SQL

LINQ

Lambda

SELECT *

FROM HumanResources.Employee

from e in Employees

select e

Employees
   .Select (e => e)

SELECT e.LoginID, e.JobTitle

FROM HumanResources.Employee AS e

from e in Employees

select new {e.LoginID, e.JobTitle}

Employees
   .Select (
      e =>
         new
         {
            LoginID = e.LoginID,
            JobTitle = e.JobTitle
         }
   )

SELECT e.LoginID AS ID, e.JobTitle AS Title

FROM HumanResources.Employee AS e

from e in Employees

select new {ID = e.LoginID, Title = e.JobTitle}

Employees
   .Select (
      e =>
         new
         {
            ID = e.LoginID,
            Title = e.JobTitle
         }
   )

SELECT DISTINCT e.JobTitle

FROM HumanResources.Employee AS e

(from e in Employees

select e.JobTitle).Distinct()

Employees
   .Select (e => e.JobTitle)
   .Distinct ()

SELECT e.*

FROM HumanResources.Employee AS e

WHERE e.LoginID = 'test'

from e in Employees

where e.LoginID == "test"

select e

Employees
   .Where (e => (e.LoginID == "test"))

SELECT e.*

FROM HumanResources.Employee AS e

WHERE e.LoginID = 'test' AND e.SalariedFlag = 1

from e in Employees

where e.LoginID == "test" && e.SalariedFlag

select e

Employees
   .Where (e => ((e.LoginID == "test") && e.SalariedFlag))

SELECT e.*
FROM HumanResources.Employee AS e

WHERE e.VacationHours >= 2 AND e.VacationHours <= 10

from e in Employees

where e.VacationHours >= 2 && e.VacationHours <= 10

select e

Employees
   .Where (e => (((Int32)(e.VacationHours) >= 2) && ((Int32)(e.VacationHours) <= 10)))

SELECT e.*

FROM HumanResources.Employee AS e
ORDER BY e.NationalIDNumber

from e in Employees

orderby e.NationalIDNumber

select e

Employees
   .OrderBy (e => e.NationalIDNumber)

SELECT e.*

FROM HumanResources.Employee AS e

ORDER BY e.HireDate DESC, e.NationalIDNumber

from e in Employees

orderby e.HireDate descending, e.NationalIDNumber

select e

Employees
   .OrderByDescending (e => e.HireDate)
   .ThenBy (e => e.NationalIDNumber)

SELECT e.*
FROM HumanResources.Employee AS e

WHERE e.JobTitle LIKE 'Vice%' OR SUBSTRING(e.JobTitle, 0, 3) = 'Pro'

from e in Employees

where e.JobTitle.StartsWith("Vice") || e.JobTitle.Substring(0, 3) == "Pro"

select e

Employees
   .Where (e => (e.JobTitle.StartsWith ("Vice") || (e.JobTitle.Substring (0, 3) == "Pro")))

SELECT SUM(e.VacationHours)

FROM HumanResources.Employee AS e

Employees.Sum(e => e.VacationHours);

SELECT COUNT(*)

FROM HumanResources.Employee AS e

Employees.Count();

SELECT SUM(e.VacationHours) AS TotalVacations, e.JobTitle

FROM HumanResources.Employee AS e

GROUP BY e.JobTitle

from e in Employees

group e by e.JobTitle into g

select new {JobTitle = g.Key, TotalVacations = g.Sum(e => e.VacationHours)}

Employees
   .GroupBy (e => e.JobTitle)
   .Select (
      g =>
         new
         {
            JobTitle = g.Key,
            TotalVacations = g.Sum (e => (Int32)(e.VacationHours))
         }
   )

SELECT e.JobTitle, SUM(e.VacationHours) AS TotalVacations

FROM HumanResources.Employee AS e

GROUP BY e.JobTitle

HAVING e.COUNT(*) > 2

from e in Employees

group e by e.JobTitle into g

where g.Count() > 2

select new {JobTitle = g.Key, TotalVacations = g.Sum(e => e.VacationHours)}

Employees
   .GroupBy (e => e.JobTitle)
   .Where (g => (g.Count () > 2))
   .Select (
      g =>
         new
         {
            JobTitle = g.Key,
            TotalVacations = g.Sum (e => (Int32)(e.VacationHours))
         }
   )

