hdu-5651 xiaoxin juju needs help(数学+gcd约分求阶乘)
题目链接:
xiaoxin juju needs help
Time Limit: 2000/1000 MS (Java/Others)
Memory Limit: 65536/65536 K (Java/Others)
Total Submission(s): 491 Accepted Submission(s): 142
This summer he was working at Tencent as an intern. One day his leader came to ask xiaoxin for help. His leader gave him a string and he wanted xiaoxin to generate palindromic strings for him. Once xiaoxin generates a different palindromic string, his leader will give him a watermelon candy. The problem is how many candies xiaoxin's leader needs to buy?
For each test case, there is a single line containing a string S(1≤length(S)≤1,000).
#include <iostream>
#include <cstdio>
#include <queue>
#include <cstring>
#include <algorithm>
using namespace std;
const int mod=1e9+;
char str[];
int a[],b[];
int gcd(int x,int y)
{
if(y==)return x;
return gcd(y,x%y);
}
queue<int>qu;
int main()
{
int t;
scanf("%d",&t);
while(t--)
{
while(!qu.empty())qu.pop();
memset(a,,sizeof(a));
scanf("%s",str);
int len=strlen(str);
for(int i=;i<len;i++)
{
a[str[i]-'a']++;
}
int flag=;
long long ans=;
for(int i=;i<;i++)
{
if(a[i]%)
{
flag++;
}
a[i]=a[i]/;
}
for(int i=;i<=len/;i++)
{
b[i]=(long long)i;
}
//memset(vis,0,sizeof(vis));
for(int i=;i<;i++)
{
if(a[i]>)
{
for(int j=;j<=a[i];j++)
{
qu.push(j);
}
}
}
while(!qu.empty())
{
int x=qu.front();
qu.pop();
for(int i=;i<=len/;i++)
{
if(b[i]%x==)
{
b[i]/=x;
break;
}
else
{
int y=gcd(b[i],x);
if(y>)
{
b[i]/=y;
x/=y;
if(x>)qu.push(x);
break;
}
}
} }
for(int j=;j<=len/;j++)
{
ans*=(long long)b[j];
ans%=mod;
}
if(flag>)cout<<""<<"\n";
else cout<<ans<<"\n"; } return ;
}
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