4.8 Using Ambiguous Grammars

It is a fact that every ambiguous grammar fails to be LR and thus is not in any of the classes of grammars discussed in the previous two sections. However, certain types of ambiguous grammars are quite useful in the specification and implementation of languages. For language constructs like expressions, an ambiguous grammar provides a shorter, more natural specification than any equivalent unambiguous grammar. Another use of ambiguous grammars is in isolating commonly occurring syntactic constructs for special-case optimization. With an ambiguous grammar, we can specify the special-case constructs by carefully adding new productions to the grammar.

Although the grammars we use are ambiguous, in all cases we specify disambiguating rules that allow only one parse tree for each sentence. In this way, the overall language specification becomes unambiguous, and sometimes it becomes possible to design an LR parser that follows the same ambiguity-resolving choices. We stress that ambiguous constructs should be used sparingly and in a strictly controlled fashion, otherwise, there can be no guarantee as to what language is recognized by a parser.

4.8.1 Precedence and Associativity to Resolve Conflicts

Consider the ambiguous grammar (4.3) for expressions with operators + and *, repeated here for convenience:

E→E + E | E * E | (E) | id

This grammar is ambiguous because it does not specify the associativity or precedence of the operators + and *. The unambiguous grammar (4.1), which includes productions E→E + T and T→T * F, generates the same language, but gives + lower precedence than *, and makes both operators left associative.

There are two reasons why we might prefer to use the ambiguous grammar. First, as we shall see, we can easily change the associativity and precedence of the operators + and * without disturbing the productions of (4.3) or the number of states in the resulting parser. Second, the parser for the unambiguous grammar will spend a substantial fraction of its time reducing by the productions E→T and T→F, whose sole function is to enforce associativity and precedence. The parser for the ambiguous grammar (4.3) will not waste time reducing by these single productions (productions whose body consists of a single nonterminal).

The sets of LR(0) items for the ambiguous expression grammar (4.3) augmented by E 0→E are shown in Fig. 4.48. Since grammar (4.3) is ambiguous, there will be parsing-action conflicts when we try to produce an LR parsing table from the sets of items. The states corresponding to sets of items I7 and I8 generate these conflicts. Suppose we use the SLR approach to constructing the parsing action table. The conflict generated by I7 between reduction by E→E + E and shift on + or * cannot be resolved, because + and * are each in FOLLOW (E). Thus both actions would be called for on inputs + and *. A similar conflict is generated by I8, between reduction by E→E * E and shift on inputs + and *. In fact, each of our LR parsing table-construction methods will generate these conflicts.

However, these problems can be resolved using the precedence and associativity information for + and *. Consider the input id + id * id, which causes a parser based on Fig. 4.48 to enter state 7 after processing id + id, in particular the parser reaches a configuration

PREFIX

STACK

INPUT

E + E 0 1 4 7 * id $

For convenience, the symbols corresponding to the states 1, 4, and 7 are also shown under PREFIX.

If * takes precedence over +, we know the parser should shift * onto the stack, preparing to reduce the * and its surrounding id symbols to an expression.

This choice was made by the SLR parser of Fig. 4.37, based on an unambiguous grammar for the same language. On the other hand, if + takes precedence over *, we know the parser should reduce E + E to E. Thus the relative precedence

I0: E 0→*E I5: E→E **E

E→*E + E E→*E + E

E→*E * E E→*E * E

E→*(E) E→*(E)

E→*id E→*id

I1: E’→E * I6: E→(E*)

E→E * + E E→E * + E

E→E * * E E→E ** E

I2: E→(*E) I7: E→E + E *

E→*E + E E→E * + E

E→*E * E E→E ** E

E→*(E)

E→*id I8: E→E * E *

E→E * + E

I3: E→id* E→E ** E

I4: E→E + *E I9: E→(E)*

E→*E + E

E→*E * E

E→*(E)

E→*id

Figure 4.48: Sets of LR(0) items for an augmented expression grammar of + followed by * uniquely determines how the parsing action conflict between reducing E→E + E and shifting on * in state 7 should be resolved.

If the input had been id + id + id instead, the parser would still reach a configuration in which it had stack 0 1 4 7 after processing input id + id. On input + there is again a shift/reduce conflict in state 7. Now, however, the associativity of the + operator determines how this conflict should be resolved.

If + is left associative, the correct action is to reduce by E→E + E. That is, the id symbols surrounding the first + must be grouped first. Again this choice coincides with what the SLR parser for the unambiguous grammar would do.

