最近整理的一些行列转换sql(有自己的，有别人的)，留作记录

--case when 经典用法
SELECT * FROM
       (SELECT 1 NUM,
              '奖项金额',
              SUM(CASE WHEN DJMC= '一等奖' AND CGBZ=0 THEN DJJE ELSE 0 END) ,
              SUM(CASE WHEN DJMC= '二等奖' AND CGBZ=0 THEN DJJE ELSE 0 END) ,
              SUM(CASE WHEN DJMC= '三等奖' AND CGBZ=0 THEN DJJE ELSE 0 END) ,
              SUM(CASE WHEN DJMC= '四等奖' AND CGBZ=0 THEN DJJE ELSE 0 END) ,
              SUM(CASE WHEN DJMC= '五等奖' AND CGBZ=0 THEN DJJE ELSE 0 END) ,  
              SUM(CASE WHEN DJMC= '一等奖' AND CGBZ=1 THEN DJJE ELSE 0 END) ,
              SUM(CASE WHEN DJMC= '二等奖' AND CGBZ=1 THEN DJJE ELSE 0 END) ,
              SUM(CASE WHEN DJMC= '三等奖' AND CGBZ=1 THEN DJJE ELSE 0 END) ,
              SUM(CASE WHEN DJMC= '四等奖' AND CGBZ=1 THEN DJJE ELSE 0 END) ,
              SUM(CASE WHEN DJMC= '五等奖' AND CGBZ=1 THEN DJJE ELSE 0 END)    
        FROM XXDZMX T  WHERE DZYF=20111129 AND ZFLX=0
        UNION ALL
       SELECT 2 NUM,
              '奖项数量',
              SUM(CASE WHEN DJMC= '一等奖' AND CGBZ=0 THEN 1 ELSE 0 END),
              SUM(CASE WHEN DJMC= '二等奖' AND CGBZ=0 THEN 1 ELSE 0 END),
              SUM(CASE WHEN DJMC= '三等奖' AND CGBZ=0 THEN 1 ELSE 0 END),
              SUM(CASE WHEN DJMC= '四等奖' AND CGBZ=0 THEN 1 ELSE 0 END),
              SUM(CASE WHEN DJMC= '五等奖' AND CGBZ=0 THEN 1 ELSE 0 END),
              SUM(CASE WHEN DJMC= '一等奖' AND CGBZ=1 THEN 1 ELSE 0 END),
              SUM(CASE WHEN DJMC= '二等奖' AND CGBZ=1 THEN 1 ELSE 0 END),
              SUM(CASE WHEN DJMC= '三等奖' AND CGBZ=1 THEN 1 ELSE 0 END),
              SUM(CASE WHEN DJMC= '四等奖' AND CGBZ=1 THEN 1 ELSE 0 END),
              SUM(CASE WHEN DJMC= '五等奖' AND CGBZ=1 THEN 1 ELSE 0 END)      
        FROM XXDZMX T WHERE DZYF=20111129 AND ZFLX=0
        ) ORDER BY NUM;

--结果如下：
-- 1 奖项金额  0 50  10  0 2   200 0   10  5  2
-- 2 奖项数量  0 1   1   0 1    1  0    1  1  1

--初始数据如下：
SELECT ZJJX, SUM(CGSL), SUM(CGJEH), SUM(SBSL), SUM(SBJEH)
  FROM (
  SELECT ZJJX,  COUNT(ZJJE) CGSL, SUM(ZJJE) CGJEH,  0 SBSL,  0 SBJEH   FROM YW_ZJFPJL  where substr(to_char(zjsj, 'yyyy-mm-dd hh24:mi:ss'), 0, 7) =  '2016-10'     GROUP BY ZJJX
        UNION ALL
   SELECT ZJJX,  0 CGSL,  0 CGJEH,  COUNT(ZJJE) SBSL, SUM(ZJJE) SBJEH FROM YW_FJCWJL  where substr(to_char(zjsj, 'yyyy-mm-dd hh24:mi:ss'), 0, 7) = '2016-10'  GROUP BY ZJJX)
 GROUP BY ZJJX;

