algorithm>
 #include <iostream>
 #include <iomanip>
 #include <cstring>
 #include <climits>
 #include <complex>
 #include <fstream>
 #include <cassert>
 #include <cstdio>
 #include <bitset>
 #include <vector>
 #include <deque>
 #include <queue>
 #include <stack>
 #include <ctime>
 #include <set>
 #include <map>
 #include <cmath>
 using namespace std;
 #define fr first
 #define sc second
 #define cl clear
 #define BUG puts("here!!!")
 #define W(a) while(a--)
 #define pb(a) push_back(a)
 #define Rint(a) scanf("%d", &a)
 #define Rll(a) scanf("%lld", &a)
 #define Rs(a) scanf("%s", a)
 #define Cin(a) cin >> a
 #define FRead() freopen("in", "r", stdin)
 #define FWrite() freopen("out", "w", stdout)
 #define Rep(i, len) for(int i = 0; i < (len); i++)
 #define For(i, a, len) for(int i = (a); i < (len); i++)
 #define Cls(a) memset((a), 0, sizeof(a))
 #define Clr(a, x) memset((a), (x), sizeof(a))
 #define Full(a) memset((a), 0x7f7f, sizeof(a))
 #define lrt rt << 1
 #define rrt rt << 1 | 1
 #define pi 3.14159265359
 #define RT return
 #define lowbit(x) x & (-x)
 #define onenum(x) __builtin_popcount(x)
 typedef long long LL;
 typedef long double LD;
 typedef unsigned long long ULL;
 typedef pair<int, int> pii;
 typedef pair<string, int> psi;
 typedef pair<LL, LL> pll;
 typedef map<string, int> msi;
 typedef vector<int> vi;
 typedef vector<LL> vl;
 typedef vector<vl> vvl;
 typedef vector<bool> vb;
 
 const int maxn = ;
 const int maxm = ;
 typedef struct Edge {
     int u, v;
     int next, i;
     bool cut;
     Edge() {}
     Edge(int uu, int vv, int ii) : u(uu), v(vv), i(ii) {}
 }Edge;
 
 Edge edge[maxm];
 int head[maxn], ecnt;
 int n, m;
 int dfn[maxn];
 int low[maxn];
 bool vis[maxn];
 bool cut[maxn];
 vi bridge;
 int st[maxn], top;
 int belong[maxn], bcnt;
 vi tmp;
 int ret;
 
 void init() {
     Clr(head, -); Cls(low); Cls(dfn);
     Cls(vis); Cls(cut); Cls(st); ret = ;
     bcnt = ; top = ; ecnt = ; bridge.cl();
 }
 
 void adde(int uu, int vv, int ii) {
     edge[ecnt] = Edge(uu, vv, ii);
     edge[ecnt].cut = ;
     edge[ecnt].next = head[uu];
     head[uu] = ecnt++;
 }
 
 void tarjan(int u, int d, int p) {
     low[u] = dfn[u] = d;
     st[++top] = u;
     vis[u] = ;
     for(int i = head[u]; ~i; i=edge[i].next) {
         int v = edge[i].v;
         int id = edge[i].i;
         if(p == id) continue;
         if(!dfn[v]) {
             tarjan(v, d+, id);
             low[u] = min(low[u], low[v]);
             if(low[v] > dfn[u]) {
                 bridge.pb(i);
                 edge[i].cut = edge[i^].cut = ;
             }
         }
         else low[u] = min(low[u], dfn[v]);
     }
     if(low[u] == dfn[u]) {
         tmp.cl();
         int v;
         bcnt = 0x7f7f7f;
         do {
             v = st[top--];
             vis[v] = ;
             bcnt = min(bcnt, v);
             tmp.pb(v);
         }while(v != u);
         Rep(i, tmp.size()) belong[tmp[i]] = bcnt;
         ret++;
     }
 }
 
 int main() {
     // FRead();
     int u, v;
     while(~scanf("%d%d", &n, &m)) {
         init();
         For(i, , m+) {
             Rint(u); Rint(v);
             adde(u, v, i);
             adde(v, u, i);
         }
         For(i, , n+) {
             if(!dfn[i]) tarjan(i, , -);
         }
         printf("%d\n", ret);
         For(i, , n+) printf("%d ", belong[i]);
         printf("\n");
     }
     RT ;
 }