python 生成螺旋矩阵

对于任意 m*n 矩阵，将 1~m*n 的数字按照螺旋规则在矩阵中排列。

如 m=3,n=3,期望结果为：

[
[ , ,  ],
[ , ,  ],
[ , ,  ]
]

以下代码支持方阵以及非方阵。

code:

# coding=utf-
import numpy
 
flag=
pos_x=
pos_y=
def inc(pos_x,pos_y,row,col):
    if(-<pos_x<row and -<pos_y<col):
        return True
    else:
        return False
def gen(row,col):
    global flag
    global pos_x
    global pos_y
    rowbox=[]
    for i in range(col):
        rowbox.append()
    data=[]
    for i in range(row):
        data.append(rowbox)
    x = numpy.array(data)
    for i in range(,row*col+):
        while():
            if(flag==):
                if(inc(pos_x,pos_y,row,col) and x[pos_x][pos_y]==):
                    x[pos_x][pos_y]=i
                    pos_y=pos_y+
                    break
                else:
                    pos_y=pos_y-
                    pos_x=pos_x+
                    flag=
            if(flag==):
                if(inc(pos_x,pos_y,row,col) and x[pos_x][pos_y]==):
                    x[pos_x][pos_y]=i
                    pos_x=pos_x+
                    break
                else:
                    pos_x=pos_x-
                    pos_y=pos_y-
                    flag=
            if(flag==):
                if(inc(pos_x,pos_y,row,col) and x[pos_x][pos_y]==):
                    x[pos_x][pos_y]=i
                    pos_y=pos_y-
                    break
                else:
                    pos_y=pos_y+
                    pos_x=pos_x-
                    flag=
            if(flag==):
                if(inc(pos_x,pos_y,row,col) and x[pos_x][pos_y]==):
                    x[pos_x][pos_y]=i
                    pos_x=pos_x-
                    break
                else:
                    pos_y=pos_y+
                    pos_x=pos_x+
                    flag=
    return x
 
# m*n Matrix
m=
n=
print(gen(m,n))

输出

[[           ]
 [      ]
 [       ]]