Codeforces Round #384 (Div. 2) 734E Vladik and cards
2 seconds
256 megabytes
standard input
standard output
Vladik was bored on his way home and decided to play the following game. He took n cards and put them in a row in front of himself. Every card has a positive integer number not exceeding 8 written on it. He decided to find the longest subsequence of cards which satisfies the following conditions:
- the number of occurrences of each number from 1 to 8 in the subsequence doesn't differ by more then 1 from the number of occurrences of any other number. Formally, if there are ck cards with number k on them in the subsequence, than for all pairs of integers the condition |ci - cj| ≤ 1 must hold.
- if there is at least one card with number x on it in the subsequence, then all cards with number x in this subsequence must form a continuous segment in it (but not necessarily a continuous segment in the original sequence). For example, the subsequence [1, 1, 2, 2] satisfies this condition while the subsequence [1, 2, 2, 1] doesn't. Note that [1, 1, 2, 2] doesn't satisfy the first condition.
Please help Vladik to find the length of the longest subsequence that satisfies both conditions.
The first line contains single integer n (1 ≤ n ≤ 1000) — the number of cards in Vladik's sequence.
The second line contains the sequence of n positive integers not exceeding 8 — the description of Vladik's sequence.
Print single integer — the length of the longest subsequence of Vladik's sequence that satisfies both conditions.
3
1 1 1
1
8
8 7 6 5 4 3 2 1
8
24
1 8 1 2 8 2 3 8 3 4 8 4 5 8 5 6 8 6 7 8 7 8 8 8
17
In the first sample all the numbers written on the cards are equal, so you can't take more than one card, otherwise you'll violate the first condition.
题意
给定一个序列an,序列中只有1~8的8个整数,让你选出一个子序列,满足下列两个要求
1.不同整数出现的次数相差小于或等于1
2.子序列中整数分布是连续的,即子序列的整数必须是1,1,1....1,2,2,2.....2,2.......连续分布,可以是任意顺序而不要求递增,比如312587644
dp[i][j]记录在j状态下前i个中长度位l个个数 答案就是 ans*l+(8-ans)*(l-1)。
Codeforces Round #384 (Div. 2) 734E Vladik and cards的更多相关文章
- Codeforces Round #384 (Div. 2) E. Vladik and cards 状压dp
E. Vladik and cards 题目链接 http://codeforces.com/contest/743/problem/E 题面 Vladik was bored on his way ...
- Codeforces Round #384 (Div. 2) C. Vladik and fractions 构造题
C. Vladik and fractions 题目链接 http://codeforces.com/contest/743/problem/C 题面 Vladik and Chloe decided ...
- Codeforces Round #384 (Div. 2) A. Vladik and flights 水题
A. Vladik and flights 题目链接 http://codeforces.com/contest/743/problem/A 题面 Vladik is a competitive pr ...
- Codeforces Round #384 (Div. 2) C. Vladik and fractions(构造题)
传送门 Description Vladik and Chloe decided to determine who of them is better at math. Vladik claimed ...
- Codeforces Round #384 (Div. 2) 734E(二分答案+状态压缩DP)
题目大意 给定一个序列an,序列中只有1~8的8个整数,让你选出一个子序列,满足下列两个要求 1.不同整数出现的次数相差小于等于1 2.子序列中整数分布是连续的,即子序列的整数必须是1,1,1.... ...
- queue+模拟 Codeforces Round #304 (Div. 2) C. Soldier and Cards
题目传送门 /* 题意:两堆牌,每次拿出上面的牌做比较,大的一方收走两张牌,直到一方没有牌 queue容器:模拟上述过程,当次数达到最大值时判断为-1 */ #include <cstdio&g ...
- Codeforces Round #384 (Div. 2) //复习状压... 罚时爆炸 BOOM _DONE
不想欠题了..... 多打打CF才知道自己智商不足啊... A. Vladik and flights 给你一个01串 相同之间随便飞 没有费用 不同的飞需要费用为 abs i-j 真是题意杀啊, ...
- Codeforces Round #384 (Div. 2)D - Chloe and pleasant prizes 树形dp
D - Chloe and pleasant prizes 链接 http://codeforces.com/contest/743/problem/D 题面 Generous sponsors of ...
- Codeforces Round #384 (Div. 2)B. Chloe and the sequence 数学
B. Chloe and the sequence 题目链接 http://codeforces.com/contest/743/problem/B 题面 Chloe, the same as Vla ...
随机推荐
- MySQL主从同步
脚本 [root@test scripts]# cat ss.sh #!/bin/bash . /etc/init.d/functions MYUSER=root MYPASS=c565f972 SO ...
- Spring用代码来读取properties文件
我们都知道,Spring可以@Value的方式读取properties中的值,只需要在配置文件中配置org.springframework.beans.factory.config.PropertyP ...
- $.extend()、$.fn和$.fn.extend()
理解$.extend().$.fn和$.fn.extend() 原文链接:http://caibaojian.com/jquery-extend-and-jquery-fn-extend.ht ...
- 将做好的py文件打包成模块,供别人安装调用
现在要将写完的3个py文件,打包. 步骤: 1.新建一个文件夹setup(名字随便取),在setup文件夹下,再新建一个文件夹financeapi. 2.将上面4个py文件拷贝至financeapi文 ...
- 【.net+jquery】绘制自定义表单(含源码)
前言 两年前在力控的时候就想做一个类似的功能,当时思路大家都讨论好了,诸多原因最终还是夭折了.没想到两年多后再这有重新提出要写一个绘制表单的功能.对此也是有点小激动呢?总共用时8.5天的时间基本功能也 ...
- R3.2.2安装
- 数据结构与算法之链表-javascript实现
链表的定义: 链表是一种物理存储单元上非连续.非顺序的存储结构,数据元素的逻辑顺序是通过链表中的指针链接次序实现的.链表由一系列结点(链表中每一个元素称为结点)组成,结点可以在运行时动态生成.每个结点 ...
- kettle系列-6.kettle实现多字段字典快速翻译
在数据清洗转换中,常见的字典翻译,如性别在原表中是1(男).2(女)等,类似还有很多较大的字典需要翻译,若同一个表中有很多个字典需要翻译,采用[数据库查询]方式翻译的话效率就会相当低下. 这里采用ja ...
- Java研发岗位面试归类B(附答案)
本文承接上文:Java研发岗位面试归类A(附答案): http://www.cnblogs.com/wp5719/p/5870243.html 答案自己网上找的,如有纰漏或错误,烦请指教. 七.数据库 ...
- VS2015 编译 Qwt6.1.3
VS2015 + Qt5.7 编译 Qwt6.1.3 1. 将 qwtconfig.pri 中的 C:\Qwt 改为 D:/ProgramFiles/C_Library/Qwt/Qwt , 我的Qw ...