UVA 11292-Dragon of Loowater (贪心)
Once upon a time, in the Kingdom of Loowater, a minor nuisance turned into a major problem.
The shores of Rellau Creek in central Loowater had always been a prime breeding ground for geese. Due to the lack of predators, the geese population was out of control. The people of Loowater mostly kept clear of the geese. Occasionally, a goose would attack one of the people, and perhaps bite off a finger or two, but in general, the people tolerated the geese as a minor nuisance.
One day, a freak mutation occurred, and one of the geese spawned a multi-headed fire-breathing dragon. When the dragon grew up, he threatened to burn the Kingdom of Loowater to a crisp. Loowater had a major problem. The king was alarmed, and called on his knights to slay the dragon and save the kingdom.
The knights explained: "To slay the dragon, we must chop off all its heads. Each knight can chop off one of the dragon's heads. The heads of the dragon are of different sizes. In order to chop off a head, a knight must be at least as tall as the diameter of the head. The knights' union demands that for chopping off a head, a knight must be paid a wage equal to one gold coin for each centimetre of the knight's height."
Would there be enough knights to defeat the dragon? The king called on his advisors to help him decide how many and which knights to hire. After having lost a lot of money building Mir Park, the king wanted to minimize the expense of slaying the dragon. As one of the advisors, your job was to help the king. You took it very seriously: if you failed, you and the whole kingdom would be burnt to a crisp!
Input Specification:
The input contains several test cases. The first line of each test case contains two integers between 1 and 20000 inclusive, indicating the number n of heads that the dragon has, and the number m of knights in the kingdom. The next n lines each contain an integer, and give the diameters of the dragon's heads, in centimetres. The following mlines each contain an integer, and specify the heights of the knights of Loowater, also in centimetres.
The last test case is followed by a line containing:
0 0
Output Specification:
For each test case, output a line containing the minimum number of gold coins that the king needs to pay to slay the dragon. If it is not possible for the knights of Loowater to slay the dragon, output the line:
Loowater is doomed!
Sample Input:
2 3
5
4
7
8
4
2 1
5
5
10
0 0
Output for Sample Input:
11
Loowater is doomed!
题解:贪心
代码:
#include<cstdio>
#include<iostream>
#include<algorithm>
#include<cstring>
using namespace std;
int main() {
int n,m;
int a[100005];
int b[100005];
while(scanf("%d%d",&n,&m)!=EOF) {
if(n==0&&m==0) {
break;
}
for(int t=0; t<n; t++) {
scanf("%d",&a[t]);
}
for(int t=0; t<m; t++) {
scanf("%d",&b[t]);
}
sort(a,a+n);
sort(b,b+m);
long long int sum=0;
int j=0;
for(int t=0; t<m; t++) {
if(a[j]<=b[t]) {
sum+=b[t];
j++;
if(j==n) {
break;
}
}
}
if(j<n) {
printf("Loowater is doomed!\n");
} else {
printf("%lld\n",sum);
}
}
return 0;
}
UVA 11292-Dragon of Loowater (贪心)的更多相关文章
- UVA - 11292 Dragon of Loowater 贪心
贪心策略:一个直径为X的头颅,应该让雇佣费用满足大于等于X且最小的骑士来砍掉,这样才能使得花费最少. AC代码 #include <cstdio> #include <cmath&g ...
- UVA 11292 Dragon of Loowater(简单贪心)
Problem C: The Dragon of Loowater Once upon a time, in the Kingdom of Loowater, a minor nuisance tur ...
- uva 11292 Dragon of Loowater (勇者斗恶龙)
Problem C: The Dragon of Loowater Once upon a time, in the Kingdom of Loowater, a minor nuisance tur ...
- [ACM_水题] UVA 11292 Dragon of Loowater [勇士斗恶龙 双数组排序 贪心]
Once upon a time, in the Kingdom of Loowater, a minor nuisance turned into a major problem. The shor ...
