Educational Codeforces Round 76 (Rated for Div. 2) B. Magic Stick 水题
B. Magic Stick
Recently Petya walked in the forest and found a magic stick.
Since Petya really likes numbers, the first thing he learned was spells for changing numbers. So far, he knows only two spells that can be applied to a positive integer:
If the chosen number
Educational Codeforces Round 76 (Rated for Div. 2) B. Magic Stick 水题的更多相关文章
- Educational Codeforces Round 76 (Rated for Div. 2) C. Dominated Subarray 水题
C. Dominated Subarray Let's call an array
- Educational Codeforces Round 76 (Rated for Div. 2) B. Magic Stick
Recently Petya walked in the forest and found a magic stick. Since Petya really likes numbers, the f ...
- Educational Codeforces Round 69 (Rated for Div. 2) C. Array Splitting 水题
C. Array Splitting You are given a sorted array
- Educational Codeforces Round 76 (Rated for Div. 2) E. The Contest
Educational Codeforces Round 76 (Rated for Div. 2) E. The Contest(dp+线段树) 题目链接 题意: 给定3个人互不相同的多个数字,可以 ...
- Educational Codeforces Round 60 (Rated for Div. 2) - C. Magic Ship
Problem Educational Codeforces Round 60 (Rated for Div. 2) - C. Magic Ship Time Limit: 2000 mSec P ...
- Educational Codeforces Round 60 (Rated for Div. 2) - D. Magic Gems(动态规划+矩阵快速幂)
Problem Educational Codeforces Round 60 (Rated for Div. 2) - D. Magic Gems Time Limit: 3000 mSec P ...
- Educational Codeforces Round 71 (Rated for Div. 2)-E. XOR Guessing-交互题
Educational Codeforces Round 71 (Rated for Div. 2)-E. XOR Guessing-交互题 [Problem Description] 总共两次询 ...
- Educational Codeforces Round 76 (Rated for Div. 2)E(dp||贪心||题解写法)
题:https://codeforces.com/contest/1257/problem/E 题意:给定3个数组,可行操作:每个数都可以跳到另外俩个数组中去,实行多步操作后使三个数组拼接起来形成升序 ...
- Educational Codeforces Round 76 (Rated for Div. 2)
传送门 A. Two Rival Students 签到. Code /* * Author: heyuhhh * Created Time: 2019/11/13 22:37:26 */ #incl ...
随机推荐
- 用js传递当前页面的url,丢失了&后面的参数 解决办法
问题:因为登陆是用ajax传值的,在哪个页面点击登陆的,登陆成功跳到再跳回那个页面,之前直接传递的是 /index_do.php?gourl=" +location.href这样传递的,但是 ...
- redis5.0.0功能介绍以及主从集群、哨兵搭建
这两天突然想起redis,索性就再尝试一下搭建最新版本的redis,过程有点艰辛呀,记录一下,供自己和大家今后搭建做参考. 一.为什么用Redis? 我自己总结了一下: 1.基于内存实现的key-va ...
- day97_11_29
一.数据存储到mongodb 爬取的数据如果需要存储到mongodb中,要通过item,定义一个存储类.再yield一个类. 数据存储的时候需要进过pipelines,再到setting中配置. fr ...
- C# detect latest .net framework installed on PC
static void GetNetVersionDemo() { using (RegistryKey ndpKey = RegistryKey.OpenBaseKey(RegistryHive.L ...
- (转)isolation forest进行异常点检测
原文链接:https://www.cnblogs.com/gczr/p/9156971.html 一.简介 孤立森林(Isolation Forest)是另外一种高效的异常检测算法,它和随机森林类似, ...
- Add an Editor to a Detail View 将编辑器添加到详细信息视图
In this lesson, you will learn how to add an editor to a Detail View. For this purpose, the Departme ...
- git操作教程
首先就是创建码云(用户名不能是中文),然后新建一个项目(用户名/项目名都不能是中文). 一.在Windows上安装Git 1.从http://msysgit.github.io下载,然后按默认选项安装 ...
- 图像几何变换之平移(Matlab)
G=imread('aini555.jpg'); A=rgb2gray(G); se=translate(strel(),[,]); B=imdilate(A,se); figure; subplot ...
- Pycharm2019最新激活注册码(pycharm激活教程)
给大家分享一下PyCharm2019最新可用的激活注册码.激活Pycharm专业版的方法有很多,这里主要给大家分享最有效的两种,一种是使用最新可用的注册激活码,一种是使用破解补丁的方法,这种方法虽然麻 ...
- PC/SC双界面读写器开发指南
友我科技PCSC双界面读写器YW-606开发指南 1.建立资源管理器的上下文 函数ScardEstablishContext()用于建立将在其中进行设备数据库操作的资源管理器上下文(范围). 函数原型 ...