URL to load resources from the classpath in Java
In Java, you can load all kinds of resources using the same API but with different URL protocols:
file:///tmp.txt
http://127.0.0.1:8080/a.properties
jar:http://www.foo.com/bar/baz.jar!/COM/foo/Quux.class
This nicely decouples the actual loading of the resource from the application that needs the resource, and since a URL is just a String, resource loading is also very easily configurable.
Is there a protocol to load resources using the current classloader? This is similar to the Jar protocol, except that I do not need to know which jar file or class folder the resource is coming from.
I can do that using Class.getResourceAsStream("a.xml")
, of course, but that would require me to use a different API, and hence changes to existing code. I want to be able to use this in all places where I can specify a URL for the resource already, by just updating a property file.
Intro and basic Implementation
First up, you're going to need at least a URLStreamHandler. This will actually open the connection to a given URL. Notice that this is simply called Handler
; this allows you to specify java -Djava.protocol.handler.pkgs=org.my.protocols
and it will automatically be picked up, using the "simple" package name as the supported protocol (in this case "classpath").
Usage
new URL("classpath:org/my/package/resource.extension").openConnection();
Code
package org.my.protocols.classpath;
import java.io.IOException;
import java.net.URL;
import java.net.URLConnection;
import java.net.URLStreamHandler;
/** A {@link URLStreamHandler} that handles resources on the classpath. */
public class Handler extends URLStreamHandler {
/** The classloader to find resources from. */
private final ClassLoader classLoader;
public Handler() {
this.classLoader = getClass().getClassLoader();
}
public Handler(ClassLoader classLoader) {
this.classLoader = classLoader;
}
@Override
protected URLConnection openConnection(URL u) throws IOException {
final URL resourceUrl = classLoader.getResource(u.getPath());
return resourceUrl.openConnection();
}
}
Launch issues
If you're anything like me, you don't want to rely on a property being set in the launch to get you somewhere (in my case, I like to keep my options open like Java WebStart - which is why I need all this).
Workarounds/Enhancements
Manual code Handler specification
If you control the code, you can do
new URL(null, "classpath:some/package/resource.extension", new org.my.protocols.classpath.Handler(ClassLoader.getSystemClassLoader()))
and this will use your handler to open the connection.
But again, this is less than satisfactory, as you don't need a URL to do this - you want to do this because some lib you can't (or don't want to) control wants urls...
JVM Handler registration
The ultimate option is to register a URLStreamHandlerFactory
that will handle all urls across the jvm:
package my.org.url;
import java.net.URLStreamHandler;
import java.net.URLStreamHandlerFactory;
import java.util.HashMap;
import java.util.Map;
class ConfigurableStreamHandlerFactory implements URLStreamHandlerFactory {
private final Map<String, URLStreamHandler> protocolHandlers;
public ConfigurableStreamHandlerFactory(String protocol, URLStreamHandler urlHandler) {
protocolHandlers = new HashMap<String, URLStreamHandler>();
addHandler(protocol, urlHandler);
}
public void addHandler(String protocol, URLStreamHandler urlHandler) {
protocolHandlers.put(protocol, urlHandler);
}
public URLStreamHandler createURLStreamHandler(String protocol) {
return protocolHandlers.get(protocol);
}
}
To register the handler, call URL.setURLStreamHandlerFactory()
with your configured factory. Then do new URL("classpath:org/my/package/resource.extension")
like the first example and away you go.
JVM Handler Registration Issue
Note that this method may only be called once per JVM, and note well that Tomcat will use this method to register a JNDI handler (AFAIK). Try Jetty (I will be); at worst, you can use the method first and then it has to work around you!
License
I release this to the public domain, and ask that if you wish to modify that you start a OSS project somewhere and comment here with the details. A better implementation would be to have a URLStreamHandlerFactory
that uses ThreadLocal
s to store URLStreamHandler
s for each Thread.currentThread().getContextClassLoader()
. I'll even give you my modifications and test classes.
URL to load resources from the classpath in Java的更多相关文章
- Load resources from classpath in Java--reference
In general classpath is the path where JVM can find .class files and resources of your application a ...
- The SSL certificate used to load resources from xxx will be distrusted in M70.
今天在浏览网站的时候遇到如下报警信息: The SSL certificate used to load resources from https://xxx.com will be distrust ...
