Safecracker

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 13237    Accepted Submission(s): 6897

Problem Description
=== Op tech briefing, 2002/11/02 06:42 CST ===
"The
item is locked in a Klein safe behind a painting in the second-floor
library. Klein safes are extremely rare; most of them, along with Klein
and his factory, were destroyed in World War II. Fortunately old
Brumbaugh from research knew Klein's secrets and wrote them down before
he died. A Klein safe has two distinguishing features: a combination
lock that uses letters instead of numbers, and an engraved quotation on
the door. A Klein quotation always contains between five and twelve
distinct uppercase letters, usually at the beginning of sentences, and
mentions one or more numbers. Five of the uppercase letters form the
combination that opens the safe. By combining the digits from all the
numbers in the appropriate way you get a numeric target. (The details of
constructing the target number are classified.) To find the combination
you must select five letters v, w, x, y, and z that satisfy the
following equation, where each letter is replaced by its ordinal
position in the alphabet (A=1, B=2, ..., Z=26). The combination is then
vwxyz. If there is more than one solution then the combination is the
one that is lexicographically greatest, i.e., the one that would appear
last in a dictionary."
v - w^2 + x^3 - y^4 + z^5 = target
"For
example, given target 1 and letter set ABCDEFGHIJKL, one possible
solution is FIECB, since 6 - 9^2 + 5^3 - 3^4 + 2^5 = 1. There are
actually several solutions in this case, and the combination turns out
to be LKEBA. Klein thought it was safe to encode the combination within
the engraving, because it could take months of effort to try all the
possibilities even if you knew the secret. But of course computers
didn't exist then."
=== Op tech directive, computer division, 2002/11/02 12:30 CST ===
"Develop
a program to find Klein combinations in preparation for field
deployment. Use standard test methodology as per departmental
regulations. Input consists of one or more lines containing a positive
integer target less than twelve million, a space, then at least five and
at most twelve distinct uppercase letters. The last line will contain a
target of zero and the letters END; this signals the end of the input.
For each line output the Klein combination, break ties with
lexicographic order, or 'no solution' if there is no correct
combination. Use the exact format shown below."
 
Sample Input
1 ABCDEFGHIJKL
11700519 ZAYEXIWOVU
3072997 SOUGHT
1234567 THEQUICKFROG
0 END
Sample Output
LKEBA
YOXUZ
GHOST
no solution
 #include<iostream>
#include<cstdio>
#include<cmath>
#include<map>
#include<cstdlib>
#include<vector>
#include<set>
#include<queue>
#include<cstring>
#include<string.h>
#include<algorithm>
#define INF 0x3f3f3f3f
typedef long long ll;
typedef unsigned long long LL;
using namespace std;
const int N = 1e6+;
const ll mod = 1e9+;
char s[];
int a[];
int b[];
int visited[];
int n;
int flag=;
void DFS(int t){
if(flag==)return;
if(t==){
int sum1=b[]+b[]*b[]*b[]+b[]*b[]*b[]*b[]*b[];
int sum2=b[]*b[]+b[]*b[]*b[]*b[];
if(sum1-sum2==n){
flag=;
printf("%c%c%c%c%c\n",b[]-+'A',b[]-+'A',b[]-+'A',b[]-+'A',b[]-+'A');
return ;
}
return ;
}
for(int i=;i>=;i--){
if(visited[i]==)continue;
else if(visited[i]==&&a[i]==){
visited[i]=;
b[t]=i;
DFS(t+);
visited[i]=;
}
}
}
int main(){
while(scanf("%d %s",&n,s)!=EOF){
if(n==&&strcmp(s,"END")==)break;
int len=strlen(s);
flag=;
memset(a,,sizeof(a));
for(int i=;i<len;i++){
int tt=s[i]-'A'+;
a[tt]=;
}
memset(visited,,sizeof(visited));
DFS();
if(flag==)cout<<"no solution"<<endl; } }

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