按键精灵手机版多点找色,图片对比 by <剑行洪荒> 忠哥
代码:
Do
Dim ret1,ret2
Delay 500
ret1 = CmpColor(76,72, "153274", 0.9)
ret2 = CmpColor(81,574, "CCEFFF", 0.9)
If ret1 > -1 and ret2 > -1 Then
Tap 72, 92
Delay 300
Tap 73,608
Exit Do
End If
Loop
代码:
Do
FindPic 0,0,1080,1920, "Attachment:k确定.png", "000000", 0, 0.9, intX, intY
If intX > -1 And intY > -1 Then
Delay 300
Tap 97, 631
Exit Do
End If
Loop
代码:
RunApp "com.wanmei.xom.uc" 启动UC客户端
killApp "com.wanmei.xom.uc"关闭UC客户端
KeyPress "Back”
KeyPress "Del"
Swipe 251, 940, 251, 840
Exit for
Rem A3 标记 A3
Goto A3 跳转到 A3
代码:
//定义全局变量
Dim a,intX,intY,dx1,dx2,dx3,dx4,dx5,dx6,dx7,dx8,dx9,dx10
dx1= ReadUIConfig("dx1", "") //是否早上6点开始
If dx1=true then
Do
a = DateTime.Hour()
Delay 1000
If a = 6 Then
Exit Do
Else
If a > 6 and a < 12 Then
Exit Do
End If
End If
Loop
End If
代码:
//已点击到账号
Sub 输入958()
Delay 300
InputText "589611958"
Delay 500
Tap 357, 677
Delay 200
InputText "19911031"
Delay 300
KeyPress "Enter"End Sub
代码:
//复杂情况下排错的多重应用(多对一关系)
Sub 刷装备普4()
Do
//扫荡
// Dim intX, intY
FindPic 182, 659, 105, 839, "Attachment:扫荡.png", "000000", 0, 0.9, intX, intY
If intX > -1 And intY > -1 Then
Tap 146,747
End If//开始
FindPic 179, 584, 117, 675, "Attachment:开始.png", "000000", 0, 0.9, intX, intY
If intX > -1 And intY > -1 Then
Tap 149,642
End If
//元宝不足
FindPic 186, 554, 126, 720, "Attachment:充值.png", "000000", 0, 0.9, intX, intY
If intX > -1 And intY > -1 Then
Delay 300
Tap 567,998
Delay 500
goto A1
End If
//确定FindPic 376, 483, 311, 608, "Attachment:确定.png", "000000", 0, 0.9, intX, intY
If intX > -1 And intY > -1 Then
Tap 263, 640
Delay 500
Goto A1
End If
//包满
FindPic 444, 424, 358, 721, "Attachment:包满.png", "000000", 0, 0.9, intX, intY
If intX > -1 And intY > -1 Then
Tap 262, 640
Delay 500
Goto A1
End If//是
ret1 = CmpColor(261,480, "0F3059", 0.9)
ret2 = CmpColor(264,743, "103162", 0.9)
If ret1 > -1 and ret2 > -1 Then
Tap 261,480
End If//退出循环
ret1 = CmpColor(265,621, "BEECF9", 0.9)
ret2 = CmpColor(427,559, "111A23", 0.9)
If ret1 > -1 and ret2 > -1 Then
Tap 265, 621
Delay 500
Tap 593, 927
Delay 200
Exit Do
End ifLoop
Rem A1
//关闭 副本
Do
//取消
ret1 = CmpColor(266,748, "C0DDEF", 0.9)
