++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++

给定一个二叉树，找出他的最小的深度。

最小的深度，指的是从根节点到叶子节点的，经历的最多的节点个数。

++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++

Given a binary tree, find its maximum depth.

The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node.

  1. ++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++
  1. test.cpp:
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
  
#include <iostream>
#include <cstdio>
#include <stack>
#include <vector>
#include <queue>
#include "BinaryTree.h"

using namespace std;

int maxDepth(TreeNode *root)
{
    if(root == NULL)
    {
        return 0;
    }
    /*用队列来模拟广度优先搜索*/
    queue<TreeNode *> que;
    que.push(root);
    int count = 1;
    int depth = 0;
    while(!que.empty())
    {
        TreeNode *tmp = que.front();
        que.pop();
        count --;

if(tmp->left != NULL)
        {
            que.push(tmp->left);
        }
        if(tmp->right != NULL)
        {
            que.push(tmp->right);
        }
        if(count == 0)
        {
            depth ++;
            count = que.size();
        }
    }
    return depth;
}

// 树中结点含有分叉，
//                  8
//              /       \
//             6         1
//           /   \
//          9     2
//               / \
//              4   7
int main()
{
    TreeNode *pNodeA1 = CreateBinaryTreeNode(8);
    TreeNode *pNodeA2 = CreateBinaryTreeNode(6);
    TreeNode *pNodeA3 = CreateBinaryTreeNode(1);
    TreeNode *pNodeA4 = CreateBinaryTreeNode(9);
    TreeNode *pNodeA5 = CreateBinaryTreeNode(2);
    TreeNode *pNodeA6 = CreateBinaryTreeNode(4);
    TreeNode *pNodeA7 = CreateBinaryTreeNode(7);

ConnectTreeNodes(pNodeA1, pNodeA2, pNodeA3);
    ConnectTreeNodes(pNodeA2, pNodeA4, pNodeA5);
    ConnectTreeNodes(pNodeA5, pNodeA6, pNodeA7);

cout << maxDepth(pNodeA1) << endl;

DestroyTree(pNodeA1);
    return 0;
}
结果输出：
4
 
BinaryTree.h:
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
  
#ifndef _BINARY_TREE_H_
#define _BINARY_TREE_H_

struct TreeNode
{
    int val;
    TreeNode *left;
    TreeNode *right;
    TreeNode(int x) : val(x), left(NULL), right(NULL) {}
};

TreeNode *CreateBinaryTreeNode(int value);
void ConnectTreeNodes(TreeNode *pParent,
                      TreeNode *pLeft, TreeNode *pRight);
void PrintTreeNode(TreeNode *pNode);
void PrintTree(TreeNode *pRoot);
void DestroyTree(TreeNode *pRoot);

#endif /*_BINARY_TREE_H_*/
BinaryTree.cpp:
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
88
89
  
#include <iostream>
#include <cstdio>
#include "BinaryTree.h"

using namespace std;

/**
 * Definition for binary tree
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
 * };
 */

//创建结点
TreeNode *CreateBinaryTreeNode(int value)
{
    TreeNode *pNode = new TreeNode(value);

return pNode;
}

//连接结点
void ConnectTreeNodes(TreeNode *pParent, TreeNode *pLeft, TreeNode *pRight)
{
    if(pParent != NULL)
    {
        pParent->left = pLeft;
        pParent->right = pRight;
    }
}

//打印节点内容以及左右子结点内容
void PrintTreeNode(TreeNode *pNode)
{
    if(pNode != NULL)
    {
        printf("value of this node is: %d\n", pNode->val);

if(pNode->left != NULL)
            printf("value of its left child is: %d.\n", pNode->left->val);
        else
            printf("left child is null.\n");

if(pNode->right != NULL)
            printf("value of its right child is: %d.\n", pNode->right->val);
        else
            printf("right child is null.\n");
    }
    else
    {
        printf("this node is null.\n");
    }

printf("\n");
}

//前序遍历递归方法打印结点内容
void PrintTree(TreeNode *pRoot)
{
    PrintTreeNode(pRoot);

if(pRoot != NULL)
    {
        if(pRoot->left != NULL)
            PrintTree(pRoot->left);

if(pRoot->right != NULL)
            PrintTree(pRoot->right);
    }
}

void DestroyTree(TreeNode *pRoot)
{
    if(pRoot != NULL)
    {
        TreeNode *pLeft = pRoot->left;
        TreeNode *pRight = pRoot->right;

delete pRoot;
        pRoot = NULL;

DestroyTree(pLeft);
        DestroyTree(pRight);
    }
}

 
  1.  

