HDOJ 4424 Conquer a New Region

并检查集合

侧降序,每增加一个侧面应该推断，其中基本建设方.....

Conquer a New Region

Time Limit: 8000/4000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)

Total Submission(s): 1169    Accepted Submission(s): 373

Problem Description

The wheel of the history rolling forward, our king conquered a new region in a distant continent.

There are N towns (numbered from 1 to N) in this region connected by several roads. It's confirmed that there is exact one route between any two towns. Traffic is important while controlled colonies are far away from the local country. We define the capacity
C(i, j) of a road indicating it is allowed to transport at most C(i, j) goods between town i and town j if there is a road between them. And for a route between i and j, we define a value S(i, j) indicating the maximum traffic capacity between i and j which
is equal to the minimum capacity of the roads on the route. 

Our king wants to select a center town to restore his war-resources in which the total traffic capacities from the center to the other N - 1 towns is maximized. Now, you, the best programmer in the kingdom, should help our king to select this center.

 

Input

There are multiple test cases.

The first line of each case contains an integer N. (1 <= N <= 200,000)

The next N - 1 lines each contains three integers a, b, c indicating there is a road between town a and town b whose capacity is c. (1 <= a, b <= N, 1 <= c <= 100,000)

 

Output

For each test case, output an integer indicating the total traffic capacity of the chosen center town.

 

Sample Input

4
1 2 2
2 4 1
2 3 1
4
1 2 1
2 4 1
2 3 1

 

Sample Output

4
3

 

Source

2012 Asia ChangChun Regional Contest

 

#include <iostream>
#include <cstdio>
#include <cstring>
#include <algorithm>

using namespace std;

const int maxn=200200;

typedef long long int LL;

struct Edge
{
	LL u,v,w;
}edge[maxn];

bool cmp(Edge x,Edge y)
{
	return x.w>y.w;
}

LL n;
LL fa[maxn];
LL value[maxn];
LL sz[maxn];

LL find(LL x)
{
	if(x==fa[x]) return x;
	return fa[x]=find(fa[x]);
}

int main()
{
	while(scanf("%I64d",&n)!=EOF)
	{
		for(LL i=0;i<n-1;i++)
		{
			LL a,b,c;
			scanf("%I64d%I64d%I64d",&a,&b,&c);
			edge[i].u=a; edge[i].v=b; edge[i].w=c;
			fa[i]=i;sz[i]=1;value[i]=0;
		}
		fa[n-1]=n-1; sz[n-1]=1; value[n-1]=0;
		fa[n]=n;sz[n]=1;value[n]=0;
		sort(edge,edge+n-1,cmp);
		for(LL i=0;i<n-1;i++)
		{
			LL u=edge[i].u,v=edge[i].v; LL w=edge[i].w;
			LL U=find(u),V=find(v);
			if(U==V) continue;
			LL VVV=max(value[U]+w*sz[V],value[V]+w*sz[u]);
			fa[U]=V;
			value[V]=VVV;
			sz[V]=sz[V]+sz[U];
		}
		cout<<value[find(1)]<<endl;
	}
	return 0;
}

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