Python基础（递归函数）

def age(n):
    if n == 1:
        return 18
    else:
        return age(n - 1) + 2
 
ret=age(100)
print(ret)#216
 
def test(num):
    print(num)
    if num > 0:
        test(num-1)
    else:
        print('------')
        print(num)
test(2)#依次打印出2 1 0 ------ 0

备注：图片转载自http://www.cnblogs.com/Fantinai/p/7806356.html