用PYTHON实现将电脑里的所有文件按大小排序，便于清理

嘿嘿，慢慢找到写代码的感觉了。

这个小程序涉及的东东还是很多的，数据结构的设计，错误的处理，快速字典排序，文件数值调整。。。。

import os,os.path
import glob
 
SUFFIXES = ['KB', 'MB', 'GB', 'TB', 'PB', 'EB', 'ZB', 'YB']
 
def approximate_size(size):
    '''Convert a file size to human-readable form.
 
    Keyword arguments:
    size -- file size in bytes
 
    Returns: string
 
    '''
    if size < 0:
        raise ValueError('number must be non-negative')
 
    multiple = 1024.0
    for suffix in SUFFIXES:
        size /= multiple
        if size < multiple:
            return '{0:.1f} {1}'.format(size, suffix)
 
rootDir = raw_input('Please input root dir:')
count = 0
fileDict = {}
sortfileDict = {}
for parent, dirnames, filenames in os.walk(rootDir):
    #print('Folder: %s' % dirName)
    for filename in filenames:
        name = os.path.join(parent,filename)
        try:
            filesize = os.path.getsize(name)
        except (OSError):
            filesize = 0
        fileDict[name] = filesize
        count += 1
        print count
 
sortfileDict = sorted(fileDict.iteritems(), key=lambda fileDict:fileDict[1], reverse = True)
 
fList = open('filelist.txt','w')
for i in range(len(sortfileDict)):
    #print sortfileDict[i][0], "\t", sortfileDict[i][1]
    fileList = "{0} \t {1} \n".format(sortfileDict[i][0], approximate_size(sortfileDict[i][1]))
    fList.write(fileList)
 
fList.close()
 
print 'DONE'