HDU 1000 & HDU1001 & 字符串连接

A + B Problem

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 571020    Accepted Submission(s):
181151

Problem Description

Calculate A + B.

 

Input

Each line will contain two integers A and
B. Process to end of file.

 

Output

For each case, output A + B in one
line.

 

Sample Input

1 1

 

Sample Output

2

#include <iostream>
#include <cstdio>
 
using namespace std;
 
int main()
{
    int a=,b=;
    while(scanf("%d %d",&a,&b)!=EOF){
        printf("%d\n",a+b);
    }
    return ;
}

Sum Problem

Time Limit: 1000/500 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 410639    Accepted Submission(s):
103262

Problem Description

Hey, welcome to HDOJ(Hangzhou Dianzi University Online
Judge).

In this problem, your task is to calculate SUM(n) = 1 + 2 + 3 +
... + n.

 

Input

The input will consist of a series of integers n, one
integer per line.

 

Output

For each case, output SUM(n) in one line, followed by a
blank line. You may assume the result will be in the range of 32-bit signed
integer.

 

Sample Input

1
100

 

Sample Output

1

5050

#include <iostream>
#include <cstdio>
using namespace std;
 
int main()
{
    int t;
    int sum=;
    while(scanf("%d",&t)!=EOF){
        for(int i=;i<=t;i++){
            sum+=i;
        }
        printf("%d\n\n",sum);
        sum=;
    }
    return ;
}

字符串连接：

#include <iostream>
#include <cstdio>
 
using namespace std;
 
int main()
{
    char a[]="i love";
    char b[]="you!";
    char c[];
    sprintf(c,"%s %s",a,b);
    printf("%s",c);
    return ;
}