ret2 = CmpColor(266,795, "D3F0FE", 0.9)
If ret1 > -1 and ret2 > -1 Then
Tap 266, 748End If
//关闭背包
ret1 = CmpColor(432,850, "43D1D5", 0.9)
ret2 = CmpColor(432,1012, "3CD0DA", 0.9)
If ret1 > -1 and ret2 > -1 Then
Tap 681,1134End If
ret1 = CmpColor(679,1112, "1B4374", 0.9)
ret2 = CmpColor(679,1135, "507CAA", 0.9)
If ret1 > -1 and ret2 > -1 Then
Delay 200
Tap 679, 1112
Delay 200
Exit Do
End If
LoopEnd Sub
代码:
//是否中,do loop结构确是一定的处理
//是否第二章精英
do
Delay 700
ret1 = CmpColor(681,296, "000000", 0.9)
ret2 = CmpColor(690,296, "010202", 0.9)
ret3= CmpColor(548,237, "0A0AF1", 0.9)
If ret1 > -1 and ret2 > -1 and ret3 > -1 Then
Exit Do
Else
Swipe 410, 1051, 410, 800
End If
Loop
代码:
//艺术就是代码 by忠哥
Sub 小交易()
Dim ret1,ret2,intX, intY
Rem j2
//交易
Do
Delay 500
//点开交易
ret1 = CmpColor(537,1056, "151840", 0.9)
ret2 = CmpColor(531,1050, "0F133E", 0.9)
If ret1 > -1 and ret2 > -1 Then
Tap 521, 1049
Delay 500
Tap 262, 504
End If
//是 否交易
// FindPic 445,423, 365,573, "Attachment:八.png", "000000", 0, 0.9, intX, intY
// If intX > -1 And intY > -1 Then
// Tap 262, 504
// Else
// ret1 = CmpColor(265,742, "113263", 0.9)
// ret2 = CmpColor(260,772, "CEEBFA", 0.9)
// If ret1 > -1 and ret2 > -1 Then
// Tap 265,772
// End If
// End If
FindPic 705,597, 667,674, "Attachment:交易.png", "000000", 0, 0.9, intX, intY
If intX > -1 And intY > -1 Then
Exit Do
End If
Loop
//交易装备
Delay 500
ret1 = CmpColor(550,863, "3E6590", 0.9)
ret2 = CmpColor(546, 900, "3E6590", 0.9)
If ret1 > -1 and ret2 > -1 Then
Tap 681,1131
Goto A3
End If
Dim x,y
x = 547
For 2
y=880
For 3
Delay 500
Tap x, y
Delay 500
ret1 = CmpColor(77,520, "CEEBFA", 0.9)
ret2 = CmpColor(73,489, "07214C", 0.9)
If ret1 > -1 and ret2 > -1 Then
Tap 77,520
End If
y=y+111
Next
x=x-111
Next
delay 300
Tap 54, 896
Delay 100
Do
ret1 = CmpColor(57,1039, "0D2E5F", 0.9)
ret2 = CmpColor(60,1114, "05264F", 0.9)
If ret1 > -1 and ret2 > -1 Then
Tap 57, 1039
Exit Do
End If
Loop
Do
ret1 = CmpColor(537,1056, "151840", 0.9)
ret2 = CmpColor(531,1050, "0F133E", 0.9)
If ret1 > -1 and ret2 > -1 Then
Goto j2
End If
LoopRem A3
End Sub
代码:
//相对于上面多重多对一,if嵌套能不用尽量不用吧,呃我觉得。只有当必须要搞的时候,才去嵌套。正常情况下,游戏逻辑是不可逆的。所以流水线般运作的程序完全不必担心.