In summary, assuming + is left associative, the action of state 7 on input + should be to reduce by E→E + E, and assuming that * takes precedence over +, the action of state 7 on input * should be to shift. Similarly, assuming that * is left associative and takes precedence over +, we can argue that state 8, which can app ear on top of the stack only when E * E are the top three grammar symbols, should have the action reduce E→E * E on both + and * inputs. In the case of input +, the reason is that * takes precedence over +, while in the case of input *, the rationale is that * is left associative. Proceeding in this way, we obtain the LR parsing table shown in Fig. 4.49. Productions 1 through 4 are E→E + E, E→E *, E→(E), and E → id, respectively. It is interesting that a similar parsing action table would be produced by eliminating the reductions by the single productions E→T and T→F from the SLR table for the unambiguous expression grammar (4.1) shown in Fig. 4.37. Ambiguous grammars like the one for expressions can be handled in a similar way in the context of LALR and canonical LR parsing.

STATE

ACTION GOTO

id + * ( ) $ E

0 s3 s2 1

1 s4 s5 acc

2 s3 s2 6

3 r4 r4 r4 r4

4 s3 s2 7

5 s3 s2 8

6 s4 s5 s9

7 r1 s5 r1 r1

8 r2 r2 r2 r2

9 r3 r3 r3 r3

Figure 4.49: Parsing table for grammar (4.3)

4.8.2 The “Dangling-Else” Ambiguity

Consider again the following grammar for conditional statements:

stmt→if expr then stmt else stmt

| if expr then stmt

| other

As we noted in Section 4.3.2, this grammar is ambiguous because it does not resolve the dangling-else ambiguity. To simplify the discussion, let us consider an abstraction of this grammar, where i stands for if expr then, e stands for else, and a stands for “all other productions.” We can then write the grammar, with augmenting production S’→S, as S’→S

S→i S e S | i S | a

(4.67)

The sets of LR(0) items for grammar (4.67) are shown in Fig. 4.50. The ambiguity in (4.67) gives rise to a shift/reduce conflict in I4. There, S→iS eS calls for a shift of e and, since FOLLOW (S) = {e, $}, item S→iS  calls for reduction

by S→iS on input e.

Translating back to the if-then-else terminology, given

I0: S’→S

S→iS eS

S→iS

S→a

I1: S’→S

I2: S→iS eS

S→iS

S→iS eS

S→iS

S→a

I3: S→a

I4: S→iS eS

I5: S→iS eS

S→iS eS

S→iS

S→a

I6: S→iS eS

Figure 4.50: LR(0) states for augmented grammar (4.67)

if expr then stmt

on the stack and else as the first input symbol, should we shift else onto the stack (i.e., shift e) or reduce if expr then stmt (i.e., reduce by S→iS )? The answer is that we should shift else, because it is “associated” with the previous then. In the terminology of grammar (4.67), the e on the input, standing for else, can only form part of the body beginning with the iS now on the top of the stack. If what follows e on the input cannot be parsed as an S, completing body iS eS , then it can be shown that there is no other parse possible.

We conclude that the shift/reduce conflict in I 4 should be resolved in favor of shift on input e. The SLR parsing table constructed from the sets of items of Fig. 4.50, using this resolution of the parsing-action conflict in I4 on input e, is shown in Fig. 4.51. Productions 1 through 3 are S→iS eS, S→iS, and S→a, respectively.

STATE

ACTION GOTO

i e a $ S

0 s2 s3 1

1 acc

2 s2 s3 4

3 r3 r3

4 s5 r2

5 s2 s3 6

6 r1 r1

Figure 4.51: LR parsing table for the \dangling-else" grammar

For example, on input iiaea, the parser makes the moves shown in Fig. 4.52, corresponding to the correct resolution of the “dangling-else.” At line (5), state 4 selects the shift action on input e, whereas at line (9), state 4 calls for reduction by S→iS on input $.

STACK SYMBOLS INPUT ACTION

(1) 0 i i a e a $ shift

(2) 0 2 i i a e a $ shift

(3) 0 2 2 i i a e a $ shift

(4) 0 2 2 3 i i a e a $ shift

(5) 0 2 2 4 i i S e a $ reduce by S→a

(6) 0 2 2 4 5 i i S e a $ shift

(7) 0 2 2 4 5 3 i i S e a $ reduce by S→a

(8) 0 2 2 4 5 6 i i S e S $ reduce by S→iS eS

(9) 0 2 4 i S $ reduce by S→iS

(10) 0 1 S $ accept

Figure 4.52: Parsing actions on input iiaea

By way of comparison, if we are unable to use an ambiguous grammar to specify conditional statements, then we would have to use a bulkier grammar along the lines of Example 4.16.

