python 切片获取list、tuple中的元素

#-*- coding:UTF-8 -*-
L=[]
n=6
r=[1,2,3,4,5,6]
for  i  in range(n):
    L.append(r[i])
 
print   L  # =>[1, 2, 3, 4, 5, 6]
#取所有
print  L[:]   # => [1, 2, 3, 4, 5, 6]
#取前三个
print L[0],L[1],L[2] # => 1 2 3
print  L[0:3]   # => [1, 2, 3]
 
#取第三个和第四个
print L[2:4] #= >[3, 4]
 
#取倒数第一个
print  L[-1:] # =>[6]
 
print  L[-4:-2]
 
#取前四个
print  L[:4]  # =>[1, 2, 3, 4]
 
#创建一个0-99的数列：
L=range(100)
#取前十个
print  L[:10]    # =>[0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
#后十个
print  L[-10:]   # =>  [90, 91, 92, 93, 94, 95, 96, 97, 98, 99]
 
#前10个，每两个取一个
print  L[:10:2]     # => [0, 2, 4, 6, 8]
 
#所有数，每5个取一个
print L[::5]
 
# ==>[0, 5, 10, 15, 20, 25, 30, 35, 40, 45, 50, 55, 60, 65, 70, 75, 80, 85, 90, 95]
 
#tuple也是一种list，唯一区别是tuple不可变，tuple也可以用切片操作,操作结果仍是tuple
 
print (0,1,2,3,4,5)[:3]   #  ==> (0, 1, 2)
 
#字符串'xxx'或Unicode字符串u'XXX'也可以看成一种list,每个元素就是一个字符，操作结果仍是字符串：
print  'abcdefg'[:3]    #  ==>>abc
 
print  'ABCDEFGHI'[::2]   #  ==>> ACEGI