A + B Problem II

I have a very simple problem for you. Given two integers A and B, your job is to calculate the Sum of A + B.

Input

The first line of the input contains an integer T(1<=T<=20) which means the number of test cases. Then T lines follow, each line consists of two positive integers, A and B. Notice that the integers are very large, that means you should not process them by using 32-bit integer. You may assume the length of each integer will not exceed 1000.

Output

For each test case, you should output two lines. The first line is "Case #:", # means the number of the test case. The second line is the an equation "A + B = Sum", Sum means the result of A + B. Note there are some spaces int the equation. Output a blank line between two test cases.

Sample Input

2
1 2
112233445566778899 998877665544332211

Sample Output

Case 1:
1 + 2 = 3 Case 2:
112233445566778899 + 998877665544332211 = 1111111111111111110

代码:

import java.io.BufferedInputStream;
import java.math.BigInteger;
import java.util.Scanner; public class Main { public static void main(String[] args) {
// TODO 自动生成的方法存根
Scanner str = new Scanner(System.in);
int T;
T=str.nextInt();
int i=1; for(i=1;i<=T;i++)
{
BigInteger a=str.nextBigInteger();
BigInteger b=str.nextBigInteger();
System.out.println("Case "+i+":");
System.out.println(a+" + "+b+" = "+a.add(b));
if(i<T)
{
System.out.println("");
} } } }

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