HDU 2672 god is a girl (字符串处理，找规律，简单)

题目

//1,1,2,3,5,8,13,21,34,55……

//斐波纳契数列

#include<math.h>
#include<stdio.h>
#include<string.h>
#include<algorithm>
using namespace std;

int main()
{
    char str[];
    int len,i,a,b,c;
    while(gets(str))
    {
        len = strlen(str);
        a=;
        b=c=;
        for(i=;i<len;i++)
        {
            if(str[i] >= 'A' && str[i] <= 'Z')
            {
                int ii = (str[i] - 'A' + c) %  ;
                printf("%c",ii + 'A');
                c=(a+b)%;
                a=b;
                b=c;
            }
            else
            {
                printf("%c",str[i]);
            }
        }
        puts("");

    }
    return ;

}