4.8.3 Error Recovery in LR Parsing

An LR parser will detect an error when it consults the parsing action table and finds an error entry. Errors are never detected by consulting the goto table. An LR parser will announce an error as soon as there is no valid continuation for the portion of the input thus far scanned. A canonical LR parser will not make even a single reduction before announcing an error. SLR and LALR parsers may make several reductions before announcing an error, but they will never shift an erroneous input symbol onto the stack.

In LR parsing, we can implement panic-mode error recovery as follows. We scan down the stack until a states with a goto on a particular nonterminal A is found. Zero or more input symbols are then discarded until a symbol a is found that can legitimately follow A. The parser then stacks the state GOTO(s, A) and resumes normal parsing. There might be more than one choice for the nonterminal A. Normally these would be nonterminals representing major program pieces, such as an expression, statement, or block. For example, if A is the nonterminal stmt, a might be semicolon or g, which marks the end of a statement sequence.

This method of recovery attempts to eliminate the phrase containing the syntactic error. The parser determines that a string derivable from A contains an error. Part of that string has already been processed, and the result of this processing is a sequence of states on top of the stack. The remainder of the string is still in the input, and the parser attempts to skip over the remainder of this string by looking for a symbol on the input that can legitimately follow A. By removing states from the stack, skipping over the input, and pushing GOTO(s, A) on the stack, the parser pretends that it has found an instance of A and resumes normal parsing.

Phrase-level recovery is implemented by examining each error entry in the LR parsing table and deciding on the basis of language usage the most likely programmer error that would give rise to that error. An appropriate recovery procedure can then be constructed, presumably the top of the stack and/or first input symbols would be modified in a way deemed appropriate for each error entry.

In designing specific error-handling routines for an LR parser, we can ll in each blank entry in the action field with a pointer to an error routine that will take the appropriate action selected by the compiler designer. The actions may include insertion or deletion of symbols from the stack or the input or both, or alteration and transposition of input symbols. We must make our choices so that the LR parser will not get into an in finite loop. A safe strategy will assure that at least one input symbol will be removed or shifted eventually, or that the stack will eventually shrink if the end of the input has been reached.

Popping a stack state that covers a nonterminal should be avoided, because this modification eliminates from the stack a construct that has already been successfully parsed.

Example 4.68: Consider again the expression grammar

E→E + E | E * E | (E) | id

Figure 4.53 shows the LR parsing table from Fig. 4.49 for this grammar, modified for error detection and recovery. We have changed each state that calls for a particular reduction on some input symbols by replacing error entries in that state by the reduction. This change has the erect of postponing the error detection until one or more reductions are made, but the error will still be caught before any shift move takes place. The remaining blank entries from Fig. 4.49 have been replaced by calls to error routines.

The error routines are as follows.

e1: This routine is called from states 0, 2, 4 and 5, all of which expect the beginning of an operand, either an id or a left parenthesis. Instead, +, * or the end of the input was found.

push state 3 (the goto of states 0, 2, 4 and 5 on id),

issue diagnostic “missing operand.”

e2: Called from states 0, 1, 2, 4 and 5 on finding a right parenthesis.

remove the right parenthesis from the input,

issue diagnostic “unbalanced right parenthesis.”

STATE

ACTION GOTO

id + * ( ) $ E

0 s3 e1 e1 s2 e2 e1 1

1 e3 s4 s5 e3 e2 acc

2 s3 e1 e1 s2 e2 e1 6

3 r4 r4 r4 r4 r4 r4

4 s3 e1 e1 s2 e2 e1 7

5 s3 e1 e1 s2 e2 e1 8

6 e3 s4 s5 e3 s9 e4

7 r1 r1 s5 r1 r1 r1

8 r2 r2 r2 r2 r2 r2

9 r3 r3 r3 r3 r3 r3

Figure 4.53: LR parsing table with error routines

e3: Called from states 1 or 6 when expecting an operator, and an id or right parenthesis is found.

push state 4 (corresponding to symbol +) onto the stack, issue diagnostic “missing operator.”

e4: Called from state 6 when the end of the input is found.

push state 9 (for a right parenthesis) onto the stack, issue diagnostic “missing right parenthesis.”

On the erroneous input id + ), the sequence of configurations entered by the parser is shown in Fig. 4.54.