- UVa 11292 - Dragon of Loowater(排序贪心)
Once upon a time, in the Kingdom of Loowater, a minor nuisance turned into a major problem.The shore ...
- UVa 11292 Dragon of Loowater
简单贪心 龙头的直径和人的佣金排序,价值小的人和直径小的配 #include<iostream> #include<cstdio> #include<cmath> ...
- UVa 11292 Dragon of Loowater (水题,排序)
题意:有n个条龙,在雇佣勇士去杀,每个勇士能力值为x,只能杀死头的直径y小于或等于自己能力值的龙,只能被雇佣一次,并且你要给x赏金,求最少的赏金. 析:很简单么,很明显,能力值高的杀直径大的,低的杀直 ...
- UVA它11292 - Dragon of Loowater
Problem C: The Dragon of Loowater Once upon a time, in the Kingdom of Loowater, a minor nuisance tur ...
- uva 11292 The Dragon of Loowater(贪心)
题目大意: 你的王国里有一条n个头的恶龙,你希望雇一些骑士把它杀死(即砍掉所有头).村里有m个骑士可以雇佣,一个能力值为x的骑士可以砍掉恶龙一个直径不超过x的头,且需要支付x个金币.如何雇佣骑士才 ...
- 贪心/思维题 UVA 11292 The Dragon of Loowater
题目传送门 /* 题意:n个头,m个士兵,问能否砍掉n个头 贪心/思维题:两个数组升序排序,用最弱的士兵砍掉当前的头 */ #include <cstdio> #include <c ...
随机推荐
- 44-final, finally, finalize的区别
final—修饰符(关键字) 如果一个类被声明为final,意味着它不能再派生出新的子类,不能作为父类被继承. 因此一个类不能既被声明为 abstract的,又被声明为final的.将变量或方法声明为 ...
- JQury的选择器
jQuery 的选择器可谓之强大无比,这里简单地总结一下常用的元素查找方法 $("#myELement") 选择id值等于myElement的元素,id值不能重复在文档中只能有一个 ...
- Jenkins持续集成(上)-Windows下安装Jenkins
环境:Windows 2008 R2.Jenkins2.235.1: 概要 前面写过一篇文章,<自动发布-asp.net自动发布.IIS站点自动发布(集成SLB.配置管理.Jenkins)> ...
- 在Linux下安装nginx服务器详细教程
首先安装centos的扩展源 yum install epel-release 安装Nginx 方法一: yum install nginx -y 查看版本号,开启nginx,查看进程 nginx – ...
- JVM初探(三):类加载机制
一.概述 我们知道java代码会被编译为.class文件,这里class文件中的类信息最终还是需要jvm加载以后才能使用. 事实上,虚拟机把描述类的数据从Class文件加载到内存,并对数据进行校验,转 ...
- 2020-04-13:怎么在日志里排查错误,该用哪些Linux命令
能通过less命令打开文件,通过Shift+G到达文件底部,再通过?+关键字的方式来根据关键来搜索信息. 能通过grep的方式查关键字,具体用法是, grep 关键字 文件名,如果要两次在结果里查找的 ...
- C#设计模式之4-原型模式
原型模式(Prototype Pattern) 该文章的最新版本已迁移至个人博客[比特飞],单击链接 https://www.byteflying.com/archives/395 访问. 原型模式属 ...
- three.js 制作机房(上)
three.js使用的人太少了,一个博文就几百个人看,之前发js基础哪怕是d3都会有几千的阅读量,看看以后考虑说一说d3了,哈哈.吐槽完毕回归正题.前几天郭先生看到网上有人开发了3D机房,正愁博客没什 ...
- flask-sqlalchemy同字段多条件过滤
举例 from sqlalchemy import or_,and_# from operator import or_, and_ allapp = AppServer.query.filter(a ...
- Debug很重要
之前做一个小功能,就是用php发送邮件,项目中已经使用了wordpress的wp_mail,所以同事建议我继续用wp_mail函数. 然而遇到了一个奇怪的情况,邮件没有发出去,也没有任何报错日志. 照 ...