转载自:https://www.reddit.com/r/swift/comments/2w19kp/how_do_you_send_a_through_nsmutableurlrequest/

how do you send a ? through NSMutableURLRequest without encoding the ? as %3F (self.swift)

submitted 1 year ago by xStory_Timex

I have a enum Router.swift that helps me use alamofire to interact with my API.

recently i changed the API and now when i send a URL request my code changes the "?" to "%3F" which i believe is "?" in url encoding.

here is the code Look at .ReadBrandProducts /products?brand_id=(id) when the id is 1 the request comes back as /products%3Fbrand_id=1

var path: String {
switch self {
case .AddReview(let id, _):
return "/products/\(id)/reviews"
case .ReadBrands:
return "/brands"
case .ReadBrandProducts(let id):
return "/products?brand_id=\(id)"
case .ReadProductData(let id):
return "/products/\(id)"
case .ReadReviews(let id):
return "/products/\(id)/reviews"
case .Favorite(let id):
return "/products/\(id)/favorite"
case .readFeed:
return "/activity"
}
} // MARK: URLRequestConvertible var URLRequest: NSURLRequest {
let URL = NSURL(string: Router.baseURLString)!
let mutableURLRequest = NSMutableURLRequest(URL: URL.URLByAppendingPathComponent(path))
mutableURLRequest.HTTPMethod = method.rawValue if let token = KeychainService.loadToken() {
mutableURLRequest.setValue("Bearer \(token)", forHTTPHeaderField: "Authorization")
}
 
 
 
 
sorted by:

best
 
 

[–]lyinstevemod 2 points 1 year ago

If you're using Alamofire, you should really be submitting URL encoded parameters as a dictionary instead, because Alamofire handles serialization. You're doing more work than you should.

 

[–]xStory_Timex[S] 1 point 1 year ago

I don't understand, can you explain more

 

[–]lyinstevemod 1 point 1 year ago

So right now you're adding URL parameters, right? And you're serializing them into a string yourself.

You also said you're using Alamofire. Alamofire will actually take those arguments in a Dictionary as a parameter to the request() function. You don't need to -- and shouldn't -- manually create those strings.

Specifically just

?brand_id=\(id)

Instead, pass the parameters into the Alamofire request() function.

Alamofire.request(
.GET,
"/products",
parameters: ["brand_id": id]
)
 
 
 
 
 
 
 
 
 
 
 
 
 

QuestionQuestion mark is HTML escaped in NSMutableURLRequest self.iOSProgramming

Submitted 4 months ago by fourth_throwaway

ok, so I have an API that I built using ruby on rails. Pagination works completely in both the website and the API. Here is the api: https://sheltered-shelf-7331.herokuapp.com/api/yaks?page=1

just change out "page=1" at the end for "page=2" or "3", etc, and you'll see it works.

the problem though is that the "?" is read by the URL request as "%3F". Here is how the url request is printed in the console in Xcode:

  URL: https://sheltered-shelf-7331.herokuapp.com/api/yaks%3F

So of course it has a response of html status code 404. How can I make the question mark not be converted to %3F in the URL? I'm using URLRequest Convertible. Here is my code:

static let baseURL = "https://sheltered-shelf-7331.herokuapp.com"
let result: (path: String, parameters: [String: AnyObject]?) = { switch self {
case GetMainFeed:
return ("/api/yaks?", nil)
case PostLogin(let username, let password):
return ("/api/sessions", ["username": username, "password": password])
case PostCreateUser(let username, let password):
print(username, password)
return ("/api/users", ["username": username, "password": password])
case PostSendYak(let description, let image):
sending = true
return ("/api/yaks", ["description": description, "image": image])
case GetMyYaks:
sending = true
return ("/api/my-yaks", nil)
}
}() let url = NSURL(string: Router.baseURL)
let URLRequest = NSMutableURLRequest(URL: (url?.URLByAppendingPathComponent(result.path))!)
let encoding = Alamofire.ParameterEncoding.JSON
print(URLRequest)
if sending == true {
let defaults = NSUserDefaults.standardUserDefaults()
if let token = defaults.objectForKey("auth_token") as? String {
print(token)
URLRequest.setValue(token, forHTTPHeaderField: "Authorization")
} }
URLRequest.addValue("application/json", forHTTPHeaderField: "Content-Type")
let (encodedRequest, _) = encoding.encode(URLRequest, parameters: result.parameters)
encodedRequest.HTTPMethod = method.rawValue
return encodedRequest
 
 
 
all 3 comments
sorted by:

best
 
 

[–]Power781 2 points 4 months ago

It's not how URL parameters work.
the endpoint is /api/yaks
page=x is a parameter of your call.
you just have to set the encoding to let encoding = Alamofire.ParameterEncoding.URL depending on if you have URL parameters or body parameters.
Example on how I did it :

    public var parametersEncoding: Alamofire.ParameterEncoding {
switch self.method {
case .GET :
return .URL
case .POST, .PUT:
return .JSON
default:
return .JSON
}
}
 
 
 
 

[–]AyyBodyFrizzesAlone 1 point 4 months ago

?page=1 is not a path component. It's a URI parameter. Just append it with stringByAppendingString.

