Java for LeetCode 101 Symmetric Tree
Given a binary tree, check whether it is a mirror of itself (ie, symmetric around its center).
For example, this binary tree is symmetric:
- 1
- / \
- 2 2
- / \ / \
- 3 4 4 3
But the following is not:
- 1
- / \
- 2 2
- \ \
- 3 3
解题思路:
重载一个isSymmetric判断两棵树是否对称即可,JAVA实现如下:
- public boolean isSymmetric(TreeNode root) {
- if(root==null)
- return true;
- return isSymmetric(root.left,root.right);
- }
- public boolean isSymmetric(TreeNode left,TreeNode right){
- if(left==null||right==null)
- return left==null&&right==null;
- if(left.val!=right.val)
- return false;
- return(isSymmetric(left.left,right.right)&&isSymmetric(left.right,right.left));
- }
Java for LeetCode 101 Symmetric Tree的更多相关文章
- [leetcode] 101. Symmetric Tree 对称树
题目大意 #!/usr/bin/env python # coding=utf-8 # Date: 2018-08-30 """ https://leetcode.com ...
- Leetcode 101 Symmetric Tree 二叉树
判断一棵树是否自对称 可以回忆我们做过的Leetcode 100 Same Tree 二叉树和Leetcode 226 Invert Binary Tree 二叉树 先可以将左子树进行Invert B ...
- leetcode 101 Symmetric Tree ----- java
Given a binary tree, check whether it is a mirror of itself (ie, symmetric around its center). For e ...
- Java [Leetcode 101]Symmetric Tree
题目描述: Given a binary tree, check whether it is a mirror of itself (ie, symmetric around its center). ...
- LeetCode 101. Symmetric Tree (对称树)
Given a binary tree, check whether it is a mirror of itself (ie, symmetric around its center). For e ...
- (二叉树 DFS 递归) leetcode 101. Symmetric Tree
Given a binary tree, check whether it is a mirror of itself (ie, symmetric around its center). For e ...
- LeetCode 101. Symmetric Tree
Given a binary tree, check whether it is a mirror of itself (ie, symmetric around its center). For e ...
- LeetCode 101. Symmetric Tree 判断对称树 C++
Given a binary tree, check whether it is a mirror of itself (ie, symmetric around its center). For e ...
- Leetcode 101. Symmetric Tree(easy)
Given a binary tree, check whether it is a mirror of itself (ie, symmetric around its center). For e ...
随机推荐
- 深入浅出 Cocoa 之 Core Data(4)- 使用绑定
深入浅出 Cocoa 之 Core Data(4)- 使用绑定 罗朝辉(http://blog.csdn.net/kesalin) CC 许可,转载请注明出处 前面讲解了 Core Data 的框架, ...
- selenium用法 (python)
滑动到指定元素位置 browser.find_element_by_xpath("//font[text()='资产管理部经办人'][1]").location_once_scro ...
- Libimseti推荐系统
技术:easyUI.jQuery.Spring.Struts.Hibernate.Mahout.MySQL 本Libimseti推荐系统使用数据.代码參考<Mahout in action> ...
- [C++设计模式] state 状态模式
<head first 设计模式>中的样例非常不错,想制造一个自己主动交易的糖果机,糖果机有四个状态:投入钱不足,投入钱足够,出售糖果,糖果售罄. 糖果机的当前状态处于当中不同的状态时,它 ...
- vuex 中关于 mapState 的作用
辅助函数 Vuex 除了提供我们 Store 对象外,还对外提供了一系列的辅助函数,方便我们在代码中使用 Vuex,提供了操作 store 的各种属性的一系列语法糖,下面我们来一起看一下: mapSt ...
- POJ 题目3264 Balanced Lineup(RMQ)
Balanced Lineup Time Limit: 5000MS Memory Limit: 65536K Total Submissions: 39046 Accepted: 18291 ...
- widget 常用UI控件介绍
一.单选框 单选框实例程序: <LinearLayout xmlns:android="http://schemas.android.com/apk/res/android&q ...
- jquery 判断元素显示或隐藏
$().is(":hidden"); $().is(":visible");
- Linux安装indicator-china-weather
https://launchpad.net/indicator-china-weather sudo apt-get update sudo apt-get install python-appind ...
- Linux内核中链表的学习
一.自己学习链表 数组的缺点:(1)数据类型一致:(2)数组的长度事先定好,不能灵活更改. 从而引入了链表来解决数组的这些缺点:(1)结构体解决多数据类型(2)链表的组合使得链表的长度可以灵活设置. ...