SELECT *

FROM Production.Product AS p, Production.ProductReview AS pr

from p in Products

from pr in ProductReviews

select new {p, pr}

Products
   .SelectMany (
      p => ProductReviews,
      (p, pr) =>
         new
         {
            p = p,
            pr = pr
         }
   )

SELECT *

FROM Production.Product AS p

INNER JOIN Production.ProductReview AS pr ON p.ProductID = pr.ProductID

from p in Products

join pr in ProductReviews on p.ProductID equals pr.ProductID

select new {p, pr}

Products
   .Join (
      ProductReviews,
      p => p.ProductID,
      pr => pr.ProductID,
      (p, pr) =>
         new
         {
            p = p,
            pr = pr
         }
   )

SELECT *

FROM Production.Product AS p

INNER JOIN Production.ProductCostHistory AS pch ON p.ProductID = pch.ProductID AND p.SellStartDate = pch.StartDate

from p in Products

join
pch in ProductCostHistories on new {p.ProductID, StartDate =
p.SellStartDate} equals new {pch.ProductID, StartDate = pch.StartDate}

select new {p, pch}

Products
   .Join (
      ProductCostHistories,
      p =>
         new
         {
            ProductID = p.ProductID,
            StartDate = p.SellStartDate
         },
      pch =>
         new
         {
            ProductID = pch.ProductID,
            StartDate = pch.StartDate
         },
      (p, pch) =>
         new
         {
            p = p,
            pch = pch
         }
   )

SELECT *

FROM Production.Product AS p

LEFT OUTER JOIN Production.ProductReview AS pr ON p.ProductID = pr.ProductID

from p in Products

join pr in ProductReviews on p.ProductID equals pr.ProductID

into prodrev

select new {p, prodrev}

Products
   .GroupJoin (
      ProductReviews,
      p => p.ProductID,
      pr => pr.ProductID,
      (p, prodrev) =>
         new
         {
            p = p,
            prodrev = prodrev
         }
   )

SELECT p.ProductID AS ID

FROM Production.Product AS p

UNION

SELECT pr.ProductReviewID

FROM Production.ProductReview AS pr

(from p in Products

select new {ID = p.ProductID}).Union(

from pr in ProductReviews

select new {ID = pr.ProductReviewID})

Products
   .Select (
      p =>
         new
         {
            ID = p.ProductID
         }
   )
   .Union (
      ProductReviews
         .Select (
            pr =>
               new
               {
                  ID = pr.ProductReviewID
               }
         )
   )

SELECT TOP (10) *

FROM Production.Product AS p

WHERE p.StandardCost < 100

(from p in Products

where p.StandardCost < 100

select p).Take(10)

Products
   .Where (p => (p.StandardCost < 100))
   .Take (10)

SELECT *

FROM [Production].[Product] AS p

WHERE p.ProductID IN(

SELECT pr.ProductID

FROM [Production].[ProductReview] AS [pr]

WHERE pr.[Rating] = 5

)

from p in Products

where (from pr in ProductReviews

where pr.Rating == 5

select pr.ProductID).Contains(p.ProductID)

select p

Products
   .Where (
      p =>
         ProductReviews
            .Where (pr => (pr.Rating == 5))
            .Select (pr => pr.ProductID)
            .Contains (p.ProductID)
   )

SQL/LINQ/Lamda的更多相关文章

  1. SQL/LINQ/Lamda 写法[转发]

    SQL LINQ Lambda SELECT * FROM HumanResources.Employee from e in Employees select e Employees   .Sele ...

  2. SQL Linq lamda区别

    SQL LINQ Lambda SELECT * FROM HumanResources.Employee from e in Employees select e Employees   .Sele ...