 

[–]tonygoold 1 point 4 months ago

It's actually the query, not the parameter (which isn't used by HTTP), an important distinction if you're trying to get the query string from an NSURL. You're right about why it's encoding the question mark though.

%3f URL --> '?'拼接引发的问题的更多相关文章

  1. php 对url 操作类:url拼接、get获取页面、post获取页面(带传参)

    /* * @brief url封装类,将常用的url请求操作封装在一起 * */ class URL{ private $error; public function __construct(){ $ ...

  2. url拼接

    在做网页抓取的时候经常会遇到一个问题就是页面中的链接是相对链接,这个时候就需要对链接进行url拼接,才能得到绝对链接. url严格按照一定的格式构成,一般为如下5个字段: 详细可参考RFC:http: ...

  3. Python相对完美的URL拼接函数

    首先说下什么叫URL拼接,我们有这么一个HTML片段:   <a href="../../a.html">click me</a> 做为一只辛苦的爬虫,我们 ...

  4. url拼接参数格式

    在一些情况下,需要直接往url上拼接请求参数. http://www.yanggb.com?flag=1&type=normal&role=customer 通过上面的例子就可以看出, ...

  5. Ajax获取接口数据,url拼接参数跳转页面,js获取上一级页面参数给本页面

    1.Ajax获取接口数据 function demo(){ //假设请求参数 var requestBody = [{ "name":"zhang", &quo ...

  6. 字符串拼接引发的BUG

    译者按: bug虽小,却是个磨人的小妖精! 原文: Fixing a bug: when concatenated strings turn into numbers in JavaScript 译者 ...

  7. 接口测试get请求url拼接函数(python)

    get请求地址一般是 协议+域名+端口+路径+参数,除了协议和域名其他均可为空.  http(s)://domain:port/path?key1=value1&key2=value2& ...

  8. 相对URL拼接为绝对URL的过程

    URL有两种方式:绝对的和相对的. 绝对URL中包含有访问资源的所需的全部信息 举一个例子: <HTML> <HEAD><TITLE>Joe's Tools< ...

  9. 关于url拼接传参数和利用view的字典传参数时,模板获取数据的方式问题

    url = "{% url 'dashboard:internship-theme-stat' %}?teacher_name="+teacher_name+"& ...

随机推荐

  1. bug记录_document.defaultview.getcomputedstyle()

    页面中使用document.defaultview.getcomputedstyle()在火狐下取不到值. 原本方法现在$(document).ready()中,换到window.onload里就可以 ...

  2. 读取memo中某行内容

    方法1 可用以下代码读取Memo中指定行的内容: var   aLine:String; begin   aLine:=Memo1.Lines[2]; end; 在使用中,读取的行在Memo中需要保证 ...

  3. [ An Ac a Day ^_^ ] hdu 4565 数学推导+矩阵快速幂

    从今天开始就有各站网络赛了 今天是ccpc全国赛的网络赛 希望一切顺利 可以去一次吉大 希望还能去一次大连 题意: 很明确是让你求Sn=[a+sqrt(b)^n]%m 思路: 一开始以为是水题 暴力了 ...

  4. Java 内部类和匿名内部类

    1.内部类: /* 局部内部类: 在一个类 的方法内部定义另外一个类,那么另外一个类就称作为局部内部类. 局部内部类要注意的细节: 1. 如果局部 内部类访问了一个局部变量,那么该局部变量必须使用fi ...

  5. UI线程

    Application.Current.Dispatcher.Invoke(new Action(() =>))

  6. MBProgressHUD详解

    1,MBProgressHUD常用属性和用法Demo - (void)testMBProgressHUD { NSLog(@"test MBProgressHUD "); /* 要 ...

  7. id和instancetype的异同

    相同点: 都可以作为方法返回值类型 在initWithName:方法中是一样的,例如: - (id)initWithName:(NSString *)name; - (instancetype)ini ...

  8. 20_学生选课数据库SQL语句练习题

    一.            设有一数据库,包括四个表:学生表(Student).课程表(Course).成绩表(Score)以及教师信息表(Teacher).四个表的结构分别如表1-1的表(一)~表( ...

  9. .net dynamic动态加属性

    class Test : System.Dynamic.DynamicObject { public override bool TryGetMember(System.Dynamic.GetMemb ...

  10. ASP.NET之.NET FrameWork框架

    .NET FrameWork框架 是一套应用程序开发框架,主要目的提供一个开发模型. 主要的两个组件: 公共语言运行时(Common Language Runtime)(CLR): 提供内存管理.线 ...