/*
 一等奖 1 200 0 0
 三等奖 16  160 5 50
 四等奖 28  140 23  115
 五等奖 52  104 33  66
*/

--以下sql完成的哦

--奖项金额完成的
SELECT *
  FROM (SELECT '奖项金额(成功)',
               SUM(CASE  WHEN ZJJX = '一等奖' THEN SUM(ZJJE) ELSE  0 END) 一等奖成功金额,
               SUM(CASE  WHEN ZJJX = '二等奖' THEN SUM(ZJJE) ELSE  0 END) 二等奖成功金额,
               SUM(CASE  WHEN ZJJX = '三等奖' THEN SUM(ZJJE) ELSE  0 END) 三等奖成功金额,
               SUM(CASE  WHEN ZJJX = '四等奖' THEN SUM(ZJJE) ELSE  0 END) 四等奖成功金额,
               SUM(CASE  WHEN ZJJX = '五等奖' THEN SUM(ZJJE) ELSE  0 END) 五等奖成功金额
         FROM YW_ZJFPJL T   WHERE to_char(zjsj,'yyyymmdd')='20161017' GROUP BY ZJJX),
       (SELECT '奖项金额(失败)',
               SUM(CASE  WHEN ZJJX = '一等奖' THEN SUM(ZJJE)  ELSE  0  END) 一等奖失败金额,
               SUM(CASE  WHEN ZJJX = '二等奖' THEN SUM(ZJJE)  ELSE  0  END) 二等奖失败金额,
               SUM(CASE  WHEN ZJJX = '三等奖' THEN SUM(ZJJE)  ELSE  0  END) 三等奖失败金额,
               SUM(CASE  WHEN ZJJX = '四等奖' THEN SUM(ZJJE)  ELSE  0  END) 四等奖失败金额,
               SUM(CASE  WHEN ZJJX = '五等奖' THEN SUM(ZJJE)  ELSE  0  END) 五等奖失败金额        
          FROM YW_FJCWJL T WHERE to_char(zjsj,'yyyymmdd')='20161017'
         GROUP BY ZJJX);         
--输出结果： 1 奖项金额(成功)  200 0 160 140 104 奖项金额(失败)  0 0 50  115 66

                        
--奖项数量完成的
SELECT * FROM
(SELECT '奖项数量(成功)',
                SUM(CASE WHEN ZJJX = '一等奖' THEN COUNT(ZJJE)  ELSE  0  END) 一等奖成功数量,
                SUM(CASE WHEN ZJJX = '二等奖' THEN COUNT(ZJJE)  ELSE  0  END) 二等奖成功数量,
                SUM(CASE WHEN ZJJX = '三等奖' THEN COUNT(ZJJE)  ELSE  0  END) 三等奖成功数量,
                SUM(CASE WHEN ZJJX = '四等奖' THEN COUNT(ZJJE)  ELSE  0  END) 四等奖成功数量,
                SUM(CASE WHEN ZJJX = '五等奖' THEN COUNT(ZJJE)  ELSE  0  END) 五等奖成功数量
 FROM YW_ZJFPJL T  WHERE to_char(zjsj,'yyyymmdd')='20161017'  GROUP BY ZJJX),
(SELECT  '奖项数量(失败)',  
               SUM(CASE  WHEN ZJJX = '一等奖' THEN  COUNT(ZJJE)  ELSE  0  END) 一等奖失败数量,
               SUM(CASE  WHEN ZJJX = '二等奖' THEN  COUNT(ZJJE)  ELSE  0  END) 二等奖失败数量,
               SUM(CASE  WHEN ZJJX = '三等奖' THEN  COUNT(ZJJE)  ELSE  0  END) 三等奖失败数量,
               SUM(CASE  WHEN ZJJX = '四等奖' THEN  COUNT(ZJJE)  ELSE  0  END) 四等奖失败数量,
               SUM(CASE  WHEN ZJJX = '五等奖' THEN  COUNT(ZJJE)  ELSE  0  END) 五等奖失败数量
        
  FROM YW_FJCWJL T  WHERE to_char(zjsj,'yyyymmdd')='20161017'
         GROUP BY ZJJX);         
--输出结果： 奖项数量(成功)  1 0 16  28  52  奖项数量(失败)  0 0 5 23  33