xtu summer individual 5 F - Post Office
Post Office
This problem will be judged on PKU. Original ID: 1160
64-bit integer IO format: %lld Java class name: Main
Post offices will be built in some, but not necessarily all of the villages. A village and the post office in it have the same position. For building the post offices, their positions should be chosen so that the total sum of all distances between each village and its nearest post office is minimum.
You are to write a program which, given the positions of the villages and the number of post offices, computes the least possible sum of all distances between each village and its nearest post office.
Input
Output
Sample Input
10 5
1 2 3 6 7 9 11 22 44 50
Sample Output
9
Source
#include <iostream>
#include <cstdio>
#include <cstring>
#include <cstdlib>
#include <vector>
#include <climits>
#include <algorithm>
#include <cmath>
#define LL long long
#define INF 0x3f3f3f3f
using namespace std;
int dp[][],x[],n,m;
int dis(int i,int j){
int sum = ;
while(i < j) sum += x[j--]-x[i++];
return sum;
}
int main(){
int i,j,k;
while(~scanf("%d%d",&m,&n)){
memset(dp,,sizeof(dp));
for(i = ; i <= m; i++){
scanf("%d",x+i);
dp[][i] = dis(,i);
}
for(i = ; i <= n; i++){
for(j = i; j <= m; j++){
dp[i][j] = INF;
for(k = i-; k < j; k++)
dp[i][j] = min(dp[i][j],dp[i-][k]+dis(k+,j));
}
}
cout<<dp[n][m]<<endl;
}
return ;
}
#include <iostream>
#include <cstring>
#include <cstdio>
using namespace std;
const int INF = 0x3f3f3f3f;
const int maxn = ;
int w[maxn][maxn],dp[maxn][maxn],a[maxn],n,m;
int main() {
while(~scanf("%d%d",&n,&m)) {
for(int i = ; i <= n; ++i) scanf("%d",a + i);
memset(w,,sizeof w);
for(int i = ; i <= n; ++i) {
for(int j = i + ; j <= n; ++j)
w[i][j] = w[i][j-] + a[j] - a[(i+j)>>];
}
for(int i = ; i <= n; ++i) {
dp[i][i] = ;
dp[i][] = w[][i];
}
for(int j = ; j <= m; ++j) {
for(int i = j + ; i <= n; ++i) {
dp[i][j] = INF;
for(int k = j-; k < i; ++k)
dp[i][j] = min(dp[i][j],dp[k][j-] + w[k+][i]);
}
}
printf("%d\n",dp[n][m]);
}
return ;
}
还是太年轻,蓝桥杯决赛有题就是这个,当时做的时候,没有理解这题的精髓,太傻了
平行四边形优化
#include <iostream>
#include <cstring>
#include <cstdio>
using namespace std;
const int INF = 0x3f3f3f3f;
const int maxn = ;
int w[maxn][maxn],dp[maxn][maxn],a[maxn],s[maxn][maxn],n,m;
int main() {
while(~scanf("%d%d",&n,&m)) {
for(int i = ; i <= n; ++i) scanf("%d",a + i);
memset(w,,sizeof w);
for(int i = ; i <= n; ++i) {
for(int j = i + ; j <= n; ++j)
w[i][j] = w[i][j-] + a[j] - a[(i+j)>>];
}
for(int i = ; i <= n; ++i) {
dp[i][i] = ;
dp[i][] = w[][i];
s[i][] = ;
}
for(int j = ; j <= m; ++j) {
s[n+][j] = n;
for(int i = n; i > j; --i) {
dp[i][j] = INF;
for(int k = s[i][j-]; k <= s[i+][j]; ++k){
int tmp = dp[k][j-] + w[k+][i];
if(tmp < dp[i][j]){
dp[i][j] = tmp;
s[i][j] = k;
}
}
}
}
printf("%d\n",dp[n][m]);
}
return ;
}
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