Sub 刷装备4()
Do
Dim ret1,ret2
ret1 = CmpColor(185,1130, "C8E0FF", 0.9)
ret2 = CmpColor(191,1125, "B3C8D8", 0.9)
If ret1 > -1 and ret2 > -1 Then
Tap 199,1133
Exit Do
End If
Loop
Delay 500
Tap 205, 1134
Do
Delay 700
ret1 = CmpColor(682,278, "010203", 0.9)
ret2 = CmpColor(678,285, "000101", 0.9)
If ret1 > -1 and ret2 > -1 Then
Exit Do
Else
Swipe 520, 990, 520, 900
End If
LoopDim x,y
x = 463
y=376
For 3
rem g1
Delay 300Tap x, y
Delay 300
Tap 147, 757
Delay 500
ret1 = CmpColor(261,631, "C1EFFB", 0.9)
ret2 = CmpColor(357,505, "D10102", 0.9)
If ret1 - 1 and ret2 > -1 Then
Tap 261, 631
Delay 500
Tap 375,936
delay 300
Tap 367, 661
Delay 300
Tap 246, 509
Delay 300
Tap 677, 1131
Exit for
End If
Do
delay 300
Tap 138, 640
Delay 300
Tap 265, 501
Delay 500
ret1 = CmpColor(261,631, "C1EFFB", 0.9)
ret2 = CmpColor(422,559, "000000", 0.9)
If ret1 - 1 and ret2 > -1 Then
Tap 261, 631
Delay 500
ret1 = CmpColor(592,927, "15213F", 0.9)
ret2 = CmpColor(589,932, "111A37", 0.9)
If ret1 - 1 and ret2 > -1 Then
Tap 589,932
End If
Exit Do
End Ifret1 = CmpColor(261,631, "C1EFFB", 0.9)
ret2 = CmpColor(357,505, "D10102", 0.9)
If ret1 - 1 and ret2 > -1 Then
Tap 261, 631
Delay 500
Tap 375,936
delay 300
Tap 367, 661
Delay 300
Tap 246, 509
Delay 300
Tap 677, 1131
Delay 300
Tap 594,929
Exit Do
End If
//武器不刷
ret1 = CmpColor(296,1005, "C8B1BD", 0.9)
ret2 = CmpColor(345,1025, "47262E", 0.9)
If ret1 > -1 and ret2 > -1 Then
Tap 627, 1079
Delay 200
goto g1
End IfLoop
x=x-110
Next
x = 463
y=902
For 3
rem g2
Delay 300Tap x, y
Delay 300
Tap 147, 757
Delay 500
ret1 = CmpColor(261,631, "C1EFFB", 0.9)
ret2 = CmpColor(357,505, "D10102", 0.9)
If ret1 - 1 and ret2 > -1 Then
Tap 261, 631
Delay 500
Tap 375,936
delay 300
Tap 367, 661
Delay 300
Tap 246, 509
Delay 300
Tap 677, 1131
Exit for
End If
Do
delay 300
Tap 138, 640
Delay 300
Tap 265, 501
Delay 500
ret1 = CmpColor(261,631, "C1EFFB", 0.9)
ret2 = CmpColor(422,559, "000000", 0.9)
If ret1 - 1 and ret2 > -1 Then
Tap 261, 631
Delay 500
ret1 = CmpColor(592,927, "15213F", 0.9)
ret2 = CmpColor(589,932, "111A37", 0.9)
If ret1 - 1 and ret2 > -1 Then
Tap 589,932
End If
Exit Do
End Ifret1 = CmpColor(261,631, "C1EFFB", 0.9)
ret2 = CmpColor(357,505, "D10102", 0.9)
If ret1 - 1 and ret2 > -1 Then
Tap 261, 631
Delay 500
Tap 375,936
delay 300
Tap 367, 661
Delay 300
Tap 246, 509
Delay 300
Tap 677, 1131
Delay 300
Tap 594,929
Exit Do
End If
//武器不刷
ret1 = CmpColor(296,1005, "C8B1BD", 0.9)
ret2 = CmpColor(345,1025, "47262E", 0.9)
If ret1 > -1 and ret2 > -1 Then
Tap 627, 1079
Delay 200
goto g2
End IfLoop
x=x-110
NextDelay 500
ret1 = CmpColor(682,1125, "111A37", 0.9)
ret2 = CmpColor(677,1130, "111A37", 0.9)
If ret1 - 1 and ret2 > -1 Then
Tap 680, 1131
End If
End Sub
按键精灵手机版多点找色,图片对比 by <剑行洪荒> 忠哥的更多相关文章
- 按键精灵安卓版 tap、touch命令 不好用的解决办法!
用按键精灵手机版写脚本来操作新浪微博APP,在关注列表页自动取消关注,代码如下: If x > -1 And y > -1 Then delay 1000 tap x,y delay 10 ...
- 第六篇T语言实例开发,多点找色应用
---恢复内容开始--- 多点找色应用 文字,图形特征的获取 多点找色 功能原型 窗口多点找色(窗口句柄,x1,y1,x2,y2,颜色值,色点组,相似度,方向,返回x,返回y) 功能说明 根据指定的多 ...
- 按键精灵PC版<末日王者>
更新模式[强制] 更新版本[1.28] 更新链接[https://yunfei-1256035889.cos.ap-beijing.myqcloud.com/%E6%9C%AB%E6%97%A5%E4 ...
