。。。不行。这题之后、不做1000分以下的了。很耻辱
 
A. Bear and Big Brother
time limit per test

1 second

memory limit per test

256 megabytes

input

standard input

output

standard output

Bear Limak wants to become the largest of bears, or at least to become larger than his brother Bob.

Right now, Limak and Bob weigh a and b respectively. It's guaranteed that Limak's weight is smaller than or equal to his brother's weight.

Limak eats a lot and his weight is tripled after every year, while Bob's weight is doubled after every year.

After how many full years will Limak become strictly larger (strictly heavier) than Bob?

Input

The only line of the input contains two integers a and b (1 ≤ a ≤ b ≤ 10) — the weight of Limak and the weight of Bob respectively.

Output

Print one integer, denoting the integer number of years after which Limak will become strictly larger than Bob.

Examples
input

Copy
4 7
output

Copy
2
input

Copy
4 9
output

Copy
3
input

Copy
1 1
output

Copy
1
Note

In the first sample, Limak weighs 4 and Bob weighs 7 initially. After one year their weights are 4·3 = 12 and 7·2 = 14 respectively (one weight is tripled while the other one is doubled). Limak isn't larger than Bob yet. After the second year weights are 36 and 28, so the first weight is greater than the second one. Limak became larger than Bob after two years so you should print 2.

In the second sample, Limak's and Bob's weights in next years are: 12 and 18, then 36 and 36, and finally 108 and 72 (after three years). The answer is 3. Remember that Limak wants to be larger than Bob and he won't be satisfied with equal weights.

In the third sample, Limak becomes larger than Bob after the first year. Their weights will be 3 and 2 then.

#include<iostream>
using namespace std;
int main(){
int a;
int b;
cin>>a;
cin>>b;
int res = ;
do{
res++;
a*=;
b*=;
}while(a<=b);
cout<<res;
return ;
}

Codeforces A. Bear and Big Brother的更多相关文章

  1. Codeforces 791A Bear and Big Brother(暴力枚举,模拟)

    A. Bear and Big Brother time limit per test:1 second memory limit per test:256 megabytes input:stand ...

  2. Codeforces 385C Bear and Prime Numbers

    题目链接:Codeforces 385C Bear and Prime Numbers 这题告诉我仅仅有询问没有更新通常是不用线段树的.或者说还有比线段树更简单的方法. 用一个sum数组记录前n项和, ...

  3. Codeforces 385B Bear and Strings

    题目链接:Codeforces 385B Bear and Strings 记录下每一个bear的起始位置和终止位置,然后扫一遍记录下来的结构体数组,过程中用一个变量记录上一个扫过的位置,用来去重. ...

  4. Codeforces791A Bear and Big Brother

    A. Bear and Big Brother time limit per test 1 second memory limit per test 256 megabytes input stand ...

  5. Codeforces 680D Bear and Tower of Cubes 贪心 DFS

    链接 Codeforces 680D Bear and Tower of Cubes 题意 求一个不超过 \(m\) 的最大体积 \(X\), 每次选一个最大的 \(x\) 使得 \(x^3\) 不超 ...

  6. Codeforces 385C Bear and Prime Numbers(素数预处理)

    Codeforces 385C Bear and Prime Numbers 其实不是多值得记录的一道题,通过快速打素数表,再做前缀和的预处理,使查询的复杂度变为O(1). 但是,我在统计数组中元素出 ...

  7. [Codeforces 639F] Bear and Chemistry (Tarjan+虚树)(有详细注释)

    [Codeforces 639F] Bear and Chemistry(Tarjan+虚树) 题面 给出一个n个点,m条边的无向图(不保证连通,可能有自环和重边),有q次询问,每次询问给出p个点和q ...

  8. 【codeforces 791A】Bear and Big Brother

    [题目链接]:http://codeforces.com/contest/791/problem/A [题意] 给你两个数字a和b; a每次乘3,b每次乘2 问你什么时候a第一次大于b [题解] 傻逼 ...

  9. Codeforces 791B Bear and Friendship Condition(DFS,有向图)

    B. Bear and Friendship Condition time limit per test:1 second memory limit per test:256 megabytes in ...

随机推荐

  1. 【python学习】新手基础程序练习(一)

    首先得先编一下程序员必须编的程序——Hello World……(这应该是程序员情结...) #coding=utf-8 #Version:python3.7.0 #Tools:Pycharm 2017 ...

  2. python爬虫集合

    逐渐也写了有二十余篇博文,内容一多就导致有些内容不能够方便快捷定位. 虽然博客有标签进行分类,实际查找时也并不如做一个同类文章的集合来得直观. 这里就对python爬虫相关博文做个集合: 爬虫基础知识 ...

  3. nrf开发笔记一开发软件

    nrf52810 的开发环境,比较主流的可以使用keil,iar亦可.sdk中,使用的是pca10040e,s112.虽然开发板共用一个型号(pca10040) keil5中,cmsis 需要4.5. ...

  4. stm32启动地址

    理论上,CM3中规定上电后CPU是从0地址开始执行,但是这里中断向量表却被烧写在0x0800 0000地址里(Flash memory启动方式),那启动时不就找不到中断向量表了?既然CM3定下的规矩是 ...

  5. POJ:1185-炮兵阵地(状压dp入门)

    炮兵阵地 Time Limit: 2000MS Memory Limit: 65536K Description 司令部的将军们打算在N*M的网格地图上部署他们的炮兵部队.一个N*M的地图由N行M列组 ...

  6. JQuery根据字母检索元素并导航到指定位置

    介绍:类似于实现ios通讯录中右侧字母,快速导航到联系人的效果,如图: Html代码如下,分别是字母和港星名字的排序: <input type="text" id=" ...

  7. Python面试题(练习一)

    1.Python的可变类型和不可变类型? 可变类型:list.dict(列表和字典) 不可变类型:数字.字符串.元组 2.求结果: v = dict.fromkeys(['k1','k2'],[]) ...

  8. Python-函数参数的传递

    作者:Vamei 出处:http://www.cnblogs.com/vamei,感谢博主的分享, python的函数参数传递有这样的几种形式: 1.位置传递 2.关键字传递 3.参数默认值传递 4. ...

  9. activemq的安装启动

    Activemq安装和启动   官网:http://activemq.apache.org/   安装启动: $ tar -zxvf apache-activemq-5.11.1-bin.tar.gz ...

  10. Android中如何截取字符串中某个字符之前或之后的字符串

    代码改变世界 Android中如何截取字符串中某个字符之前或之后的字符串 //截取#之前的字符串 String str = "sdfs#d"; str.substring(0, s ...