A. Is it rated?
time limit per test 

2 seconds

memory limit per test 

256 megabytes

Is it rated?

Here it is. The Ultimate Question of Competitive Programming, Codeforces, and Everything. And you are here to answer it.

Another Codeforces round has been conducted. No two participants have the same number of points. For each participant, from the top to the bottom of the standings, their rating before and after the round is known.

It's known that if at least one participant's rating has changed, then the round was rated for sure.

It's also known that if the round was rated and a participant with lower rating took a better place in the standings than a participant with higher rating, then at least one round participant's rating has changed.

In this problem, you should not make any other assumptions about the rating system.

Determine if the current round is rated, unrated, or it's impossible to determine whether it is rated of not.

Input

The first line contains a single integer n (2 ≤ n ≤ 1000) — the number of round participants.

Each of the next n lines contains two integers ai and bi (1 ≤ ai, bi ≤ 4126) — the rating of the i-th participant before and after the round, respectively. The participants are listed in order from the top to the bottom of the standings.

Output

If the round is rated for sure, print "rated". If the round is unrated for sure, print "unrated". If it's impossible to determine whether the round is rated or not, print "maybe".

input
6
3060 3060
2194 2194
2876 2903
2624 2624
3007 2991
2884 2884
output
rated
input
4
1500 1500
1300 1300
1200 1200
1400 1400
output
unrated
input
5
3123 3123
2777 2777
2246 2246
2246 2246
1699 1699
output
maybe
Note

In the first example, the ratings of the participants in the third and fifth places have changed, therefore, the round was rated.

In the second example, no one's rating has changed, but the participant in the second place has lower rating than the participant in the fourth place. Therefore, if the round was rated, someone's rating would've changed for sure.

In the third example, no one's rating has changed, and the participants took places in non-increasing order of their rating. Therefore, it's impossible to determine whether the round is rated or not.

题目大意: 首先输入一个n表示参赛人数,然后给出n个人参赛前的分数和参赛后

      的分数,要求判断比赛完之后是否rate;

解题思路:首先判断赛前和赛后的分数是否相同,不同的话一定rate,

     否则判断是否按降序排列,是maybe否unrate。

AC代码:

 #include <stdio.h>
#include <string.h>
#include <math.h>
#include <stdlib.h>
#include <algorithm> using namespace std; struct Rating
{
int s;
int e;
}p[]; int main ()
{
int n,i;
int sum,s,j,flag;
while (~scanf("%d",&n))
{
flag = ;
for (i = ; i < n; i ++)
scanf("%d %d",&p[i].s,&p[i].e);
for (i = ; i < n; i ++) // 首先判断分数是否有变化
if (p[i].s != p[i].e)
{
flag = ; break;
}
if (flag)
{
printf("rated\n"); continue;
}
j = s = ;
for (i = ; i < n; i ++) // 然后判断是否是降序
{
if (p[i].s <= p[i-].s)
j ++;
}
if (j == n)
printf("maybe\n");
else
printf("unrated\n");
}
return ;
}

Codeforces Round #412 A Is it rated ?的更多相关文章

  1. Codeforces Round #412 (rated, Div. 2, base on VK Cup 2017 Round 3)(A.B.C,3道暴力题,C可二分求解)

    A. Is it rated? time limit per test:2 seconds memory limit per test:256 megabytes input:standard inp ...

  2. Codeforces Round #412 (rated, Div. 2, base on VK Cup 2017 Round 3) A B C D 水 模拟 二分 贪心

    A. Is it rated? time limit per test 2 seconds memory limit per test 256 megabytes input standard inp ...

  3. Codeforces Round #412 (rated, Div. 2, base on VK Cup 2017 Round 3) D - Dynamic Problem Scoring

    地址:http://codeforces.com/contest/807/problem/D 题目: D. Dynamic Problem Scoring time limit per test 2 ...

  4. Codeforces Round#412 Div.2

    A. Is it rated? 题面 Is it rated? Here it is. The Ultimate Question of Competitive Programming, Codefo ...

  5. Codeforces Round #412 Div. 2 第一场翻水水

    大半夜呆在机房做题,我只感觉智商严重下降,今天我脑子可能不太正常 A. Is it rated? time limit per test 2 seconds memory limit per test ...

  6. Codeforces Round #412 Div. 2 补题 D. Dynamic Problem Scoring

    D. Dynamic Problem Scoring time limit per test 2 seconds memory limit per test 256 megabytes input s ...

  7. Codeforces Round #412 (rated, Div. 2, base on VK Cup 2017 Round 3) A Is it rated?

    地址:http://codeforces.com/contest/807/problem/C 题目: C. Success Rate time limit per test 2 seconds mem ...

  8. Codeforces Round #412 (rated, Div. 2, base on VK Cup 2017 Round 3) E. Prairie Partition 二分+贪心

    E. Prairie Partition It can be shown that any positive integer x can be uniquely represented as x =  ...

  9. Codeforces Round #412 B. T-Shirt Hunt

    B. T-Shirt Hunt time limit per test 2 seconds memory limit per test 256 megabytes input standard inp ...

随机推荐

  1. Selenium三种等待元素的方式及代码,需要特别注意implicitlyWait的用法

    一.显式等待 1.显式等待: 就是明确的要等到某个元素的出现或者是某个元素的可点击等条件,等不到,就一直等,除非在规定的时间之内都没找到,那么就跳出Exception. 2.代码: new WebDr ...

  2. wx.config失败

    wx.config({ debug: false, appId: _appId, timestamp: _timestamp, nonceStr: _nonceStr, signature: _sig ...

  3. java中如何把图片转换成二进制流的代码

    在学习期间,把开发过程经常用到的一些代码段做个备份,下边代码内容是关于java中如何把图片转换成二进制流的代码,应该能对各朋友也有用处. public byte[] SetImageToByteArr ...

  4. 解决执行maven项目出现 SLF4J: Failed to load class “org.slf4j.impl.StaticLoggerBinder”. error

    最近再弄maven项目,运行起来没有问题,但是Console控制台会报错,比如说如下的问题异常提示: 由此我们可以看出,报出错误的地方主要是slf4j的jar包,而故障码中“Failed to loa ...

  5. db2 monitor event

    1.创建事件监控器至少需要哪些权限? DBADM authority SQLADM authority 2.事件监控器的种类有哪些? 3. db2 flush event monitor eventm ...

  6. JAVA学习5:用Maven创建第一个web项目(2)servlet演示

    上一章用Maven新建了web项目成功后,本文演示在此基础上应用servlet. 1.首先修改pom.xml文件,添加servlet依赖   <project xmlns="http: ...

  7. Mongodb利用aggregation实现抽样查询(按记录数和时间)

    之前对mongodb不熟,但是项目要用,因为数据量比较大,并且领导要实现抽样查询,控制数据流量,所以自己研究了下,亲测可用,分享一下! 话不多说,上代码: 第一种方案:加自增主键,实现按记录数抽样 1 ...

  8. Python数据类型(字符串)

    文章内容参考了教程:http://www.runoob.com/python/python-basic-syntax.html#commentform Python 字符串 字符串是 Python 中 ...

  9. 【随笔】MIME类型

    在openResty作为Web服务器的情况下访问根目录的首页时,出现了这样一个问题: nginx端的配置: worker_processes 2; error_log logs/error.log; ...

  10. jQuery插件的开发(一)

    jQuery插件的开发包括两种: 一种是类级别的插件开发,即给jQuery添加新的全局函数,相当于给jQuery类本身添加方法.jQuery的全局函数就是属于jQuery命名空间的函数,另一种是对象级 ...