【LeetCode】374. Guess Number Higher or Lower 解题报告（Java & Python）

作者： 负雪明烛
id： fuxuemingzhu
个人博客： http://fuxuemingzhu.cn/

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目录

• • 题目描述
  • 题目大意
  • 解题方法
  • 日期

题目地址：https://leetcode.com/problems/guess-number-higher-or-lower/#/description

题目描述

We are playing the Guess Game. The game is as follows:

I pick a number from 1 to n. You have to guess which number I picked.

Every time you guess wrong, I’ll tell you whether the number is higher or lower.

You call a pre-defined API guess(int num) which returns 3 possible results (-1, 1, or 0):

-1 : My number is lower
 1 : My number is higher
 0 : Congrats! You got it!

Example:

n = 10, I pick 6.

Return 6.

题目大意

从1～n中取了一个数字，现在给出了guess()函数，要你猜这个数字是多少。

解题方法

做这个题的重点是明白guess()函数，题目说了是我取了一个数字，你去猜这个数字，guess()是我的数字大了还是小了。。明白这个意思了么。

所以这个题是标准的二分查找。

/* The guess API is defined in the parent class GuessGame.
   @param num, your guess
   @return -1 if my number is lower, 1 if my number is higher, otherwise return 0
      int guess(int num); */

public class Solution extends GuessGame {
    public int guessNumber(int n) {
        int low = 1;
        int high = n;
        int mid = 0;
        while(low <= high){
            mid = low + (high - low) / 2;
            if(guess(mid) == -1){
                high = mid - 1;
            }else if(guess(mid) == 1){
                low = mid + 1;
            }else{
                return mid;
            }
        }
        return mid;
    }
}

python解法如下：

# The guess API is already defined for you.
# @param num, your guess
# @return -1 if my number is lower, 1 if my number is higher, otherwise return 0
# def guess(num):

class Solution(object):
    def guessNumber(self, n):
        """
        :type n: int
        :rtype: int
        """
        left, right = 1, n #[left, right]
        mid = left
        while left <= right:
            mid = (right + left) / 2
            res = guess(mid)
            if res == 0:
                return mid
            elif res == 1:
                left = mid + 1
            else:
                right = mid - 1
        return mid

日期

2017 年 5 月 10 日
2018 年 11 月 23 日 —— 这就星期五了？？