Base-64字符串无效,The input is not a valid Base-64 string as it contains a non-base 64 character
base64规则:
* 字符串只可能包含A-Z,a-z,0-9,+,/,=字符
* 字符串长度是4的倍数
* =只会出现在字符串最后,可能没有或者一个等号或者两个等号
首先,C# 做上传文件的时候,需要替换掉这些字符:
data:image/jpeg;base64,
data:image/png;base64,
data:image/gif;base64,
if (str.Contains("base64,"))
{
str = str.Split("base64,")[];
}
如果还存在错误的话,可以进行一些字符替换试试:
var imgData = "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";
//过滤特殊字符即可
string dummyData = imgData.Trim().Replace("%", "").Replace(",", "").Replace(" ", "+");byte[] byteArray = Convert.FromBase64String(dummyData);
上面两步操作完了还没有解决问题的话,可以调试看看base64字符串的长度,如果长度不是4的倍数,比如8057或者8041,可以尝试截掉最后一个字符,使字符长度变为4的倍数。(能正常解决bug,但不确定是否会产生其他问题)
str = str.Substring(, str.Length - );
上面两个长度其实是本人调试的时候遇到的,神奇的是,复制粘贴后就会变成8056长度,可以正常解析。如果有大佬知道是怎么回事的话,欢迎评论沟通。
Base-64字符串无效,The input is not a valid Base-64 string as it contains a non-base 64 character的更多相关文章
- winform错误提示 :窗口类名无效(Window class name is not valid)
winfrom 程序在 xp 操作系统上报错提示 窗口类名无效(Window class name is not valid) 解决方法 注释 Program类 里 这句 Application.En ...
- git是一种分布式代码管理工具,git通过树的形式记录文件的更改历史,比如: base'<--base<--A<--A' ^ | --- B<--B' 小米工程师常常需要寻找两个分支最近的分割点,即base.假设git 树是多叉树,请实现一个算法,计算git树上任意两点的最近分割点。 (假设git树节点数为n,用邻接矩阵的形式表示git树:字符串数组matrix包含n个字符串,每个字符串由字符'0
// ConsoleApplication10.cpp : 定义控制台应用程序的入口点. // #include "stdafx.h" #include <iostream& ...
- [Swift]LeetCode434. 字符串中的单词数 | Number of Segments in a String
Count the number of segments in a string, where a segment is defined to be a contiguous sequence of ...
- [Swift]LeetCode806. 写字符串需要的行数 | Number of Lines To Write String
We are to write the letters of a given string S, from left to right into lines. Each line has maximu ...
- [Swift]LeetCode833. 字符串中的查找与替换 | Find And Replace in String
To some string S, we will perform some replacement operations that replace groups of letters with ne ...
- 循环遍历Java字符串字符的规范方法——类似python for ch in string
比如我将string作为CNN 文本处理输入: float [] input = new float[maxLength]; // 1 sentence by maxLenWords // int[] ...
- C#LeetCode刷题之#557-反转字符串中的单词 III(Reverse Words in a String III)
问题 该文章的最新版本已迁移至个人博客[比特飞],单击链接 https://www.byteflying.com/archives/3955 访问. 给定一个字符串,你需要反转字符串中每个单词的字符顺 ...
- C#LeetCode刷题之#345-反转字符串中的元音字母(Reverse Vowels of a String)
问题 该文章的最新版本已迁移至个人博客[比特飞],单击链接 https://www.byteflying.com/archives/3935 访问. 编写一个函数,以字符串作为输入,反转该字符串中的元 ...
- 字符串中判断存在的几种模式和效率(string.contains、string.IndexOf、Regex.Match)
通常情况下,我们判断一个字符串中是否存在某值常常会用string.contains,其实判断一个字符串中存在某值的方法有很多种,最常用的就是前述所说的string.contains,相对来说比较常用的 ...
随机推荐
- React-Router4 按需加载的4种实现
其实几种实现都是近似的,但具体上不太一样,其中有些不需要用到bundle-loader 第一种:ReactTraining/react-router 介绍的基于 webpack, babel-plug ...
- Spring+Struts2+Hibernate框架搭建
SSH框架版本:Struts-2.3.30 + Spring-4.2.2 + Hibernate5.2.2 下图是所需要的Jar包: 下面是项目的结构图: 1.web.xml <?xml ...
- MySQL用户、库、表(单/多)操作
用户及权限操作: 管理员登录:mysql -uroot -p 用户设置密码:set password=password(密码); 查看数据库所有用户:select * from mysql.user; ...
- mysql 查询获取排名的方法(绝对有效)
http://blog.csdn.net/k8080880/article/details/11253305 select case when pid=0 then case when @prevTy ...
- 王艳 201771010127《面向对象程序设计(java)》第十六周学习总结
一:理论部分 1.程序:是一段静态的代码,它是应用程序执行的蓝本. 2.进程:是程序的一次动态执行,它对应了从代码加载.执行至执行完毕的一个完整过程. 3.多线程:是进程执行过程中产生的多条执行线索. ...
- Fabric CA的部署与使用
Fabric CA是Hyperledger Fbric的证书认证中心,提供以下功能:用户信息的登记与注册,数字证书的颁发与管理. 前言 之前使用CA服务一直是在docker容器中运行下载好的CA镜像, ...
- Gunicorn+Nginx+Flask项目部署
安装python3.6 1)前往用户根目录 >: cd ~ 2)下载 或 上传 Python3.6.7 >: wget https://www.python.org/ftp/python/ ...
- DEDE自增序号 自动增加数字序号 autoindex属性
在DEDE的模板制作过程中经常会需要用到1,2,3,4....这样的排序方式,这个时候就需要用到DEDE自带的自增序号产生函数 1.按顺序从1开始 需要使用到 [field:global runphp ...
- PHP数组简单操作
1.数字索引数组 1.1创建一个数组 php中最常用的两个类型是:数组,字符串.数组也分为两种,一种是数字索引,一种是关键是索引,关键字索引有点像python中字典的意思.数字索引类型的数组的创建方法 ...
- (板子)缩点 + DAG上的DP(深搜)luogu P3387
板子传送门 根据题目意思,我们只需要找出一条点权最大的路径就行了,不限制点的个数.那么考虑对于一个环上的点被选择了,一整条环是不是应该都被选择,这一定很优,能选干嘛不选.很关键的是题目还允许我们重复经 ...