Bone Collector

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 52296    Accepted Submission(s): 22040

Problem Description

Many years ago , in Teddy’s hometown there was a man who was called “Bone Collector”. This man like to collect varies of bones , such as dog’s , cow’s , also he went to the grave …
The bone collector had a big bag with a volume of V ,and along his trip of collecting there are a lot of bones , obviously , different bone has different value and different volume, now given the each bone’s value along his trip , can you calculate out the maximum of the total value the bone collector can get ?
 

Input

The first line contain a integer T , the number of cases.
Followed by T cases , each case three lines , the first line contain two integer N , V, (N <= 1000 , V <= 1000 )representing the number of bones and the volume of his bag. And the second line contain N integers representing the value of each bone. The third line contain N integers representing the volume of each bone.
 

Output

One integer per line representing the maximum of the total value (this number will be less than 231).
 

Sample Input

1
5 10
1 2 3 4 5
5 4 3 2 1
 

Sample Output

14
 
裸的01背包
 //2016.9.6
#include <iostream>
#include <cstdio>
#include <cstring> using namespace std; const int N = ;
int dp[N], c[N], w[N]; int main()
{
int T, n, v;
cin>>T;
while(T--)
{
scanf("%d%d", &n, &v);
memset(dp, , sizeof(dp));
for(int i = ; i < n; i++)
scanf("%d", &w[i]);
for(int i = ; i < n; i++)
scanf("%d", &c[i]);
for(int i = ; i < n; i++)
for(int j = v; j >= c[i]; j--)
dp[j] = max(dp[j], dp[j-c[i]]+w[i]);
printf("%d\n", dp[v]);
} return ;
}

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