actor binary tree lab4
forward 与 ! (tell) 的差异,举个例子:
Main(当前actor): topNode ! Insert(requester, id=1, ele = 2)
topNode: root ! Insert(requester, id=1, ele = 2)
对于root而言,Insert消息的来源是topNode
假如第二行替换为
topNode: root forward Insert(requester, id=1, ele = 2)
此时,对于root而言,Insert消息的来源是Main
从上面的例子可以看出,! 和 forward之间是有差别的,但是差别本身比较tricky,会增加理解的成本,所以传递消息时,把消息的actorRef作为参数传递会简单很多。
在lab4中,就需要考虑到!与forward的异同点
testcase 的 code
test("proper inserts and lookups") {
val topNode = system.actorOf(Props[BinaryTreeSet]) topNode ! Contains(testActor, id = , )
expectMsg(ContainsResult(, false)) topNode ! Insert(testActor, id = , )
topNode ! Contains(testActor, id = , ) expectMsg(OperationFinished())
expectMsg(ContainsResult(, true))
}
结合topNode,与root的处理逻辑
val normal: Receive = {
// 这个forward非常重要,不能写成 !,不然第一个testcase都不过去
case operation: Operation => root ! operation
case GC => {
//garbageCollecting需要先变,因为节点的复制可能会很久
val newRoot = createRoot
context.become(garbageCollecting(newRoot))
root ! CopyTo(newRoot) }
case _ => println("unknown operation")
}
// root 的处理逻辑
case Insert(requester, id, elem) =>
if(this.elem == elem) {
if(this.removed) this.removed = false
requester ! OperationFinished(id)
} else {
val child = if(this.elem > elem) Left else Right
if(subtrees contains child) subtrees(child) ! Insert(requester, id, elem)
else {
subtrees += child -> context.actorOf(props(elem, false))
requester ! OperationFinished(id)
}
}
在source code中,topNode收到消息后,把消息传递给root,root认为消息的来源是topNode。假如消息不绑定requester参数,那么通过sender获得actor是tiopNode,而不是main。我们在testcase中做assertion的话,肯定就是错的。
另外,上例中用到了testActor,它是implicit变量,用于处理发送到main中的消息。主要是测试方便。
一个debug了5个小时的bug
case msg: Operation =>
pendingQueue = pendingQueue.enqueue(msg)
pendingQueue.enqueue(msg) 并不能更新pendingQueue自己,必须重新赋值才行。
actor binary tree lab4的更多相关文章
- [数据结构]——二叉树(Binary Tree)、二叉搜索树(Binary Search Tree)及其衍生算法
二叉树(Binary Tree)是最简单的树形数据结构,然而却十分精妙.其衍生出各种算法,以致于占据了数据结构的半壁江山.STL中大名顶顶的关联容器--集合(set).映射(map)便是使用二叉树实现 ...
- Leetcode 笔记 110 - Balanced Binary Tree
题目链接:Balanced Binary Tree | LeetCode OJ Given a binary tree, determine if it is height-balanced. For ...
- Leetcode, construct binary tree from inorder and post order traversal
Sept. 13, 2015 Spent more than a few hours to work on the leetcode problem, and my favorite blogs ab ...
- [LeetCode] Find Leaves of Binary Tree 找二叉树的叶节点
Given a binary tree, find all leaves and then remove those leaves. Then repeat the previous steps un ...
- [LeetCode] Verify Preorder Serialization of a Binary Tree 验证二叉树的先序序列化
One way to serialize a binary tree is to use pre-oder traversal. When we encounter a non-null node, ...
- [LeetCode] Binary Tree Vertical Order Traversal 二叉树的竖直遍历
Given a binary tree, return the vertical order traversal of its nodes' values. (ie, from top to bott ...
- [LeetCode] Binary Tree Longest Consecutive Sequence 二叉树最长连续序列
Given a binary tree, find the length of the longest consecutive sequence path. The path refers to an ...
- [LeetCode] Serialize and Deserialize Binary Tree 二叉树的序列化和去序列化
Serialization is the process of converting a data structure or object into a sequence of bits so tha ...
- [LeetCode] Binary Tree Paths 二叉树路径
Given a binary tree, return all root-to-leaf paths. For example, given the following binary tree: 1 ...
随机推荐
- RavenDb学习(六)查询补充特性
.延迟加载 原来的查询方式如下: IEnumerable<User> users = session .Query<User>() .Where(x => x.Name ...
- mysql找到所有索引
SELECT a.TABLE_SCHEMA,a.TABLE_NAME,a.index_name,GROUP_CONCAT(column_name ORDER BY seq_in_index) AS ` ...
- shell将字符串分隔成数组
#!/bin/bash a="hello,world,nice,to,meet,you" #要将$a分割开,先存储旧的分隔符 OLD_IFS="$IFS" #设 ...
- windows 中 到底是用的哪个java.exe??? 删除了PATH变量的Java设置还是可以运行java.exe windows/system32
到底是用的哪个java.exe??? 删除了PATH变量的Java设置还是可以运行java.exe JavaWindowsCC++C# 当电脑里面有多个jdk或是jre时,在cmd里面到底是用的哪个 ...
- SpringBoot2 【关于:Table 'XXX.hibernate_sequence' doesn't exist】
将ID生成略组改成@GeneratedValue(strategy = GenerationType.IDENTITY).
- R matrix 转换为 dataframe
When I try converting a matrix to a data frame, it works for me: > x <- matrix(1:6,ncol=2,dimn ...
- PHP递归算法的简单实例
递归函数为自调用函数,在函数体内直接或直接自个调用自个,但需求设置自调用的条件,若满意条件,则调用函数自身,若不满意则停止本函数的自调用,然后把目前流程的主控权交回给上一层函数来履行,也许这么给我们解 ...
- ADB 设置远程调试
Version:0.9 StartHTML:-1 EndHTML:-1 StartFragment:00000099 EndFragment:00016657 相信很多人在android 开发调试的时 ...
- Linux 错误记录
1.libmysqlclient.so.18: cannot open shared object file: No such file or directory 解决办法: [root@linux- ...
- Spring JMS 官方文档学习
最后部分的XML懒得写了,因为个人更倾向于JavaConfig形式. 为知笔记版本见这里,带格式~ 做了一个小demo,放到码云上了,有兴趣的点我. 说明:需要先了解下JMS的基础知识. 1.介绍 S ...