  3. SQL,LINQ,Lambda语法对照图(转载)

    如果你熟悉SQL语句,当使用LINQ时,会有似曾相识的感觉.但又略有不同.下面是SQL和LINQ,Lambda语法对照图 SQL LINQ Lambda SELECT * FROM HumanReso ...

  4. SQL,Linq,Lambda之间的转换练习

    1.查询Student表中的所有记录的Sname.Ssex和Class列. SQL:select sname,ssex,class from Students linq:from s in Stude ...

  5. LINQ / LINQ to SQL / LINQ to XXX 它们到底有什么区别

    LINQ是新生事物,不过从不少文章和讨论上看来,这方面的概念也已经有点混沌不清了.因此我们经常可以看到这样的话: LINQ只能将数据表与实体属性一一对应…… LINQ开发指南:在LINQ中进行数据库字 ...

  6. SQL&&LINQ:左(外)连接,右(外)连接,内连接,完全连接,交叉连接,多对多连接

    SQL: 外连接和内连接: 左连接或左外连接:包含左边的表的所有行,如果右边表中的某行没有匹配,该行内容为空(NULL) --outer jion:left join or left outer jo ...

  7. Linq lamda表达式Single和First方法

      让我们来看看如何对一个整数数组使用 Single 操作符.这个整数数组的每个元素代表 2 的 1 到 10 次方.先创建此数组,然后使用 Single 操作符来检索满足 Linq Lambda表达 ...

  8. sql linq lambda 对比

    . 查询Student表中的所有记录的Sname.Ssex和Class列. select sname,ssex,class from student Linq: from s in Students ...

  9. linq lamda

    var query6 = CustomerList.SelectMany(c => c.Orders);var query6= from c in CustomerList            ...

随机推荐

  1. 我的Android第三章:Android的组件介绍

    小编摘录了Android文档介绍Android四大组件的基本内容,感觉文档的内容写的很详细所以小编将它写入了博客 Android 使用Java语言开发.Android SDK 工具编译代码-以及任意数 ...

  2. OC NSFileManager(文件路径操作)

    OC NSFileManager(文件路径操作) 初始化 NSFileManager * fm = [NSFileManager defaultManager]; 获取当前目录 [fm current ...

  3. art.dialog 返回提示

    <form  target="_top"  /> 1 如果加   target="_top" 提示跳出子页面 2 如果不加则在子页面提示

  4. mac 终端 常用指令

    开始正式研究ios 应用开发,由于是从C开始学起,所以学习下常用的mac终端指令,方便后续常用操作. mac 终端 常用指令: 1.ls指令 用途:列出文件 常用参数 -w 以简洁的形式列出所有文件和 ...

  5. 安全攻防之SQL注入(通过sqlmap搞定所有问题)

    第一步: sqlmap基于Python,所以首先下载: http://yunpan.cn/QiCBLZtGGTa7U  访问密码 c26e 第二步: 安装Python,将sqlmap解压到Python ...

  6. 区别和详解:js中call()和apply()的用法

    1.关于call()和apply()的疑点: apply和call的区别在哪里 什么情况下用apply,什么情况下用call apply的其他巧妙用法(一般在什么情况下可以使用apply) 2.语法和 ...

  7. openstack数据库获取一个虚机的floating_ip, fix_ip, project_name, user_name, hostname, host

     转载请注明 http://www.cnblogs.com/juandx/p/5418204.html openstack有3个库,nova,neutron,keystone,我现在需要做的是跨库联表 ...

  8. JavaScript(七)——视频插入

    代码: <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3. ...

  9. sql server 基础教程[温故而知新三]

    子曰:“温故而知新,可以为师矣.”孔子说:“温习旧知识从而得知新的理解与体会,凭借这一点就可以成为老师了.“ 尤其是咱们搞程序的人,不管是不是全栈工程师,都是集十八般武艺于一身.不过有时候有些知识如果 ...

  10. 问题解决——开启Guest后仍无法共享打印机

    ==================================声明================================== 本文版权归作者所有 未经作者授权 请勿转载 保留法律追究的 ...