求height数组

  procedure getheight;
  var
   i,po1,po2:longint;
    begin
      for i:= to len do
        begin
          if k> then k:=k-;
          po1:=i;po2:=sa[rank[i]-];
          while (a[po1+k]=a[po2+k]) and (po1+k<=len) and (po2+k<=len) do
            inc(k);
          height[i]:=k;
        end;
    end;

其中height[i]表示suffix（i）与suffix(sa[rank[i]-1])的最长公共前缀

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c++

void getheight(){
      int k=;
      int po1,po2;
      for (int i=;i<=n;i++){
          po1=i,po2=sa[rank[i]-];
          if (k) k--;
          while ((st[po1+k]==st[po2+k])&&(po1+k<=len)&&(po2+k<=len))
          k++;
          height[rank[i]-]=k;
      }
  }

其中height[i]表示rank[i]+1与rank[i]的最长公共前缀