【BZOJ 1296】 [SCOI2009]粉刷匠

【链接】 我是链接,点我呀:)

【题意】

在这里输入题意

【题解】

f[i][j][k]表示第i行前j列刷了k次，最大满意度
f[][j][k]=max{f[i][l][k],f[i][l][k-1]+max{zero(l+1,j),one(l+1,j)} }

g[i][j]表示前i行刷了j次的最大满意度。

g[i][j]=max{g[i-1][j-k] + f[i][m][k]}

取max{g[n][0..t]}就好

【代码】

#include <bits/stdc++.h>
#define LL long long
#define rep1(i,a,b) for (int i = a;i <= b;i++)
#define rep2(i,a,b) for (int i = a;i >= b;i--)
#define all(x) x.begin(),x.end()
#define pb push_back
#define lson l,mid,rt<<1
#define rson mid+1,r,rt<<1|1
using namespace std;
const double pi = acos(-1);
const int dx[4] = {0,0,1,-1};
const int dy[4] = {1,-1,0,0};
const int N = 50;
int f[N+10][N+10][N+10],a[N+10][N+10],n,m,t,b[N+10][N+10][2],g[N+10][N*N+10];
char s[N+10][N+10];
int main(){
	#ifdef LOCAL_DEFINE
	    freopen("rush_in.txt", "r", stdin);
	#endif
	ios::sync_with_stdio(0),cin.tie(0);
    cin >> n >> m >> t;
    rep1(i,1,n)
        cin >> (s[i]+1);
    rep1(i,1,n)
        rep1(j,1,m){
            a[i][j] = s[i][j]-'0';
            for (int k = 0;k <= 1;k++) b[i][j][k] = b[i][j-1][k];
            b[i][j][a[i][j]]++;
        }
    rep1(i,1,n)
        rep1(j,1,m)
            rep1(k,0,j){
                rep1(l,0,j-1){
                    f[i][j][k] = max(f[i][j][k],f[i][l][k]);
                    if (k>0) f[i][j][k] = max(f[i][j][k],f[i][l][k-1]+ max(b[i][j][0]-b[i][l][0],b[i][j][1]-b[i][l][1]));
                }
            }
    rep1(i,1,n)
        rep1(j,0,N*N)
            rep1(k,0,N)
                if (j-k>=0)
                    g[i][j] = max(g[i][j],g[i-1][j-k]+f[i][m][k]);
                    else break;
    int ans = 0;
    rep1(i,0,t) ans = max(ans,g[n][i]);
    cout<<ans<<endl;
	return 0;
}