aaarticlea/png;base64,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" alt="" />

 public boolean hasCycle(ListNode head) {
ListNode s=head;
ListNode f=head;
while(f!=null&&f.next!=null){
s=s.next;
f=f.next.next;
if(s==f){
return true;
}
}
return false; }

leetcode--009 Linked List Cycle I的更多相关文章

  1. 【Leetcode】Linked List Cycle II

    Given a linked list, return the node where the cycle begins. If there is no cycle, return null. Foll ...

  2. [LeetCode] 141. Linked List Cycle 链表中的环

    Given a linked list, determine if it has a cycle in it. Follow up:Can you solve it without using ext ...

  3. [LeetCode] 142. Linked List Cycle II 链表中的环 II

    Given a linked list, return the node where the cycle begins. If there is no cycle, return null. Foll ...

  4. Java for LeetCode 142 Linked List Cycle II

    Given a linked list, return the node where the cycle begins. If there is no cycle, return null. Foll ...

  5. 【算法分析】如何理解快慢指针?判断linked list中是否有环、找到环的起始节点位置。以Leetcode 141. Linked List Cycle, 142. Linked List Cycle II 为例Python实现

    引入 快慢指针经常用于链表(linked list)中环(Cycle)相关的问题.LeetCode中对应题目分别是: 141. Linked List Cycle 判断linked list中是否有环 ...

  6. [Leetcode Week6]Linked List Cycle II

    Linked List Cycle II 题解 题目来源:https://leetcode.com/problems/linked-list-cycle-ii/description/ Descrip ...

  7. [Leetcode Week6]Linked List Cycle

    Linked List Cycle 题解 原创文章,拒绝转载 题目来源:https://leetcode.com/problems/linked-list-cycle/description/ Des ...

  8. [LeetCode] 142. Linked List Cycle II 单链表中的环之二

    Given a linked list, return the node where the cycle begins. If there is no cycle, return null. To r ...

  9. [LeetCode] 141. Linked List Cycle 单链表中的环

    Given a linked list, determine if it has a cycle in it. To represent a cycle in the given linked lis ...

  10. 【题解】【链表】【Leetcode】Linked List Cycle II

    Given a linked list, return the node where the cycle begins. If there is no cycle, return null. Foll ...

随机推荐

  1. GameUnity 2.0 发布倒计时

    万众期待的 gameunity 网络游戏框架 已经完成了,现在在最后的检验调试阶段. 因为版本 改动非常之大,所以 版本号 从0.2版本 改成 2.0版本. gameunity事件部分,一如既往保持高 ...

  2. Linux环境下Android JNI程序的编译

    尊重原创作者,转载请注明出处: http://blog.csdn.net/gemmem/article/details/8993493 在android开发中,有时候需要编写一些C/C++代码,这时候 ...

  3. POJ 1061 青蛙的约会(欧几里得扩展)

    题意:已知青蛙1位置x,速度m,青蛙2位置y,速度n,纬线长度为l,求他们相遇时最少跳跃次数. 思路:设最小跳跃次数为k,则(x + k*m) - (y + k*n) = q*l:经过整理得到k*(n ...

  4. FTP 7.5 自定义扩展功能

    @import url(http://i.cnblogs.com/Load.ashx?type=style&file=SyntaxHighlighter.css);@import url(/c ...

  5. asp读取指定目录下的文件名

    bianli(Server.MapPath("/")+"\pic") InStrRev("abcd.jpg", ".") ...

  6. 使用nginx简单实现负载均衡

    只是简单使用nginx玩玩而已,知道能这么用,但是在实际项目中并没有实践过,在项目不大的时候用不到,但是对于理解负载均衡来说还是可以的. 利用虚拟机安装了三个centOS系统,然后顺便装了环境. 这里 ...

  7. CSS样式覆盖规则

    有一下问题, 想让下面的border生效 ,#比. 优先级高, #navigator { height: 100%; width: 200; position: absolute; left: 0; ...

  8. Servlet程序开发--取得初始化配置信息

    代码: 两个初始化init方法,一起出现的话,有参的才起作用 package org.lxh.servletdemo ; import java.io.* ; import javax.servlet ...

  9. HTTP 中 POST和GET的区别

    1.传送数据的方式不一样 get是将数据队列添加到URL中提交,用户可以看到(对URL反编码就行) post是将数据队列放到HTTP的报文的报头中提交,用户看不到所提交的数据: 2.服务器端获取变量的 ...

  10. 2016大连网络赛 Function

    Function Time Limit: 7000/3500 MS (Java/Others)    Memory Limit: 262144/262144 K (Java/Others) Probl ...