leetcode917

class Solution {
public:
    string reverseOnlyLetters(string S) {
        int len = S.length();
        queue<char> Q;
        stack<char> ST;
        vector<int> V;
        for (int i = ; i < len; i++)
        {
            char c = S[i];
            //小写 ASCII[97,122]
            //大写 ASCII[65,90]
            if ((c >=  && c <= ) || (c >=  && c <= ))//字母
            {
                ST.push(c);
            }
            else//符号
            {
                Q.push(c);
                V.push_back(i);
            }
        }
        string R;
        for (int i = ; i < len; i++)
        {
            char c = ;
            if (find(V.begin(), V.end(), i) == V.end())//当前应该是一个字符
            {
                c = ST.top();
                ST.pop();
            }
            else
            {
                c = Q.front();
                Q.pop();
            }
            R += c;
        }
        return R;
    }
};