hdu 5154 Harry and Magical Computer
题目连接
http://acm.hdu.edu.cn/showproblem.php?pid=5154
Harry and Magical Computer
Description
In reward of being yearly outstanding magic student, Harry gets a magical computer. When the computer begins to deal with a process, it will work until the ending of the processes. One day the computer got n processes to deal with. We number the processes from 1 to n. However there are some dependencies between some processes. When there exists a dependencies (a, b), it means process b must be finished before process a. By knowing all the m dependencies, Harry wants to know if the computer can finish all the n processes.
Input
There are several test cases, you should process to the end of file.
For each test case, there are two numbers n m on the first line, indicates the number processes and the number of dependencies. $1 \leq n \leq 100,1 \leq m \leq 10000$
The next following m lines, each line contains two numbers a b, indicates a dependencies $(a, b). 1 \leq a, b \leq n$
Output
Output one line for each test case.
If the computer can finish all the process print "YES" (Without quotes).
Else print "NO" (Without quotes).
Sample Input
3 2
3 1
2 1
3 3
3 2
2 1
1 3
Sample Output
YES
NO
先建立一张有向图,再遍历,若有顶点未访问到输出"NO",否则输出"YES"。。。
#include<algorithm>
#include<iostream>
#include<cstdlib>
#include<cstring>
#include<cstdio>
#include<vector>
#include<queue>
#include<map>
using std::cin;
using std::cout;
using std::endl;
using std::find;
using std::sort;
using std::pair;
using std::vector;
using std::queue;
using std::multimap;
#define pb(e) push_back(e)
#define sz(c) (int)(c).size()
#define mp(a, b) make_pair(a, b)
#define all(c) (c).begin(), (c).end()
#define iter(c) decltype((c).begin())
#define cls(arr,val) memset(arr,val,sizeof(arr))
#define cpresent(c, e) (find(all(c), (e)) != (c).end())
#define rep(i, n) for (int i = 0; i < (int)(n); i++)
#define tr(c, i) for (iter(c) i = (c).begin(); i != (c).end(); ++i)
const int N = ;
int n, m, G[N][N];
bool vis[N], flag[N];
typedef unsigned long long ull;
void bfs() {
bool f = false;
queue<int> que;
rep(i, n) {
if (!flag[i]) {
vis[i] = true;
que.push(i);
}
}
while (!que.empty()) {
int p = que.front(); que.pop();
rep(i, n) {
if (G[p][i]) {
if (vis[i]) continue;
que.push(i);
vis[i] = true;
}
}
}
rep(i, n) {
if (!vis[i]) { f = true; break; }
}
puts(f ? "NO" : "YES");
}
int main() {
#ifdef LOCAL
freopen("in.txt", "r", stdin);
freopen("out.txt", "w+", stdout);
#endif
int a, b;
while (~scanf("%d %d", &n, &m)) {
cls(vis, ), cls(flag, ), cls(G, );
rep(i, m) {
scanf("%d %d", &a, &b);
G[b - ][a - ] = ;
flag[a - ] = ;
}
bfs();
}
return ;
}
hdu 5154 Harry and Magical Computer的更多相关文章
- hdu 5154 Harry and Magical Computer 拓扑排序
Harry and Magical Computer Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Ja ...
- (简单) HDU 5154 Harry and Magical Computer,图论。
Description In reward of being yearly outstanding magic student, Harry gets a magical computer. When ...
- HDU 5154 Harry and Magical Computer bfs
Harry and Magical Computer Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Ja ...
- HDU 5154 Harry and Magical Computer 有向图判环
题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=5154 题解: 有向图判环. 1.用dfs,正在访问的节点标记为-1,已经访问过的节点标记为1,没有访 ...
- 【HDOJ】5154 Harry and Magical Computer
拓扑排序. /* 5154 */ #include <iostream> #include <cstdio> #include <cstring> #include ...
- BC Harry and Magical Computer (拓扑排序)
Harry and Magical Computer Accepts: 350 Submissions: 1348 Time Limit: 2000/1000 MS (Java/Others) ...
- hdu 5154 拓扑排序
例题:hdu 5154 链接 http://acm.hdu.edu.cn/showproblem.php?pid=5154 题目意思是第一行先给出n和m表示有n件事,m个关系,接下来输入m行,每行有 ...
- BestCoder25 1001.Harry and Magical Computer(hdu 5154) 解题报告
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=5154 题目意思:有 n 门 processes(编号依次为1,2,...,n),然后给出 m 种关系: ...
- HDU5154拓扑排序
Harry and Magical Computer Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Ja ...
随机推荐
- PERT(计划评审技术,Program Evaluation an Review Technique)
如果你对项目管理.系统架构有兴趣,请加微信订阅号"softjg",加入这个PM.架构师的大家庭 PERT(计划评审技术,Program Evaluation an Review T ...
- LICEcap GIF 屏幕录制工具
LICEcap 是一款屏幕录制工具,支持导出git动画图片格式,简单好用.大小只有几百KB 运行之后,可以随意调整大小,右下角有开始/停止按钮. 压缩包:http://files.cnb ...
- 洛谷P2722 总分 Score Inflation
P2722 总分 Score Inflation 184通过 295提交 题目提供者该用户不存在 标签USACO 难度普及- 提交 讨论 题解 最新讨论 关于算法 题目背景 学生在我们USACO的 ...
- iOS 国际化
1.在APPproject的新建一个Localizable.strings File->new file--->Resource --->strings File 2.添加需要的语言 ...
- 错误处理php
一 HP关闭脚本错误提示的方法: 打开PHP安装目录下的php.ini文件 找到display_errors = On 修改为 display_errors = off 注意:如果你已经把PHP.in ...
- sotower1.5报错 -Xlint:unchecked
新建sotower项目 控制台启动正常,登录页面报错 StandardWrapperValve[jsp]: Servlet.service() for servlet jsp threw except ...
- Nginx 下无法读取session 导致 thinkphp验证码错误
打开php配置文件 php.ini 使用搜索命令 whereis php.ini 一般在:/etc/php.ini 目录下 使用vim命令打开 找到: session.save_path 找到php保 ...
- s3c6410_uboot中的代码重定位(nand->sdram)
本文仅探讨s3c6410从nand flash启动u-boot时的代码重定位过程 参考: 1)<USER'S MANUAL-S3C6410X>第二章 MEMORY MAP 第八章 NAND ...
- cpack
一. 简介 CPack是CMake 2.4.2之后的一个内置工具,主要作用就是生成制定类型的安装包.它可以脱离cmake单独运行. 二. 基本设置 (mandatory) 设置包类型set(CPACK ...
- Windows系统错误代码大全
1 Microsoft Windows 系统错误代码简单分析: 0000 操作已成功完成.0001 错误的函数. 0002 系统找不到指定的文件. 0003 系统找不到指定的路径. 0004 系统无法 ...