利用gmpy2破解rsa

gmpy2的相关文档：

https://gmpy2.readthedocs.io/en/latest/

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题目：

来自实验吧的rsarsa：http://www.shiyanbar.com/ctf/1979

题目内容：

p =
q =
e =
c =  

Use RSA to find the secret message

求明文

Python代码：

import gmpy2

p = gmpy2.mpz(9648423029010515676590551740010426534945737639235739800643989352039852507298491399561035009163427050370107570733633350911691280297777160200625281665378483)
q = gmpy2.mpz(11874843837980297032092405848653656852760910154543380907650040190704283358909208578251063047732443992230647903887510065547947313543299303261986053486569407)
e = gmpy2.mpz(65537)
phi_n = (p - 1) * (q - 1)
d = gmpy2.invert(e, phi_n)
print ("private key:")
print (d)

c = gmpy2.mpz(83208298995174604174773590298203639360540024871256126892889661345742403314929861939100492666605647316646576486526217457006376842280869728581726746401583705899941768214138742259689334840735633553053887641847651173776251820293087212885670180367406807406765923638973161375817392737747832762751690104423869019034)
print ("plaintext:")
print (pow(c,d,p*q))