For a undirected graph with tree characteristics, we can choose any node as the root. The result graph is then a rooted tree. Among all possible rooted trees, those with minimum height are called minimum height trees (MHTs). Given such a graph, write a function to find all the MHTs and return a list of their root labels.

Format
The graph contains n nodes which are labeled from 0 to n - 1. You will be given the number n and a list of undirected edges (each edge is a pair of labels).

You can assume that no duplicate edges will appear in edges. Since all edges are undirected, [0, 1] is the same as [1, 0] and thus will not appear together in edges.

Example 1:

Given n = 4, edges = [[1, 0], [1, 2], [1, 3]]

        0
|
1
/ \
2 3

return [1]

Example 2:

Given n = 6, edges = [[0, 3], [1, 3], [2, 3], [4, 3], [5, 4]]

     0  1  2
\ | /
3
|
4
|
5

return [3, 4]

Hint:

Show Hint

  1. How many MHTs can a graph have at most?

Note:

(1) According to the definition of tree on Wikipedia: “a tree is an undirected graph in which any two vertices are connected by exactly one path. In other words, any connected graph without simple cycles is a tree.”

(2) The height of a rooted tree is the number of edges on the longest downward path between the root and a leaf.

public class Solution {

    /** return the height of tree if let s to be the root of the tree */
public static int bfs(ArrayList<ArrayList<Integer> > g, int s) { HashSet<Integer> upper = new HashSet<Integer> ();
HashSet<Integer> lower = new HashSet<Integer> ();
HashSet<Integer> vis = new HashSet<Integer> (); upper.add(s);
vis.add(s);
int lv = 1; while(!upper.isEmpty()) { for(int u: upper) {
ArrayList<Integer> adj = g.get(u);
for(int i=0; i<adj.size(); ++i) {
int adj_node = adj.get(i);
if(!vis.contains(adj_node)) {
lower.add(adj_node);
}
}
} if(!lower.isEmpty()) {
++lv;
} upper.clear();
for(int c: lower) {
vis.add(c);
upper.add(c);
}
lower.clear();
} return lv;
} public static ArrayList<Integer> topologicalSort(int n, int[][] edges, ArrayList<ArrayList<Integer> > g) { ArrayList<Integer> topo = new ArrayList<Integer> ();
int[] d = new int[n]; for(int i=0; i<edges.length; ++i) {
int u = edges[i][0], v = edges[i][1];
++d[u]; ++d[v];
} LinkedList<Integer> queue = new LinkedList<Integer> ();
for(int i=0; i<n; ++i) {
if(d[i] == 1) {
queue.addLast(i);
}
} while(!queue.isEmpty()) {
int top = queue.pollFirst();
topo.add(top); ArrayList<Integer> adj = g.get(top);
for(int next: adj) {
d[next]--;
if(d[next] == 1) {
queue.addLast(next);
}
}
} return topo;
} public List<Integer> findMinHeightTrees(int n, int[][] edges) { List<Integer> rs = new ArrayList<Integer> ();
if(n == 1) {
rs.add(0);
return rs;
} ArrayList<ArrayList<Integer> > g = new ArrayList<ArrayList<Integer> > ();
for(int i=0; i<n; ++i) {
ArrayList<Integer> row = new ArrayList<Integer> ();
g.add(row);
}
for(int i=0; i<edges.length; ++i) {
int u = edges[i][0];
int v = edges[i][1]; g.get(u).add(v);
g.get(v).add(u);
} HashMap<Integer, Integer> mapping = new HashMap<Integer, Integer> ();
ArrayList<Integer> topo = topologicalSort(n, edges, g); int idx = topo.get(topo.size()-1);
int min_lv = bfs(g, idx);
rs.add(idx); if(topo.size() >= 2) {
int indice = topo.get(topo.size()-2);
if(bfs(g, indice) == min_lv) {
rs.add(indice);
}
} return rs; }
}

leetcode@ [310] Minimum Height Trees的更多相关文章

  1. [LeetCode] 310. Minimum Height Trees 解题思路

    For a undirected graph with tree characteristics, we can choose any node as the root. The result gra ...

  2. [LeetCode] 310. Minimum Height Trees 最小高度树

    For a undirected graph with tree characteristics, we can choose any node as the root. The result gra ...

  3. 【LeetCode】310. Minimum Height Trees 解题报告(Python)

    作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 BFS 相似题目 参考资料 日期 题目地址:http ...

  4. 310. Minimum Height Trees

    For a undirected graph with tree characteristics, we can choose any node as the root. The result gra ...

  5. [LeetCode] 310. Minimum Height Trees_Medium tag: BFS

    For a undirected graph with tree characteristics, we can choose any node as the root. The result gra ...

  6. 310. Minimum Height Trees -- 找出无向图中以哪些节点为根,树的深度最小

    For a undirected graph with tree characteristics, we can choose any node as the root. The result gra ...

  7. [LeetCode] Minimum Height Trees 最小高度树

    For a undirected graph with tree characteristics, we can choose any node as the root. The result gra ...

  8. LeetCode Minimum Height Trees

    原题链接在这里:https://leetcode.com/problems/minimum-height-trees/ 题目: For a undirected graph with tree cha ...

  9. Minimum Height Trees -- LeetCode

    For a undirected graph with tree characteristics, we can choose any node as the root. The result gra ...

随机推荐

  1. 37. Sudoku Solver

    题目: Write a program to solve a Sudoku puzzle by filling the empty cells. Empty cells are indicated b ...

  2. JNI读取assets资源文件

    源自:http://www.rosoo.net/a/201112/15459.html assets目录底下的文件会被打包到一个apk文件里,这些资源在安装时他们并没被解压,使用时是直接从apk中读取 ...

  3. 【转载】R6034错误,C Runtime Error

    能查到的解决方法都在里面有提及: 我是使用 stdafx.h加入这句 code #pragma comment(linker, "\"/manifestdependency:typ ...

  4. 【POJ】1084 Square Destroyer

    1. 题目描述由$n \times n, n \in [1, 5]$的正方形由$2 \times n \times (n+1)$根木棍组成,可能已经有些木棍被破坏,求至少还需破坏多少木根,可以使得不存 ...

  5. android的ScaleGestureDetector缩放类详解

    文章由多出组合,它们来自: http://elvajxw.iteye.com/blog/1308452 http://www.cnblogs.com/lknlfy/archive/2012/03/11 ...

  6. ASCII码常用值

    大写字母 A~Z 65~90 小写字母a~z 97~122 数字0~9 48~ 57

  7. bzoj2482

    还是像以前那样维护下次出现位置,计算影响 其实不难,思维盲点,受到做最大子段和的影响 其实这里可以直接维护当前每个位置的子段和,再记录一个历史最大和 当然tag也需要记录当前tag和历史(距离上次pu ...

  8. UVa 253 Cube paiting

    题意:输入两个骰子,判断是否等价 因为每一个面可以作顶面,共6*4种情况,枚举就可以了 #include<iostream> #include<cstdio> #include ...

  9. javascript倒计时代码

    其实就是用两个时间戳相减,余数转换为日期,就是所剩的年月日时分秒,不过年份-1970 $scope.timerID = null; $scope.timerRunning = false;$scope ...

  10. macro names must be identifiers

    1.错把 #include 写成了 #define 会报这个错 2.定义一个不存在的宏业会报这个错,如加了-DANDRO 而ANDRO不存在