4.8 Using Ambiguous Grammars的更多相关文章

  1. 4.2 Context-Free Grammars

    4.2 Context-Free Grammars Grammars were introduced in Section 2.2 to systematically describe the syn ...

  2. [Erlang 0105] Erlang Resources 小站 2013年1月~6月资讯合集

    很多事情要做,一件一件来; Erlang Resources 小站 2013年1月~6月资讯合集,方便检索.      小站地址: http://site.douban.com/204209/     ...

  3. 4.9 Parser Generators

    4.9 Parser Generators This section shows how a parser generator can be used to facilitate the constr ...

  4. Qt5.3编译错误——call of overloaded ‘max(int int)’is ambiguous

    错误描述: 今天在使用Qt写一个C++函数模板的测试程序的时候,编译的时候,编译的时候出现如下错误: 错误描述为:在main函数中,进行函数max()重载时,出现(ambiguous)含糊的,不明确的 ...

  5. 解决ambiguous symbol命名空间中类名、变量名冲突的问题

    最近在将一个复杂的工程集成到现有的项目中.编译时发现,有的变量名冲突了,提示就是xxxx ambiguous symbol,并且在编译输出时,指明了两个文件当中特定的变量名或者类名相同.出现这个编译错 ...

  6. column 'id' in field list is ambiguous

    column 'id' in field list is ambiguous  这个错误,是因为你查询语句里面有id字段的时候,没有说明是哪个表的id字段,应该加上表名(或者别名)来区分.

  7. FbxDataType is ambiguous

    ??? 使用fbx自定义的类型的时候,比如 FbxIntDT 会有link error 根本原因是 FbxDataType is ambiguous solution: 把fbx的lib换成 libf ...

  8. 函数重载二义性:error C2668: 'pow' : ambiguous call to overloaded function

    2013-07-08 14:42:45 当使用的函数时重载函数时,若编译器不能判断出是哪个函数,就会出现二义性,并给出报错信息. 问题描述: 在.cpp代码中用到pow函数,如下: long int ...

  9. Ambiguous mapping found. Cannot map 'xxxxController' bean method

    1.背景 今天要做一个demo,从github上clone一个springmvc mybatis的工程(https://github.com/komamitsu/Spring-MVC-sample-u ...

随机推荐

  1. Nginx出现403 forbidden (13: Permission denied)报错的四种原因

    一.由于php-fpm启动用户和nginx工作用户不一致所致 php-fpm启动用户配置位置 nginx工作用户配置位置 二.不存在在文件,可能是文件路径有误,可以查看nginx错误日志来判断 三.缺 ...

  2. Python之trutle库-五角星

    Python之trutle库-五角星 #!/usr/bin/env python # coding: utf-8 # Python turtle库官方文档:https://docs.python.or ...

  3. Jbox 弹出窗口 子页面操作完成后关闭 父页面刷新

    父页面js //父页面js <script> var isFreshFlag = '1'; //添加会议活动 function addMeetingAct(){ var attendVip ...

  4. Atcoder regular Contest 073(C - Sentou)

    Atcoder regular Contest 073(C - Sentou) 传送门 每个人对开关的影响区间为a[i]--a[i]+t,因此此题即为将所有区间离散化后求所有独立区间的长度和 #inc ...

  5. Unity3D 固定功能函数

    Unity 3D 测试固定功能函数执行顺序 1. 在GameObject和脚本激活状态下,测试: 2. 在GameObject激活状态下,测试: 3. 在2种情况都不激活的状态下测试:脚本无输出: 函 ...

  6. Python文件处理(txt、csv文件读取)

    打开文件 使用Python内置的方法 open()可以打开文件 file object = open(file_name [, access_mode][, buffering]) file_name ...

  7. 计算1+2+...+100之和<for循环的学习>

    #include <stdio.h> /* 计算1+2+....+100 soulsjie 20170525 */ void main(){ int i; int s=0; for(i=0 ...

  8. hihoCoder#1048 状态压缩·二

    原题地址 位运算的状态压缩太操蛋了,很容易出错...又是数组没开够导致诡异现象(明明某个值是1,莫名其妙就变成0了),害我debug一整天!fuck 代码: #include <iostream ...

  9. Redis 命令与连接【十一】

    ---------------------Redis 命令--------------- Redis 命令用于在 redis 服务上执行操作. 要在 redis 服务上执行命令需要一个 redis 客 ...

  10. IntentService用于服务中开启子线程的自动关闭

    package com.pingyijinren.test; import android.app.IntentService; import android.content.Intent; impo ...