python基础操作---list

 #coding:utf-8
 list1 = ['physics', 'chemistry', 1997, 2000];
 list2 = [1, 2, 3, 4, 5 ];
 list3 = ["a", "b", "c", "d"];

 #切片功能跟str一样
 print "list1[0]: ", list1[0]
 print "list2[1:5]: ", list2[1:5]
 print list1[::-1]
 list3.append("e")# 追加
 print list3

 del list1[2];
 print list1;

 list4 = list2 + list3

 print list4

 print 3 in list2

 for item in list2:
 print item

 #等价
 # for i in range(len(list2)):
 # print list2[i]

 # list_2d = [[0 for col in range(cols)] for row in range(rows)]
 list_2d = [ [0 for i in range(5)] for i in range(4)] #2维数据, 0为初始化数值

 print list_2d
 list_2d[0][1]=1
 print list_2d

输出----------------------------------------------------
list1[0]: physics
list2[1:5]: [2, 3, 4, 5]
[2000, 1997, 'chemistry', 'physics']
['a', 'b', 'c', 'd', 'e']
['physics', 'chemistry', 2000]
[1, 2, 3, 4, 5, 'a', 'b', 'c', 'd', 'e']
True
1
2
3
4
5
[[0, 0, 0, 0, 0], [0, 0, 0, 0, 0], [0, 0, 0, 0, 0], [0, 0, 0, 0, 0]]
[[0, 1, 0, 0, 0], [0, 0, 0, 0, 0], [0, 0, 0, 0, 0], [0, 0, 0, 0, 0]]