- Java 实例 - 如何执行指定class文件目录(classpath) Java 实例 J
Java 实例 - 如何执行指定class文件目录(classpath) Java 实例 如果我们 Java 编译后的class文件不在当前目录,我们可以使用 -classpath 来指定class ...
- 环境变量/path/classpath/JAVA_HOME/JAVA环境变量配置
环境变量 环境变量是在操作系统中一个具有特定名字的对象,它包含了一个或者多个应用程序所将使用到的信息.例如Windows和DOS操作系统中的path环境变量,当要求系统运行一个程序而没有告诉它程序所在 ...
- path 与classpath针对JAVA来说
Path 路径,是java编译时需要调用的程序(如java,javac等)所在的地方CLASSPATH 类的路径,在编译运行java程序时,如果有调用到其他类的时候,在classpath中寻找需要的类 ...
- 使用任意的输入流(InputStream)实例,包括字符串形式的文件路径或者 file:// 的 URL 形式的文件路径来配置
mybatis – MyBatis 3 | 入门 http://www.mybatis.org/mybatis-3/zh/getting-started.html 从 XML 中构建 SqlSessi ...
- How to load a local .CSS file & JavaScript resources using iPhone UIWebView Class
This post will cover the basic setup and creation of an application with web content for iPhone that ...
- springboot-项目获取resources下文件碰到的问题(classPath下找不到文件和文件名乱码)
项目是spring-boot + spring-cloud 并使用maven 管理依赖.在springboot+maven项目下怎么读取resources下的文件实现文件下载? 怎么获取resourc ...
- 一个编译可执行jar包 jar包中不包含resources下config.properties且可以读到config.properties文件且classpath中有当前路径的pom
<project xmlns="http://maven.apache.org/POM/4.0.0" xmlns:xsi="http://www.w3.org/20 ...
随机推荐
- 【selenium2】【selenium基础语法】
#栗子 设置浏览器窗口大小 driver.set_window_size(480,800) #栗子 设置浏览器大小为最大maximize_window() 控制浏览器前进.后退 #栗子from sel ...
- Codeforces 629 E. Famil Door and Roads
题目链接:http://codeforces.com/problemset/problem/629/E 询问这个简单环的期望.考虑将这个环拆成两部分. 令${deep[x]>=deep[y]}$ ...
- 【UOJ】#273. 【清华集训2016】你的生命已如风中残烛
题目链接:http://uoj.ac/problem/273 $${Ans=\frac{\prod _{i=1}^{m}i}{w-n+1}}$$ #include<iostream> #i ...
- base64 加密原理 解密原理
假设需要加密的字符串是Jasmine 具体转换步骤: 第一步 将待转换的字符串转为一个个字符第二步 计算每一个字符对应的ASCII码十进制第三步 计算出十进制对应的二进制,若不足8位,在前面添加0进行 ...
- Mysql一些常用语句
1.查询表创建的时间: SELECT CREATE_TIME FROM INFORMATION_SCHEMA.TABLES WHERETABLE_NAME='TableName'
- php 中 public private protected的区别
public 子类,外部都可调用. protected 子类可以调用,外部不可以调用. private 子类不可以调用,外部不可以调用. <?php class AA { public func ...
- fiddler学习笔记&&基本使用
周末在网上找了些fiddler相关的资料来看,学习下如何使用这个工具(平时接口测试用得比较多,在没有接口文档的情况下,可以通过抓包工具来提取需要测试的接口,ps.好久没写博客了,争取5月结束前再写2篇 ...
- (转)C#连接OleDBConnection数据库的操作
对于不同的.net数据提供者,ADO.NET采用不同的Connection对象连接数据库.这些Connection对我们屏蔽了具体的实现细节,并提供了一种统一的实现方法. Connection类有四种 ...
- GRCh38基因组和注释文件探究
ensembl/release91: cat Homo_sapiens.GRCh38.91.gtf | grep -v "#" | cut -f9 | cut -f1,3,6,8 ...
- English trip V1 - B 1. How much is it? 它是多少钱? Teacher:Corrine Key: is/are
In this lesson you will learn to ask about prices. 本节课你将学习询问关于价格 课上内容(Lesson) one piece of two p ...