思路:

dp。

实现:

 class Solution
{
public:
int splitArray(vector<int>& nums, int m)
{
int n = nums.size();
vector<int> sum(n + , );
for (int i = ; i <= n; i++) sum[i] = sum[i - ] + nums[i - ];
vector<vector<int>> dp(n + , vector<int>(m + , INT_MAX));
for (int i = ; i <= n; i++) dp[i][] = sum[i];
for (int i = ; i <= n; i++)
{
for (int j = ; j <= min(m, i); j++)
{
for (int k = ; k < i; k++)
{
int tmp = sum[i] - sum[k];
dp[i][j] = min(dp[i][j], max(tmp, dp[k][j - ]));
}
}
}
return dp[n][m];
}
};

leetcode410 Split Array Largest Sum的更多相关文章

  1. [Swift]LeetCode410. 分割数组的最大值 | Split Array Largest Sum

    Given an array which consists of non-negative integers and an integer m, you can split the array int ...

  2. [LeetCode] Split Array Largest Sum 分割数组的最大值

    Given an array which consists of non-negative integers and an integer m, you can split the array int ...

  3. Split Array Largest Sum

    Given an array which consists of non-negative integers and an integer m, you can split the array int ...

  4. Leetcode: Split Array Largest Sum

    Given an array which consists of non-negative integers and an integer m, you can split the array int ...

  5. 动态规划——Split Array Largest Sum

    题意大概就是,给定一个包含非负整数的序列nums以及一个整数m,要求把序列nums分成m份,并且要让这m个子序列各自的和的最大值最小(minimize the largest sum among th ...

  6. Split Array Largest Sum LT410

    Given an array which consists of non-negative integers and an integer m, you can split the array int ...

  7. 410. Split Array Largest Sum 把数组划分为m组,怎样使最大和最小

    [抄题]: Given an array which consists of non-negative integers and an integer m, you can split the arr ...

  8. [LeetCode] 410. Split Array Largest Sum 分割数组的最大值

    Given an array which consists of non-negative integers and an integer m, you can split the array int ...

  9. 【leetcode】410. Split Array Largest Sum

    题目如下: Given an array which consists of non-negative integers and an integer m, you can split the arr ...

随机推荐

  1. (linux)wake_lock机制

      Android的休眠唤醒主要基于wake_lock机制,只要系统中存在任一有效的wake_lock,系统就不能进入深度休眠,但可以进行设备的浅度休眠操作.wake_lock一般在关闭lcd.tp但 ...

  2. bzoj3137: [Baltic2013]tracks

    炸一看好像很神仙的样子,其实就是个sb题 万年不见的1A 但是我们可以反过来想,先选一个起点到终点的联通块,然后这联通块后面相当于就能够走了,继续找联通块 然后就能发现直接相邻的脚步相同的边权为0,否 ...

  3. 在canvas标签和style中定义width和height

    在canvas标签中定义width.height跟在style中定义width.height是不同的.canvas标签的width和height是画布实际宽度和高度,就是在这个上面绘制图形.style ...

  4. SPOJ:Ada and Graft (set合并&优化)

    As you might already know, Ada the Ladybug is a farmer. She grows a big fruit tree (with root in 0). ...

  5. 虚拟机bridged, NAT and host-only网络区别

    In Linux, a network of each type is created when running vmware-config.pl. In Windows, they are auto ...

  6. this调用属性

    示例: class Person{ private String name; private int age; public Person(String name,int age){ this.nam ...

  7. spark运行原理

    一.Spark专业术语定义 二. Spark的任务提交机制 一.Spark专业术语定义 从以下十五个方面描述spark概念. 1  application: spark应用程序 2  Driver:驱 ...

  8. J20170422-hm

    ワイルドスクリプト wild script 通配符 シェルスクリプト     shell脚本

  9. IT兄弟连 JavaWeb教程 URI、URL

    URI介绍 URI(Uniform Resource Identifier),是统一资源标识符的缩写,是一个用于标识某一个Web资源名称的字符串,该标识允许用户对任何资源通过特定的协议进行交互.Web ...

  10. USACO Training 3.3 商店购物 By cellur925

    题目传送门 这道题有着浓浓的背包气氛.所以我们可以这样想:可以把每个优惠方案都当做一个物品,每个单买所需要花的钱也当做一个物品.(也就是代码中的p结构体数组)而且基于此题的环境,这题是一个完全背包.另 ...