题目:

Given a sorted integer array without duplicates, return the summary of its ranges.

For example, given [0,1,2,4,5,7], return ["0->2","4->5","7"].

代码:

class Solution {
public:
vector<string> summaryRanges(vector<int>& nums) {
vector<string> vecStr;
if(nums.size() == )
{
vecStr.push_back(to_string(nums[]));
return vecStr;
}
for(int i = ; i < nums.size(); ++i)
{
int a = nums[i];
while( i+ < nums.size() && (nums[i+] - nums[i]) == )
{
++i;
}
if(a != nums[i])
{
vecStr.push_back(to_string(a) + "->" + to_string(nums[i]));
}
else if(a == nums[i])
vecStr.push_back(to_string(a));
}
return vecStr;
}
};

[LeetCode228]Summary Ranges的更多相关文章

  1. Leetcode228. Summary Ranges汇总区间

    给定一个无重复元素的有序整数数组,返回数组区间范围的汇总. 示例 1: 输入: [0,1,2,4,5,7] 输出: ["0->2","4->5",& ...

  2. leetcode-【中等题】228. Summary Ranges

    题目: 228. Summary Ranges Given a sorted integer array without duplicates, return the summary of its r ...

  3. Missing Ranges & Summary Ranges

    Missing Ranges Given a sorted integer array where the range of elements are [lower, upper] inclusive ...

  4. leetcode面试准备:Summary Ranges

    1 题目 Given a sorted integer array without duplicates, return the summary of its ranges. For example, ...

  5. 【LeetCode】228. Summary Ranges 解题报告(Python)

    [LeetCode]228. Summary Ranges 解题报告(Python) 标签(空格分隔): LeetCode 题目地址:https://leetcode.com/problems/sum ...

  6. 【刷题-LeetCode】228. Summary Ranges

    Summary Ranges Given a sorted integer array without duplicates, return the summary of its ranges. Ex ...

  7. [Swift]LeetCode228. 汇总区间 | Summary Ranges

    Given a sorted integer array without duplicates, return the summary of its ranges. Example 1: Input: ...

  8. [LeetCode] Summary Ranges 总结区间

    Given a sorted integer array without duplicates, return the summary of its ranges. For example, give ...

  9. Java for LeetCode 228 Summary Ranges

    Given a sorted integer array without duplicates, return the summary of its ranges. For example, give ...

随机推荐

  1. C语言文件操作之fgets()

        来说一说fgets(..)函数.     原型  char *  fgets(char * s, int n,FILE *stream);     參数:          s: 字符型指针, ...

  2. iOS 单元測试之XCTest具体解释(一)

    原创blog,转载请注明出处 blog.csdn.net/hello_hwc 欢迎关注我的iOS-SDK具体解释专栏 http://blog.csdn.net/column/details/huang ...

  3. hdu5119(dp)

    题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=5119 分析:dp[i][j]表示由前i个数组成异或和为j的方法数,则dp[i][j]=d[i-1][j ...

  4. Beijing Perl Workshop - Augest 10th, 2013

    Beijing Perl Workshop - Augest 10th, 2013 Beijing Perl Workshop

  5. ARM裸编程系列---UART

    S5PV210 UART说明 通用异步收发器缩写UART,这是UNIVERSAL ASYNCHRONOUS RECEIVER AND TRANSMITTER.它被用来传送串行数据.当发送数据,CPU将 ...

  6. 什么样的企业造什么样的软件最easy成功?

    事件1: 一般软件企业按功能分,大体分业务应用型软件和系统工具型软件. 按市场分,应用型软件企业较多,直接贴近生活:系统工具类较少,间接贴近大众较少. 事件2: 软件企业中,当中中小型企业老板存在非常 ...

  7. pcie inbound、outbound及EP、RC间的互相訪问

    Inbound:PCI域訪问存储器域 Outbound:存储器域訪问PCI域 RC訪问EP: RC存储器域->outbound->RC PCI域->EP PCI域->inbou ...

  8. OSGI学习总结

    最近的一项研究了解了一下OSGI技术,感觉OSGI尽管有一定的学习难度.可是终于掌握和推广之后将是一项对系统开发比較实用的技术.在此和大家分享一下自己的感悟. 1.什么是OSGI OSGI直译为&qu ...

  9. Windows Phone开发(2):竖立自信,初试锋茫

    原文:Windows Phone开发(2):竖立自信,初试锋茫 上一篇文章中,我们聊了一些"大炮"话题,从这篇文章开始,我们一起来学习WP开发吧. 一.我们有哪些装备. 安装完VS ...

  10. Vector Clock理解

    背景近期在重读"Dynamo: Amazon's Highly Available Key-value Store"(经典好文,推荐!).文章4.4 中聊到了Data Versio ...