- 【按键精灵篇】如何做一个自动打开APP进入注册页面自动输入自己手机号
按键精灵,虽然很早听过,但是一直没有真正使用过,所以最近有点时间也简单试一下,通过脚本自动清理APP缓存,打开百家号并自动进入注册页面输入自己的手机号. 软件清单 1. 雷电手机模拟器:https:/ ...
- 按键精灵对APP自动化测试(上)
简单介绍下应用背景:测试安卓app时发现重复点击某一按钮的时候会出现报错,开发修复后提交测试.如果采用手动点击按钮,效率不高,在领导提示下使用按键精灵实现自动操作. 一. 安卓手机按键精灵 ...
- 按键精灵与逍遥安卓ADB连接重键方法
1.按键精灵与逍遥安卓ADB连接安装按键精灵与逍遥安卓这两个软件我不用多说了.安装好后把逍遥安卓安装目录下的三个文件adb.exe,AdbWinApi.dll,AdbWinUsbApi.dll 全部复 ...
- C#实现按键精灵的'找图' '找色' '找字'的功能
http://www.cnblogs.com/JimmyBright/p/4355862.html 背景:游戏辅助功能通常使用按键精灵编写脚本,按键精灵的最大卖点就是能够找到画面中字,图,色,这对于模 ...
- 原来找字也可以这样用ElseIf FindStr 手机按键精灵 跟大漠的区别
原来找字也可以这样用ElseIf FindStr(646, 1109, 776, 1261, "公告小叉", "FFFFFF-333333", 0.9, in ...
- 自己开发iOS版按键精灵--TTouch
利用闲余时间,把之前的按键录制和播放整理了一些,开发了一个iOS版按键录制.播放的越狱APP,类似按键精灵.触动精灵等按键类的基本功能.脚本采用lua语法格式,可直接执行lua脚本,通过lua和obj ...
随机推荐
- Test checkout of feature 'Compiler' failed 解决方法(转载)
Test checkout of feature 'Compiler' failed. 2014a的解决办法 适用于已安装compiler但破解不完全的, ht—tp://pan.baidu.co ...
- September 25th 2017 Week 39th Monday
No man is rich enough to buy back his own past. 没有人富有到可以赎回自己的过去. Those rich are not willing to buy b ...
- November 22nd 2016 Week 48th Tuesday
Eventually, you will learn to cry on the inside. 终有一天,你得学会让眼泪在心里流. Cry on the inside. I am tired, an ...
- [BZOJ 4031][LOJ 2122][HEOI 2015] 小Z的房间
[BZOJ 4031][LOJ 2122][HEOI 2015] 小Z的房间 题意 给定一个 \(n\times m\) 的矩阵, 一些格子是障碍, 相邻的格子(四联通)之间可以连边, 求把非障碍的格 ...
- 2018 - 2019 CTU Open Contest H. Split Game 【SG函数】
H. Split Game time limit per test 1.0 s memory limit per test 256 MB input standard input output sta ...
- Burpsuite-Intruder基础学习(一)
上周吧,将公司的短信及邮箱服务测试了一遍,就学习了Burpsuite的Intruder.(自学成才,还好网上有资料,入手还是挺简单的) 网上资料:https://www.gitbook.com/boo ...
- R执行报错:Error in `[<-.ts`(`*tmp*`,...only replacement of elements is allowed
原因: pred$mean是Time-Series类型,rbind函数不支持.通过as.double将其转换成double类型即可. 修改前代码: all_predata_time <- dat ...
- 关于iframe的父页面调取子页面里的事件(父往子里传)
在body里打开一个iframe页面,想要调取打开的这个页面里的函数: $('iframe')[0].contentWindow.sonFn(canshu); [0]:比如在index.html页面里 ...
- ASP.NET Razor引入命名空间(视图中数据序列化)
问题描述: 视图有时可以作为保存数据的载体,使用Razor语法给我们带来便捷的同时,也会使我们陷入局限.@可以保存int.bool.string等类型,但却保存不了对象类型,例如Dictionary. ...
- git 代码分支合并merge提交新修改远程以及本地分支
第一步:创建本地分支 点击右键选择TortoiseGit,选择Create Branch…,在Branch框中填写新分支的名称(若选中”switch to new branch”则直接转到新分支上,省 ...