2014 HDU多校弟九场I题 不会DP也能水出来的简单DP题

听了ZWK大大的思路，就立马1A了

思路是这样的：

算最小GPA的时候，首先每个科目分配到69分（不足的话直接输出GPA 2），然后FOR循环下来使REMAIN POINT减少，每个科目的上限加到100即可

算最大GPA的时候，首先每个科目分配到60分,然后FOR循环下来使REMAIN POINT减少，每个科目的上限加到85即可，如果还有REMAIN POINT，就FOR循环下来加到100上限即可

不会DP 阿 QAQ

过段时间得好好看DP了  =  =

于是默默的把这题标记为《水题集》

    //#pragma comment(linker, "/STACK:16777216") //for c++ Compiler
    #include <stdio.h>
    #include <iostream>
    #include <cstring>
    #include <cmath>
    #include <stack>
    #include <queue>
    #include <vector>
    #include <algorithm>
    #define ll long long
    #define Max(a,b) (((a) > (b)) ? (a) : (b))
    #define Min(a,b) (((a) < (b)) ? (a) : (b))
    #define Abs(x) (((x) > 0) ? (x) : (-(x)))

    #define NN 200011

    using namespace std;

    const ll INF = 0x3f3f3f3f;
    const ll MAXN = ;

    int main(){
        int i, j, n, m, k;
        int numCase;
        int score, sum;
        int a[];
        scanf("%d",&numCase);
        while(numCase--){
            double Gmax = 0.0;
            double Gmin = 0.0;
            scanf("%d%d",&score,&n);
            sum = score * n;

            if(score < )  Gmax = ;
            else{
                for(i = ; i <= n; ++i){
                    a[i] = ;
                }
                int remain = sum - n * ;
                while(remain != ){
                    for(i = ; i <= n; ++i){
                        if(a[i] <= ){
                            int delta =  - a[i];
                            if(remain > delta){
                                a[i] += delta;
                                remain -= delta;
                            } else{
                                a[i] += remain;
                                remain = ;
                                break;
                            }

                        }
                    }
                    for(i = ; i <= n; ++i){
                        if(a[i] <= ){
                            int delta =  - a[i];
                            if(remain > delta){
                                a[i] += delta;
                                remain -= delta;
                            } else{
                                a[i] += remain;
                                remain = ;
                                break;
                            }

                        }
                    }
                }
                for(i = ; i <= n; ++i){
                    if(a[i] >= )  Gmax += 4.0;
                    else if(a[i] >= ) Gmax += 3.5;
                    else if(a[i] >= ) Gmax += 3.0;
                    else if(a[i] >= ) Gmax += 2.5;
                    else if(a[i] >= ) Gmax += 2.0;
                }
                Gmax /= n;
            }

            if(score < )  Gmin = ;
            else{
                for(i = ; i <= n; ++i){
                    a[i] = ;
                }
                int remain = sum - n * ;
                while(remain != ){
                    for(i = ; i <= n; ++i){
                        if(a[i] <= ){
                            int delta =  - a[i];
                            if(remain > delta){
                                a[i] += delta;
                                remain -= delta;
                            } else{
                                a[i] += remain;
                                remain = ;
                                break;
                            }

                        }
                    }
                }
                for(i = ; i <= n; ++i){
                    if(a[i] >= )  Gmin += 4.0;
                    else if(a[i] >= ) Gmin += 3.5;
                    else if(a[i] >= ) Gmin += 3.0;
                    else if(a[i] >= ) Gmin += 2.5;
                    else if(a[i] >= ) Gmin += 2.0;
                }
                Gmin /= n;
            }
            printf("%.4f %.4f\n",Gmin,Gmax);
        }
        return ;
    }