hdoj1004--Let the Balloon Rise
This year, they decide to leave this
lovely job to you.
starts with a number N (0 < N <= 1000) -- the total number of balloons
distributed. The next N lines contain one color each. The color of a balloon is
a string of up to 15 lower-case letters.
A test case with N = 0
terminates the input and this test case is not to be processed.
popular problem on a single line. It is guaranteed that there is a unique
solution for each test case.
#include<iostream>
#include<cstdio>
#include<map>
#include<string>
#include<cstring>
using namespace std; void solve()
{
int T, max, t;
map<string, int> color_count;
string color;
while(cin>>T && T) {
max = ;
while(T--) {
cin>>color;
++color_count[color];
}
map<string, int>::const_iterator ii, it;
it = color_count.begin();
while(it != color_count.end()) {
if(max < it->second) {
max = it->second;
ii = it;
}
it++;
}
cout<<ii->first<<endl;
color_count.clear();
}
} int main()
{
solve();
return ;
}
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