 

【二叉树的递归】02二叉树的最大深度【Maximum Depth of Binary Tree】的更多相关文章

  1. LeetCode 104. 二叉树的最大深度(Maximum Depth of Binary Tree)

    104. 二叉树的最大深度 104. Maximum Depth of Binary Tree 题目描述 给定一个二叉树,找出其最大深度. 二叉树的深度为根节点到最远叶子节点的最长路径上的节点数. 说 ...

  2. [Swift]LeetCode104. 二叉树的最大深度 | Maximum Depth of Binary Tree

    Given a binary tree, find its maximum depth. The maximum depth is the number of nodes along the long ...

  3. [LintCode] Maximum Depth of Binary Tree 二叉树的最大深度

    Given a binary tree, find its maximum depth. The maximum depth is the number of nodes along the long ...

  4. leetcode 104 Maximum Depth of Binary Tree二叉树求深度

    Maximum Depth of Binary Tree Total Accepted: 63668 Total Submissions: 141121 My Submissions Question ...

  5. 104. Maximum Depth of Binary Tree(C++)

    104. Maximum Depth of Binary Tree Given a binary tree, find its maximum depth. The maximum depth is ...

  6. LeetCode:Minimum Depth of Binary Tree,Maximum Depth of Binary Tree

    LeetCode:Minimum Depth of Binary Tree Given a binary tree, find its minimum depth. The minimum depth ...

  7. 【LeetCode练习题】Maximum Depth of Binary Tree

    Maximum Depth of Binary Tree Given a binary tree, find its maximum depth. The maximum depth is the n ...

  8. [Leetcode][JAVA] Minimum Depth of Binary Tree && Balanced Binary Tree && Maximum Depth of Binary Tree

    Minimum Depth of Binary Tree Given a binary tree, find its minimum depth. The minimum depth is the n ...

  9. LeetCode Javascript实现 258. Add Digits 104. Maximum Depth of Binary Tree 226. Invert Binary Tree

    258. Add Digits Digit root 数根问题 /** * @param {number} num * @return {number} */ var addDigits = func ...

  10. 【LeetCode】104. Maximum Depth of Binary Tree (2 solutions)

    Maximum Depth of Binary Tree  Given a binary tree, find its maximum depth. The maximum depth is the ...

随机推荐

  1. 什么是bin文件？

            知道多问bin文件几个为什么.是在出现下面这个问题时引发的.         出现这种问题:未能载入文件或程序集"DAL"或它的某一个依赖项. 系统找不到指定的文件 ...

  2. 不使用库函数，编写函数int strcmp(char *source, char *dest) 相等返回0，不等返回-1；

    答案:一. int strcmp(char  *source, char *dest) { /* assert的作用是现计算表达式 expression ,如果其值为假(即为0),那么它先向stder ...

  3. Windows 下Node.js开发环境配置

    第一步:安装VirtualBox(以管理员身份安装) 1.安装完成后,打开VirtualBox,点击“新建”按钮,输入信息,“下一步”(名称可任意) 2.设置内存为1024MB,“下一步”—>“ ...

  4. c3p0;maven;model;

  5. mac查看网页时翻页

    1 fn + 上下  翻页 2 command + 上下  一下子到文档头和文档尾部

  6. POJ3094 Sky Code(莫比乌斯反演)

    POJ3094 Sky Code(莫比乌斯反演) Sky Code 题意 给你\(n\le 10^5\)个数,这些数\(\le 10^5\),问这些这些数组成的互不相同的无序四元组(a,b,c,d)使 ...

  7. BZOJ1791: [Ioi2008]Island 岛屿

    BZOJ1791: [Ioi2008]Island 岛屿 Description 你将要游览一个有N个岛屿的公园. 从每一个岛i出发,只建造一座桥. 桥的长度以Li表示. 公园内总共有N座桥. 尽管每 ...

  8. 【android】在Service的onStartCommand()中调用stopself()应该注意的问题

    在Service的onStartCommand()中调用stopself()后并不会立马destroy掉service,而是等onStartCommand()运行完才destroy. public c ...

  9. ABAP下载服务器文件到本机

    转自http://blog.sina.com.cn/s/blog_701594f40100l8ml.html ABAP:下载服务器文件到本机 对服务器的文件进行读写操作,SAP提供了OPEN DATA ...

  10. Broadcast Intent & Broadcast Receiver

    当Android系统发生某种状况,必须通知所有程序进行处理时,例如电量不足等,可利用Broadcast Intent对象的功能来进行信息广播. 运行机制包括两部:送出Intent对象的程序:监听广播信 ...